Unit 6 - Gene Expression and Regulation Flashcards

1
Q

function of nucleic acids

A
  • hereditary information
  • store and transmit genetic expression
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2
Q

structure of nucleic acids

A
  • double stranded
  • alpha helix
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3
Q

nucleotide composition

A
  • nitrogenous base
  • phosphate
  • pentase sugar
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4
Q

how do nucleotide monomers join together to form a polymer

A
  • complementary bases are bonded with hydrogen bonds
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5
Q

purines

A

A-G
- double rings

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6
Q

pyramidines

A

C-T
- single rings

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7
Q

how many hydrogen bonds between A-T

A

2 hydrogen bonds

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8
Q

how many hydrogen bonds between C-G

A

3 hydrogen bonds

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9
Q

what is meant by “DNA is antiparallel”

A

DNA runs in opposite directions

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10
Q

how are bases added to a DNA strand

A
  • bases are added 5’ -> 3’
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11
Q

building of nucleic acids: arrival with 3 P groups

A
  • nucleotides arrive with 3 phosphate groups
  • that nucleotide is energy
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12
Q

building of nucleic acids: DNA polymerase III

A
  • use the energy from breakin the 3-phosphate to bond nucleotides together
  • energy coupling
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13
Q

energy coupling

A
  • exergonic gives energy for endergonic reaction
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14
Q

when does DNA replicate

A

s-phase in mitosis

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15
Q

why does DNA replicate

A
  • growth
  • repair
  • reproduction
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16
Q

topoisomerase

A
  • loosens DNA, unwinds DNA
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17
Q

helicase

A
  • breaks hydrogen bonds between bases
  • “unzips DNA”
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18
Q

replication fork

A

dna helicase unzips here

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19
Q

DNA polymerase III

A
  • adds complementary bases on the new daughter strand

**cannot start strand

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20
Q

primase / rna primase

A
  • starts the replication process
  • adds rna primer
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21
Q

templet strand

A
  • original strand
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22
Q

leading strand

A
  • continuous replication at DNA
  • replicated in the direction of the replication fork
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23
Q

lagging strand

A
  • opposite the direction of the replication fork
  • replicated in fragments
  • okazaki fragments
  • DNA ligase binds these fragments together
  • forms phosphodiester bonds
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24
Q

DNA polymerase I

A
  • removes rna primers
  • adds the correct nucleotides in place of primers (only in lagging strand)
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25
Q

what about the first RNA primers on the leading strand?

A
  • they are removed and not replaced with nucleotides
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26
Q

telomeres

A
  • repeating sequences of DNA (TTAAGGG)
  • they get shorter everytime DNA replicates
  • as they get smaller, eventually it will enter apoptosis
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27
Q

dna polymerase??

A
  • add nucleotides
  • proof read/check
  • remove primers
  • add bases
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28
Q

shape of prokaryotic DNA

A

circular DNA

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29
Q

semi-conservative replication

A
  • the original parent strand is always going to be in at least one offspring
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30
Q

where does RNA processing occur?

A

in the nucleus

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31
Q

does RNA processing occur in prokaryotes and eukaryotes?

A

no, only eukaryotes
- prokaryotes do not have a nucleus

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32
Q

3 events in RNA processing

A
  1. modified guanine cap is added
  2. introns are removed and exons are spliced together
  3. poly a tail is added
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33
Q

RNA Processing: guanine cap

A
  • 3 phosphates added to it
  • function: attaches to the ribosome (for protection)
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34
Q

RNA Processing: introns and extrons

A
  • introns are removed and exons are spliced together
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35
Q

introns

A
  • noncoding regions of mRNA
  • “in the way”
  • these are removed using an SnRNP
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36
Q

exons

A
  • coding regions for amino acids
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37
Q

SnRNP

A
  • small nuclear RNA and proteins
  • cut out introns
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38
Q

spliceosomes

A
  • groups of SnRNPs
  • splice = cut out introns and attach exons
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39
Q

RNA Processing: poly A tail

A
  • poly A tail is added
  • 50 to 250 adenine bases are added to the 3’ end of mRNA
  • used for protection
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40
Q

alternate RNA splicing

A
  • we can use different combinations of exons to produce different proteins
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41
Q

mRNA

A

instructions to make proteins

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42
Q

ribosomes

A
  • reads mRNA 3 bases at a time (codon)
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43
Q

how many RNA bases call for an amino acid

A

3 RNA bases call for 1 amino acid

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44
Q

steps for translation

A
  • initiation
  • elongation
  • termination
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45
Q

anti codon

A
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46
Q

initiation

A
  • mRNA binds to ribosome (small ribosomal subunit)
  • ribosome calls for an amino acid
  • tRNA will bring amino acid, and bind with mRNA codon
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47
Q

elongation

A

-polypeptide is made, peptide bonds formed through dehydration synthesis

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48
Q

primary structure of a protein

A

polypeptide chain

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49
Q

termination

A
  • a stop codon is reached
  • polypeptide is released

** mutations

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50
Q

how many nitrogenous bases are in a polypeptide made from 219 amino acids

A

219 * 3 = 657

657 + 3 (stop codon) = 660 total bases

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51
Q

tRNA

A

transfer RNA that carries amino acids to the ribosome

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52
Q

prokaryotic translation

A
  • no nucleus; DNA gets transcribed and RNA gets translated at the same time
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53
Q

what is the source of heritable information found in cells?

A

DNA and (sometimes) RNA are the primary sources of heritable information

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54
Q

what are the characteristics of DNA and RNA that allow them both to be used as hereditary materials?

A
  • they store information as nitrogen base sequences
  • base pairing occurs with specific pyramidines always pairing with specific purines
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55
Q

what differences exist between the heritable information found in prokaryotes and eukaryotes

A
  • prokaryotes typically have circular chromosomes while eukaryotes have linear chromosomes
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56
Q

how is genetic information stored

A
  • stored as a sequence of bases in DNA and RNA
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57
Q

in what ways are DNA and RNA structurally similar

A
  • both are polymers containing nucleotides
  • both are chain like
  • both follow base pairing rules
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58
Q

pyramidines: rings

A

single ring structure

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59
Q

purines: rings

A

double ring structure

60
Q

what is the purpose of DNA replication

A
  • to ensure the continuity of hereditary information
  • allows transmission of genes from one gen to the next
61
Q

what does it mean for the replication process to be semiconservative

A
  • results in a DNA molecule containing one og strand and a newly synthesized compliment
62
Q

how does the directionality of a DNA molecule influence the replication process

63
Q

what are the specific enzymes involved in replication and what is the function of each?

A
  • helicase
  • topoisomerase
  • DNA Polymerase
  • ligase
64
Q

structure of DNA molecule in terms of phosphate and hydroxyl

A
  • each DNA strand has a terminal phosphate group on one end and a terminal hydroxyl group (OH) on the other end
65
Q

what is the phosphate terminus referred to as

66
Q

what is the hydroxyl terminus referred to as

67
Q

in what direction can nucleotides be added

A
  • nucleotides can only be added to a growing strand in a 5’-3’ direction
  • this means one strand will continously be made (leading strand)
68
Q

which strand will always be synthesized continuosly

A
  • leading strand
69
Q

which strand will always be synthesized discontinuously, in fragments

A
  • lagging strand
70
Q

helicase

A

unwinds DNA strand

71
Q

topoisomerase

A
  • relaxes the supercoil at the replication fork
72
Q

replication fork

A
  • the location where the two strands are separated
73
Q

DNA polymerase

A
  • synthesizes new strands
  • requires RNA primers to initiate synthesis
  • attaches to the 3’ end of the template strand
  • builds strands in the 5’-3’ direction
74
Q

ligase

A

joins DNA fragments on the lagging strand

75
Q

what is meant by the flow of genetic information

A
  • genetic information flows from DNA to RNA to protien
76
Q

what is transcription

A
  • the process in which RNA polymerase uses the noncoding strand of DNA as a template to produce an mRNA molecule
77
Q

RNA polymerase directionality

A
  • RNA polymerase synthesizes mRNA in the 5’-3’ direction while reading DNA in the 3’-5’ direction
78
Q

what are the diff types of RNA molecules and what is the function of each

A
  • mRNA
  • tRNA
  • rRNA
79
Q

mRNA

A
  • carries genetic information from DNA to the ribosomes
  • information is used to direct protein synthesis at the ribosomal site
  • codons are found on mRNA
80
Q

tRNA

A
  • recruited to the ribosomes to help create a specific polypeptide sequence as directed by mRNA
  • various tRNA molecules, each carrying a specific amino acid
  • anti codon
81
Q

anti-codon

A
  • a 3-base sequence on tRNA
  • correct base pairing of tRNA anti-codons with mRNA codons will result in the release and addition of an amino acid to a growing polypeptide
82
Q

rRNA

A
  • Ribosomal RNA
  • functional units of ribosomes responsible for protein assembly
83
Q

what are the mRNA transcript modifications that occur in eukaryotic cells

A
  • addition of a poly-A tail
  • addition of a GTP cap
  • introns and exons
84
Q

what is alternative splicing?

A
  • when introns are excised from a primary mRNA transcript and exons are retained and joined together
85
Q

how does alternative splicing result in different proteins

A
  • different combinations of exons can be retained in a mature mRNA transcript
  • diff exon combinations encode for different proteins
86
Q

what does addition of a poly-A tail do

A
  • 100-200 adenine nucleotides
  • increases stability
  • helps with exporting from nucleus
87
Q

what does the addition of GTP cap do

A
  • modified guanine nucleotide
  • protects the transcript
  • helps ribosome attach to mRNA
88
Q

introns

A
  • sequences of mRNA transcript that DO NOT CODE for amino acids
  • these are removed during RNA processing
  • not included in mature mRNA transcript
89
Q

what is translation

A
  • the process of generating polypeptides using the information carried on an mRNA molecule
89
Q

exons

A
  • sequences of mRNA transcript that code for amino acids
  • retained during RNA processing
  • different exons are connected in the mature mRNA transcript
90
Q

what are the main steps of the translation process

A

initiation, elongation, termination

91
Q

when does translation occur in prokaryotes

92
Q

protein synthesis objective

A
  • this is how we get the directions from DNA about how to make proteins and bring them to the ribosomes so that the ribosomes can join amino acids in a specific order to synthesize a protein
93
Q

what are phenotypes dependent on

A

they depend on presence or absence of particular proteins

94
Q

how do we get the directions from our genes into an actual protein

A

transcription and translation

95
Q

where does translation / transcription occur in prokaryotes

A

the cytoplasm at the same time

96
Q

miRNA

A
  • Micro RNA
  • promotion of genes
97
Q

transcription simply put is just

A
  • copying the code from DNA to RNA
98
Q

DNA is read in what direction

99
Q

coding strand

A
  • 5’-3’
  • codes for the proteins
100
Q

template strand

A
  • non coding strand
  • minus strand
  • antisense strand
  • DNA that is used for transcription (3’-5’)
101
Q

how does RNA polymerase know where to attach to begin transcription?

A

promoter region - RNA polymerase attaches and begins transcription

102
Q

how does the RNA polymerase know where the promoter is

103
Q

TATA box

A

a repeating sequence of TATA nucleotides

104
Q

how does RNA polymerase know where to stop

A

termination sequence

105
Q

transcription factors

A
  • proteins that grab RNA polymerase (this attaches to them) in order to start transcription
106
Q

transcription initiation complex

A
  • transcription factors, promoter, RNA polymerase - all bind to start transcription
107
Q

RNA Processing

A
  • results in mature mRNA
  • only happens in eukaryotes
108
Q

RNA Processing: 1

A
  • modified guanine cap is added for protection
109
Q

RNA Processing: 2

A
  • introns are removed and exons are spliced together
110
Q

what are mutations that could occur during termination in translation

111
Q

how is it possible to have over 200 different types of human cells if we all start from one cell

A
  • different genes are turned on and off (expressed)
112
Q

histones

A
  • proteins that DNA coils around
  • 8 Histones coiled up is a nucleosome
113
Q

what regulates gene expression in eukaryotes

A
  • transcription factors (proteins that help RNA polymerase bind to the promoter)
  • DNA coiling
114
Q

euchromatin

A
  • loosely/unwounded chromatin
  • able to do transcription or translation
115
Q

heterochromatin

A
  • densly packed chromatin
  • hidden
  • no transcription therefore no translation
116
Q

how do we modify the histone proteins and DNA

A
  • add acetyl groups to the histone proteins
  • relaxes the histone so that DNA is available for transcription
117
Q

what happens if you remove the acetyl group from histones

A
  • DNA ends up as heterochromatin
118
Q

what happens during histone acetylation in relation to transcription

A
  • if you acetylate the histone, gene transcription can be turned on
119
Q

deacetylation in relation to transcription

A
  • gene transcription is turned off
120
Q

what is DNA methylation

A
  • CH3
  • add a methyl to the actual DNA
  • brings you from euchromatin to heterochromatin
  • **turns off gene transcription
121
Q

how does DNA polymerase replicate DNA

A
  • DNA polymerase reads the template strand in the 3’-5’ direction and carries complementary base pairs to create a new strand
122
Q

how does DNA polymerase build the complimentary strand

A
  • DNA polymerase reads the parent strand from 3’-5’ then builds the complementary strand from 5’-3’
123
Q

role of the DNA polymerase

A
  • DNA polymerase proofreads and corrects errors with the help of nucleases
  • incorrect base pairs are removed, and correct ones inserted
124
Q

DNA Ligase

A

bonds the nucleotides and the okazaki fragments together

125
Q

helicase function

A

unwinds the parental double helix

126
Q

DNA Replication - leading strand

A
  • the DNA polymerase reads the parent strand from 3’-5’ and synthesizes continuosly in the leading strand in 5’-3’ direction, moving towards the replication fork
127
Q

telomeres

A
  • ends of eukaryotic DNA molecules
  • protects coding genes from being eroded during multiple rounds of DNA replication
128
Q

DNA replication vs Transcription + Translation

A
  • DNA replication occurs only when the cell is ready to divide
  • Translation and Transcription occur constantly to make proteins needed as the cell carries out metabolic activities
129
Q

where does transcription occur in eukaryotes

A

transcription of DNA to RNA occurs in the nucleus

130
Q

where does translation of RNA occur in eukaryotes

A

the cytoplasm

131
Q

transcription: promoter

A
  • TATA Box
  • the part of the DNA where RNA Polymerase binds to start transcription
  • noncoding DNA
132
Q

transcription: transcription factors

A
  • in eukaryotes
  • proteins that bind to the promoter region and ease the binding of RNA polymerase to the promoter
133
Q

why does the RNA get modified before it exits the nucleus into the cytoplasm?

A

purpose of 5’ cap and poly-A tail: prevent enzymatic degradation of the mRNA when it moves out of the nucleus into the cytoplasm

134
Q

purpose of RNA splicing

A

removes the introns so that only the exons will remain in the mRNA that goes out into the cytoplasm to be translated

135
Q

length of final mRNA vs. og mRNA

A

final mRNA is much shorter than the initial RNA transcript due to the removal of introns

136
Q

function of mRNA

A
  • carries the instruction for making a protein from a gene and delivers it to the site of translation (ribosome)
  • this mRNA is a complementary copy of a segment of DNA
137
Q

ribosomal RNA (rRNA) function

A
  • part of the structure of the ribosome
138
Q

mutations are caused by…

A
  • a change in the sequence of DNA nucleotides
  • error in DNA replication or as a result of environmental factors (mutagens)
139
Q

phenotypic plasticity

A
  • the ability of one genotype to produce several phenotypes when exposed to different environments
140
Q

what are the bonds between nucleotides

A

phosphodiester bonds formed by dehydration synthesis

141
Q

translation: initiation

A
  • mRNA binds to small ribosomal subunit
  • ribosome calles for tRNA to bring amino acid
  • tRNA will bring amino acid and bind with mRNA codon
142
Q

start codon is

143
Q

translation: elongation

A

building a polypeptide by forming peptide bonds

144
Q

explain why a normal polypeptide may have 100 amino acids whereas a mutated polypeptide may only have 10

A

there was a stop codon earlier in the sequence so the mutated polypeptide ended up shorter