Unit 6 - Stoichiometry & Chemical Formulas - Honors Addendum

Question 1

What is the Stoichiometric Rosetta Stone when answering Practice Problems?

Answer 1

1 mole = gfm = 6.022 x 10²³ Particles = 22.4L (g)

Question 2

When given the number of moles, how do you find molecular weight, number of molecules/atoms and volume?

Answer 2

Gram Formula Mass - Given Number of Moles x GFM of 1 Mole
Number of Molecules- Given Num. of Moles x 6.022 x 10²³ Particles
Number of Atoms - Given Num. Moles x 6.022 x 10²³ x Num. Atoms of MOL
Volume - Given Num. of Moles x 22.4 L (g)

Question 3

When given the number of particles, how do you find GFM, moles and volume?

Answer 3

Moles - GIven Num. of Particles/6.022 x 10²³
Gram Formula Mass - Moles x GFM of 1 Mole
Volume - Moles x 22.4 L

Question 4

When given the molecular weight, how do you find number of particles, moles and volume?

Answer 4

Moles - Given GFM/GFM of one Mole
Number of Particles - Num. of Moles x 6.022 x 10²³ Particles
Volume - Num. of Moles x 22.4 L (g)

Question 5

When given the volume, how do you find number of particles, moles and GFM?

Answer 5

Moles - Given Volume/22.4 L
Number of Particles - Num. of Moles x 6.022 x 10²³ Particles
Gram Formula Mass - Given GFM/GFM of one Mole

Question 6

What is a trend seen all the time when solving for moles, number of particles, gram formula mass and volume?

Answer 6

1. No matter what you are given at first,
2. Number of moles must be found first
3. To find all of the other values (GFM, Particles & Vol)