Sulfuric acid

Question 1

Fertilizer equation

Answer 1

2NH_{3 (aq)} + H₂SO_{4 (aq)} ⇌ (NH₄)₂SO_{4 (aq)}

Question 2

Show that sulfuric acid is a diprotic acid with an equation

Answer 2

• H₂SO_{4 (l)} + H₂O _(l) ⇌ HSO₄^- _(aq) + H₃O⁺ _(aq)
  
  • Ka= 10⁹ M
• HSO₄^- _(aq) + H₂O _(l) ⇌ SO₄^2- + H₃O⁺ _(aq) ​​
  
  • ​Ka= 1.0 x 10^-2 M

Question 3

Sulfuric acid as an oxidant

Answer 3

C (s) + 2H₂SO₄ (l) → CO₂ (g) + 2H₂O (l) + 2SO₂ (g)

Question 4

Sulfuric acid as a dehyrdating agent

Answer 4

C₁₂H₂₂O₁₁(s) → (H₂SO₄) → 12C (s) + 11H₂O (g)

Question 5

Acid rain

Answer 5

SO₂ (g) + H₂O (l) → H₂SO₄ (aq)

Question 6

Contact Process: Stage 1

Answer 6

Furnace

Molten sulfur sprayed into furnace, reacts with dry air to produce sulfer dioxide. The air is then purified and cooled

• S (l) + O₂ (g) → SO₂ (g)

Question 7

Contact Process: Stage 2

Answer 7

Converter

Sulfur dioxide oxidised to form sulfur trioxide

Reaction is reversible

Vanadium (V) oxide (V₂O₅) used as catalyst to maximise product, allows work to be done aat slightly lower temp (400 degrees)

450 degrees

• 2SO₂(g) + O₂(g) ⇌ 2SO₃(g)

Question 8

Contact process: Stage 3

Answer 8

Absorption tower

Sulfur trioxide formed to oleum, then into sulfuric acid

SO₃(g) + H₂SO₄(aq) → H₂S₂O₇ (l)

Dilute to standard

H₂S₂O₇ (l) + H2O (l) ⇌ 2H₂SO₄ (l)