Week 1-Electrical Activity Flashcards

1
Q

far field

A

extra-cranial recordings
*cannot give full access to electrical activity, but sampling the response at various levels gives idea about integrity or sensitivity of the aud system

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2
Q

stations/addresses/sampling

A

fixed number of vertical lines at fixed time at equal intervals

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3
Q

analysis window

A

recording epoch or time ensemble

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4
Q

stimulus repetitions/epoch/ sweeps

A

number of epochs in the average AEP

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5
Q

time locked

A

electric signal concurrent with the onset of the electric response

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6
Q

digitizer triggers

A

when to start the digitization process/the capture of a signal at some specified moment in time (1ms, 5ms, etc)

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7
Q

digital computer

A
  • changes analog to discrete, uses binary numbers (aka bits)

- –uses base 2 if not binary?

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8
Q

three types of processing needed to find the evoked response in noise and EEG

A

1) differential amplification
2) filtering
3) averaging

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9
Q

what are the 2 steps to A-D conversion

A

1) quantization= chopping a continuous signal into amplitude units (steps)
2) sampling= chopping a continuous signal into a limited number of units (samples) of equal duration/time

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10
Q

what is the typical time window and number of samples in an ABR?

A

10ms time window and normally 256 sampling points?

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11
Q

what happens at each address for signal averaging

A

1) A-D conversion (digitization)
- –in each address, the analog EEG activity is digitized (+ or -) and then the value is stored at the address and then all the digital values are added algebraically at each address
2) D-A conversion
- –digital values converted to analog values meaning a continuous trace on an oscilloscope (the waveform is seen)

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12
Q

how does averaging affect noise?

A

reduction in the overall amplitude because random signals (noise) are cancelled out

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13
Q

2 things that the fidelity of A-D and D-A conversions depend on

A
  • amplitude resolution

* temporal resolution

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14
Q

amplitude resolution

A

quantization

  • set by binary word length of conversion
  • no problem with low frequency
  • problem with high freq= no digitization=high freq filtering
  • fine resolution= accurate reproduction of the EP
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15
Q

temporal resolution (of sweep)

A

is dwell time= separation between 2 successive addresses

  • set by rate of sampling
  • at least to points/cycle are sufficient resolution to reproduce the freq.
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16
Q

period (T)

A

the reciprocal of frequency (F)

*T=1/F

17
Q

nyquist freq

A

the highest freq that can be reproduced

–sampling rate should be at least 2x the highest frequency in the signal of interest