unit 8 vocab Flashcards
carboxylic acid
often found in substances derived from living organisms
alkaloids
organic bases found in plants; often poisonous
arrhenius acid
produces H+ in an aqueous solution
arrhenius base
produces OH- in an aqueous solution
bronstead-lowry acid
proton (H+ ion) donor; becomes a conjugate base
bronstead-lowry base
proton (H+ ion) receiver; becomes a conjugate acid
monoprotic acid
an acid that only contains one ionizable proton
diprotic acid
an acid containing two ionizable protons
acid ionization constant (Ka)
the equilibrium constant for the ionization of a weak acid; used to compare the relative strengths of weak acids
autoionization
when water acts as an acid and a base with itself
Kw
ion product constant for water; at 25 C, Kw = 1.0 * 10^-14
sig fig rule for log to pH
if the log has two sig figs, the pH has two decimal places
percent ionization
the ratio of the concentration of ionized acid to the initial concentration of that acid, times 100%
polyprotic acid
ionizes in steps, each step has its own Ka
binary acid
an acid with H and only one other element
oxyacid/oxoacid
an acid with H bonded to O and O is bonded with another element
adduct
the product of a lewis acid-base reaction
4 ways to make a buffer
- partial neutralization of weak acid and strong base
- partial neutralization of weak base and strong acid
- weak acid and salt of its conjugate base
- weak base and salt of its conjugate acid
when an acid is strong, its conjugate base is..
weak
adding a strong acid or base to a buffer (steps)
- initial mol
- mol of added
- add base to base n subtract base from acid or other way around
- find new concentration
- use henderson-hasselbalch equation to find pH
henderson-hasselbalch equation
pH = -log Ka + log [b]/[a]
when combining strong acid and strong base, at the equivalence point…
pH is 7
when combining strong acid and weak base, at the equivalence point…
pH is acidic
when combining strong base and weak acid, at the equivalence point…
pH is basic
titration with weak acid or base steps:
- which is strong, acid or base?
- find missing K
- find moles
- find L of missing substance
- y = mol/total L
- missing K = x^2/y-x
- find pH from there (-log it)
Ka =
x^2 over initial concentration
[OH-][H+] =
1 * 10^-14
LeChatlier’s principle
when an equilibrium is stressed, it’ll adjust to relieve the stress