Topic 12: Acid Base Equilibria Flashcards
1
Q
What are Bronsted-Lowry acids?
A
- acids are proton donors
- they release H+ ions when they’re mixed with water
- H+ ions are always combined with H2O to form hydroxonium ions, H3O+
2
Q
What is the reaction to form hydroxonium ions?
A
- HA(aq) + H2O(l) → H3O+(aq) + A-(aq)
3
Q
What are Bronsted-Lowry bases?
A
- bases are proton acceptors
- when they’re in solution, they take hydrogen ions from water molecules
- B(aq) + H2O(l) → BH+(aq) + OH-(aq)
4
Q
What are strong acids and strong bases?
A
- strong acids dissociate almost completely in water (nearly all the H+ ions will be released
- e.g. HCl is a strong acid
- strong bases dissociate almost completely too
- e.g. NaOH
5
Q
What are weak acids?
A
- weak acids dissociate only very slightly in water
- only small numbers of H+ ions are formed
- an equilibrium is set up, which lies well over to the left
- e.g. ethanoic acid
6
Q
What are weak bases?
A
- weak bases only slightly protonate in water
- equilibrium lies on the left
- e.g. ammonia
7
Q
What are conjugate pairs?
A
- conjugate pairs are species that are linked by the transfer of a proton
- the species that has lost a proton is the conjugate base
- the species that has gained a proton conjugate acid
8
Q
What the definition of the standard enthalpy change of neutralisation?
A
- the standard enthalpy change of neutralisation is the enthalpy change when the acid and alkali neutralise each other under standard conditions to form one mole of water
9
Q
How do you calculate pH?
A
- pH = -log10 [H+]
10
Q
How do you work out [H+]?
A
- 10-pH
11
Q
What is the H+ concentration of strong monoprotic acids?
A
- the H+ concentration is the same as the acid concentration
- they dissociate fully
- monoprotic: each mole of acid produces one mole of hydrogen ions
12
Q
How many protons are released per molecule of diprotic acid?
A
- two protons
13
Q
How do you find the pH of a weak acid?
A
- use Ka (the acid dissociation constant)
14
Q
What are the assumptions you have to make to find Ka?
A
- [HA(aq)](start) ≈ [HA(aq)](equilibrium)
- [H+(aq)] ≈ [A-(aq)]
15
Q
What is the ionic product of water?
A
- KW = [H+] [OH-]
- units are always mol2dm-6