TBL 7 Lipid Metabolism Flashcards

1
Q

B-oxidation of fatty acids occur in the _________ of the cell, and gives rise to form ______.

A

mitochondria; acetyl-CoA

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2
Q

(Saturated/unsaturated) fatty acids have a higher melting point. They are thus solids at room temperature.

A

Saturated

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3
Q

Fats are stored in the cytoplasm as _________ compounds.

A

triacylglycerol (TAG)

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4
Q

Fats are stored in ____ cells.

A

adipose (fat cells)

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5
Q

Bile salts are generated from ______ in the _____ and stored in the _______.

A

generated from cholesterol in the liver, stored in gallbladder

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6
Q

Bile salts _____ bulky fat globules in the intestine.

A

emulsifies

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7
Q

_______, also known as fatty stool, is a symptom due to the lack of bile salts which causes indigestion and malabsorption of fats into the blood, causing most of the fat to pass through the gut undigested.

A

Steatorrhoea

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8
Q

Bile salts have a hydrophobic and hydrophilic face and form ______ in aqueous environment to shield hydrophobic TAGs form the solution.

A

micelles

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9
Q

Bile salts increase the surface area of TAGs for ______ to bind and digest TAGs.

A

pancreatic lipase

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10
Q

Once the TAGs are incorporated into chylomicrons, these lipoproteins enter the ______ and are transported by the _____ and returned to the blood.

A

enter the lacteal and are transported by lymph

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11
Q

Orlistat inhibits _____, reducing fat absorption in the intestines and undigested fat is excreted through faeces.

A

gastric and pancreatic lipase

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12
Q

1st step of B-oxidation:

Fatty acid —> ________ by enzyme _______. This step utilises 2 high energy bonds of ATP, and occurs on the ____________.

A

Fatty acid is converted to acyl-CoA, by acyl-CoA synthetase.

Occurs on the outer mitochondrial membrane

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13
Q

2nd step of B-oxidation:

Acyl-CoA produced has to be transported from the outer mitochondrial membrane into the ____. This is done via the _______ shuttle.

A

Acyl-CoA has to be transported into the mitochondrial matrix. This is done via the carnitine shuttle.

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14
Q

How the carnitine shuttle works:
Acyl-CoA will be coupled with carnitine to form ________ by enzyme _____, and is moved to the matrix by a ______.

Acyl-carnitine is then converted back to carnitine by ____, transferring the acyl group to CoA to reform _______.

A

How the carnitine shuttle works:
Acyl-CoA will be coupled with carnitine to form Acyl-carnitine by enzyme CAT I, and is moved to the matrix by a translocase.
Acyl-carnitine is then converted back to carnitine by CAT II, transferring the acyl group to CoA to reform acyl-CoA.

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15
Q

3rd step of B-oxidation:

A) Acyl-CoA will first be ______ by enzyme _________.

Cofactor ____ is reduced in the process, forming ____.

A

A) Acyl-CoA will first be oxidised by enzyme acyl-CoA dehyodrogenase.

(H atoms are removed from alpha and beta C, forming C=C bond).

Cofactor FAD to FADH2.

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16
Q

3rd step of B-oxidation:

B) Intermediate then undergoes hydration by enzyme ________.

A

enzyme 3-hydroxyacyl CoA hydrolase

OH group added to beta C, H atom added to alpha C

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17
Q

3rd step of B-oxidation:

C) Intermediate then undergoes ________ by enzyme ________.

Cofactor ___ is reduced in the process, forming NADH.

A

Intermediate undergoes oxidation by enzyme 3-hydroxyacyl CoA dehydrogenase.
(removal of H atom at Beta C to form C=O group)

Cofactor NAD+

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18
Q

3rd step of B-oxidation:

D) Intermediate then undergoes ______ by enzyme __________, forming one molecule of acetyl-CoA and a shortened molecule of acyl-CoA.

The cycle repeats until the last cycle where 2 acetyl-CoA molecules are produced.

A

Intermediate then undergoes thiolysis by enzyme thiolase.

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19
Q

Palmitic acid (fatty acid) consists of ___C. It is used to produce pamitoyl-CoA, which undergoes __ cycles of B-oxidation to produce __ molecules of acetyl-CoA.

A

16 Carbons atoms

7 cycles of B-oxidation; 8 molecules of acetyl-CoA

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20
Q

For odd-numbered fatty acids, the last cycle of B-oxidation will result in the production of a 3C propionyl-CoA, which will be converted to ________ which can enter the Krebs’ cycle.

A

Succinyl-CoA (4C)

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21
Q

In the first step of B-oxidation where acyl-CoA is oxidised using enzyme acyl-CoA dehydrogenase, there are 5 different types of enzymes specific to the _____ of fatty acid chains.

A

length

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22
Q

Fact: Primary carnitine defiency is due to a loss-of-function mutation to the gene which encodes a carnitine transporter. This causes reduced ability to take up carnitine required for B-oxidation.

A

No answer needed :)

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23
Q

______ is the proccess of producing fatty acids from acetyl-CoA and malonyl-CoA via sequential decarboxylative condensation reactions.

A

Lipogenesis

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24
Q

The enzymes involved in lipogenesis are:
1)
2)

A

1) Acetyl-CoA carboxylase

2) Fatty acid synthase (FAS)

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25
Q

Fatty acid synthase (FAS) consists of 9 different domains and 7 different enzymes. These 7 different enzymes are:
A and B are involved in transferring ACP group onto acetyl-CoA and malonyl-CoA.
C is involved in the next step of condensation between acetyl-ACP and malonyl-ACP to form B-ketoacyl ACP.
D is involved in the following step of reduction to form 3-hydroxyacyl ACP.
E is involved in the following step of dehydration.
F is involved in the last step of reduction, to form a R group.

A

A and B: Acetyl-ACP transferase; Malonyl-ACP transferase;

C: B-ketoacyl synthase;

D: B-ketoacyl reductase;

E: 3-hydroxyacyl-ACP dehydrases 1 and 2 (dehydration);

F: Enol-ACP reductase

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26
Q

Desaturation of fatty acids (to form unsaturated fatty acids) involve the enzyme ___________.

A

Fatty acyl-CoA desaturases

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27
Q

Dietary cholesterol uptake in humans is limited to approximately ___g/day.

A

0.5

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28
Q

Cholesterol biosynthesis takes place in the (organ).

A

liver

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29
Q

Cholesterol biosynthesis takes place in three main steps:

1) Generation of ________ (a reduced 3x acetyl-CoA molecules)
2) Activation of melovanate to ________ (C5 precursor isoprene unit) which is then elongated to form ______ (C30).
3) Cyclisation and ________ of squalene to form cholesterol. (C27)

A

1) Generation of mevalonate (C6)
2) Activation of mevalonate to isopentenyl-PP (C5) which is then elongated to form squalene. (C30)
3) Cyclisation and demethylation of squalene to form cholesterol

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30
Q

In mevalonate synthesis, __ acetyl-CoA molecules come together to form ________, which is then reduced by _________ to form mevalonate.

A

3 acetyl-CoA molecules come together to form HMG-CoA (6C), which is then reduced by HMG-CoA reductase to form mevalonate.

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31
Q

Statins competitively binds to _______, and thus they are used to block the synthesis of mevalonate from acetyl-CoA, inhibiting cholesterol synthesis.

A

HMG-CoA reductase

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32
Q

HMG-CoA is under ______ feedback control by bile salts, cholesterol and mevalonate.

A

negative

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33
Q

Mevalonate (C6) then undergoes sequential ________ at the hydroxyl groups at positions 3 and 5 to form _________ (C6). This is then decarboxylated to form isopentenyl-PP (C5), which is isomerised to form ____________ (C5).

A

Mevalonate (C6) —> Mevalonate-3-phospho-5-pyrophosphate (C6) —> Isopentenyl-PP (C5) —-> 3,3-dimethyl PP (C5)

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34
Q

3,3-dimethyl PP (C5) then undergoes condensation with another unit of _________ to form _________ (C10).
Third isopentenyl-PP is added to form the intermediate __________ (C15), two of which condense to form squalene (C30) and two pyrophosphates.

A

3,3-dimethyl PP (C5) + Isopentenyl-PP (C5) —-> Geranyl PP (C10)

Geranyl-PP (C10) + Isopentenyl-PP (C5) —-> Farnesyl-PP (C15)

2x Farnesyl-PP (C15) —> Squalene (C30)

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35
Q

Condensation of 2 x Farnesyl-PP to squalene is driven by the reducing power of ______.

A

NADPH (cholesterol biosynthesis)

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36
Q

Squalene (C30) is cyclised to cholesterol by first being reduced by ___ and _____ to form squalene-2,3-epoxide.

A

O2 and NADPH

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37
Q

The enzyme _____________ catalyses the formation of lanosterol from squalene-2,3-epoxide.

A

Squalene epoxide lanosterol-cyclase

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38
Q

Lanosterol is then reduced, with the removal of ________ to form cholesterol.

A

3 methyl groups

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39
Q

The steroid precursor _________ is derived from cholesterol via the action of the enzyme _______.

A

Steroid precursor pregnenolene is derived from cholesterol via the action of desmolase.

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40
Q

__________ biosynthesis from cholesterol involves UV radiation, as it is required to initiate the reaction in epidermal keratinocytes.

A

Vitamin D

41
Q

______ is formed from Vitamin D3 and it plays a key role in calcium metabolism.
Therefore, vitamin D deficiency can cause _____ (in children) or osteomalacia in adults, leading to softened or weakened bones.

A

Calcitriol; cause Rickets in children

42
Q

Bile salts are derived from ______.

A

cholesterol

43
Q

Primary bile salts include ______ and ______.

A

glycocholate and taurocholate

44
Q

_________ are fluctuating assemblies of cholesterol and sphingomyelins in the plasma membrane, which helps to organise cell signalling by localising key proteins.

A

Lipid rafts

45
Q

Cholesterol is attached to the N-terminus of ________- proteins during its processing, limiting diffusion within tissues, which is essential for successful limb formation during embryogenesis.

A

Hedgehog-signalling protein

46
Q

_______ are composed of a phospholipid monolayer containing (un-/esterified) cholesterol and apoproteins.

A

Lipoproteins; unsterified cholesterol

47
Q

HDL transports cholesterol from the ________ to the ______. It is therefore known as the ‘good’ cholesterol, as it picks up excess cholesterol in the blood stream and lowers the total serum levels.

A

from peripheries to the liver

48
Q

LDL transport cholesterol from the ______ to the _______. It is therefore known as the ‘bad’ cholesterol, as it has the potential to clog up the arteries.

A

from the liver to the peripheries

49
Q

__________ is an enzyme found on capillary endothelial cells lining various tissues. It catalyses the hydrolysis of triacylglyceries (TAGs) to glycerol and fatty acids.

A

Lipoprotein lipase

50
Q

Familial hypercholesterolemia (FH) is a monogenic (dominant/recessive) trait in the LDL receptor gene.

A

dominant

51
Q

FH may cause superficial ________ in the body, arising from plasma LDL-derived cholesterol deposits in skin macrophages.

A

xanthomas

52
Q

Cholesterol in the form of LDL is taken up into cells via __________ by cell surface receptors.

A

receptor-mediated endocytosis

53
Q

The LDL receptor has five domains:

A
  1. Cytoplasmic domain
  2. O-linked carbohydrate
  3. Ligand-binding
  4. EGFP (pH dependent)
  5. Transmembrane (holds the recceptor in the plasma membrane)
54
Q

The _______ domain of the LDL receptor localises the receptors to clarithin-coated pits and triggers receptor-mediated endocytosis.

A

cytoplasmic

55
Q

Class __ LDLR mutation occurs when there is no synthesis of the LDLR. This might be caused by a ______ mutation, causing a non-functional protein.

A

Class I LDLR mutation

Might be caused by a deletion/frameshift mutation/mutation in the promoter region

56
Q

Class ___ LDLR mutation occurs when there is ineffective ligand binding. This might be caused by a mutation in the _____ region of the gene, which is the ligand-binding region.

A

Class III LDLR (ligand-binding)

N-terminus region

57
Q

Class IV LDLR mutation occurs when the _________ of the receptor is affected. There is therefore no clustering of the clathrin-coated pits.

A

cytoplasmic domain

58
Q

Class V LDLR mutation occurs when there is a mutation in the ____ domain. Endocytosis occurs, but there is no recycling of the LDLR to the surface as LDL is not released from the LDLR.

A

EGFP domain (sensitive to pH changes causing conformational shift)

59
Q

Class __ LDLR mutation occurs when there is a mutation throughout the coding region, which leads to LDLR not being properly transported to the GA and therefore low surface expression.

A

II

60
Q

Resins/sequesterants (cholestyramines) bind and sequester _________ to prevent intestinal absorption.

A

bile acid-cholesterol complexes

61
Q

Muscles (40% of body weight) can metabolise _______ and ______.

A

carbohydrates and fats (B-oxidation)

62
Q

Brain and nervous tissue (2% of body weight) can metabolise _____ and ______. It cannot metabolise _____.

A

Can metabolise carbohydrates (glucose) and ketone bodies; cannot metabolise fats

63
Q

Adipose tissue (15% of body weight) can metabolise ________ and ________.

A

carbohydrates and fats (B-oxidation)

64
Q

The heart (1% body weight) can metabolise ____ and ______.

It accounts for ___% of the BMR as it needs to beat continuously. It is completely (aerobic/anaerobic).

A

can metabolise carbohydrates and fats.

10% of BMR, completely aerobic.

65
Q

The liver (2.5% of body weight) metabolise _____ and ____. It accounts for __% of the B,R and is the main glycogen store.

A

carbohydrates and fats; 20% of BMR

66
Q

The (organ) fuels the body during activation. It is highly metabolically active and can inter-convert nutrient types. It is also involved in lipoprotein metabolism.

A

liver

67
Q

During glycolysis, excess glucose-6-phosphate is converted to ______ and stored in the _____ and _____.

A

Excess glucose-6-phosphate is converted to glycogen and stored in the liver and skeletal muscles.

68
Q

During link reaction, excess acetyl-CoA can be converted into _____ and _______.

A

fatty acids and cholesterol (lipogenesis)

69
Q

During Krebs cycle, pyruvate and other intermediates can be metabolised to produce _________.

A

amino acids

70
Q

___________ is the process of making glucose or glycogen from oxaloacetate. It only occurs in the (organ).

A

Gluconeogenesis; only occurs in the liver

71
Q

Gluconeogenesis requires the hydrolysis of ATP to provide energy. There is a net loss of ___ ATP.

A

Net loss of 6 ATP

72
Q

1st step of gluconeogenesis:

Enzyme ___________ is activated allosterically by _____, and carboxylates pyruvate (3C) to form ______.

A

Enzyme pyruvate carboxylase is allosterically activated by acetyl-CoA, and carboxylates pyruvate (3C) to form oxaloacetate. (4C)

*Acetyl-CoA is accumulated because TCA cycle is halted. (Due to oxaloacetate being diverted to form glucose)

73
Q

2nd step of gluconeogenesis:

Oxaloacetate (4C) will be converted to _______ (3C) by enzyme ___________.

A

oxaloacetate (4C) –> phosphoenolpyruvate (3C)

by enzyme phosphoenolpyruvate carboxykinase

74
Q

3rd step of gluconeogenesis:

Phosphoenolpyruvate (3C) —-»» __________ (reverse glycolysis)

A

fructose-1,6-bisphophate (6C)

75
Q

4th step of gluconeogenesis:

Enzyme ___________ catalyses the removal of a phosphate group from fructose-1,6-bisphosphate to form fructose-6-phosphate.

A

fructose-1,6-bisphosphatase

76
Q

5th step of gluconeogenesis:

Enzyme _______ then removes the last phosphate group from glucose-6-phosphate to form glucose.

A

G-6-phosphatase

77
Q

Fats can feed into the Krebs’ cycle by being broken down into _______, which can be converted to _______.

A

Fats —> Acetyl-CoA (B-oxidation) —> Ketone bodies (which can be used by the heart tissue)

78
Q

Under anaerobic conditions, ATP demand cannot be matched by oxygen delivery and glucose transport. Myocytes will utilise their own ______ and _____ stores.

A

glycogen and fatty acid stores

79
Q

The control of glucose metabolism usually occur in:

  1. steps that involve ________
  2. _____ steps
  3. _______ steps
A
  1. steps that involve enzymatic activity
  2. early steps
  3. irreversible steps
80
Q

Glucose metabolism can be controlled by:

  1. ______
  2. ______
A
  1. Feedback loops

2. Signalling hormones

81
Q

Blood glucose concentration is always maintained around ____.

A

4mM

82
Q

Increased blood glucose concentration leads to increased blood transport into _____ and _____ cells.

A

liver and muscle cells

83
Q

Muscle hexokinase I have a (low/high) glucose affinity, leading to very rapid conversion of glucose at low glucose concentrations.

A

Muscle hexokinase I - high glucose affinity

It is therefore highly sensitive to G6P-inhibition.

84
Q

Liver hexokinase IV have a (low/high) glucose affinity, so it needs to have a certain accumulation of glucose in liver cells before maximal rate can be achieved.

A

Liver hexokinase IV - low glucose affinity

It is therefore less sensitive to G6P-inhibition.

85
Q

When there is increased blood glucose concentration, there is increased glucose transport into liver and muscle cells. This glucose will then be converted to ________ by enzyme _______.

A

glucose-6-phosphate by enzyme hexokinases

86
Q

Hexokinase is inhibited by the accumulation of the product _________. This is negative feedback.

A

G6P

87
Q

There are two main types of hormonal control for blood glucose: ?

A
  1. Pancreatic hormones (Insulin, glucagon)

2. Adrenal hormones (Adrenaline, glucocorticoids)

88
Q

Insulin is secreted by the __ cells in the islets of Langerhans in the pancreas.

A

B-cells

89
Q

Type __ diabetes is the autoimmune destruction of B-cells that produce insulin. Patients therefore cannot make insulin.

A

Type I

90
Q

Type __ diabetes refers to liver and muscle cells having reduced responsiveness to insulin.

A

Type II

91
Q

In diabetes, tissues do not detect the glucose in the bloodstream.

Muscles must therefore break down _____ to produce amino acids as a means of generating energy via gluconeogenesis.

Excess glucose is generated by the liver to meet the needs of the various tissues, but is not taken up.

______ tissues begin to break down fat molecules - the increase in TAG catabolism results in higher ______ in the blood stream, which might undergo B-oxidation in the liver to produce increased concentration of _______.

A

Muscles break down proteins to produce amino acids.

Adipose tissues break down fat molecules to produce fatty acids.

Fatty acids will undergo B-oxidation in the liver to produce ketone bodies.

92
Q

The pancreas is a highly _______ structure. This allows it to sense change in glucose concentration very acutely.

A

vascularised

93
Q

Glucose enters the cell via ____ transporter on the plasma membrane.

A

GLUT-2

94
Q

After a meal:

Increased glucose concentration leads to increased expression of the _____ gene in the cell.

A

insulin

95
Q

After a meal:
Increased ATP closes the ____ channel, depolarising the cell membrane. This causes the opening of voltage-gated ___ channel, allowing the influx of ___ ions.
This would cause insulin-containing vesicles to migrate to the plasma membrane and fuse with it, releasing insulin into the bloodstream via _______.

A
Increased ATP (from glucose metabolism) closes the K+-ATP channel, depolarising the cell membrane. This causes the opening of voltage-gated Ca2+ channel, allowing the influx of Ca2+ ions.
This would cause insulin-containing vesicles to migrate to the plasma membrane and fuse with it, releasing insulin into the bloodstream via exocytosis.
96
Q

The release of insulin into the bloodstream leads to the activation of cell signalling cascades in the cell, one of which increases _____, leading to a change in the gene expression of the insulin gene. This is _______ feedback.

A

PI3’-kinase

Positive feedback loop

97
Q

The bihormonal hypothesis of diabetes suggest that:

A

Insulin deficiency and relative excess of glucagon causes increased hepatic glucose output.

98
Q

Insulin is able to act on pancreatic alpha cells such that the presence of insulin inhibits ______.

A

glucagon release

99
Q

When the blood glucose starts to fall, ________ stimulates skeletal muscle cells to operate glycogenolysis and glycolysis, and adipose tissue towards lipolysis to generate fatty acids and glycerol, which are alternative substrates to glucose.

A

Adrenaline