Substitution reactions of benzene 12-13 Flashcards
Draw the general reaction mechanism of electrophilic substitution of benzene.
- The electron-dense ring attracts an electrophile- the electrophile accepts a pair of the pi electrons from the delocalised ring to form a covalent bond.
- An intermediate forms that that contains both the electrophile and the hydrogen atom that is being substituted. The delocalised pi-electron cloud has been disrupted and the intermediate is less stable than benzene.
- The unstable intermediate rapidly loses the hydrogen as an H* ion. The delocalised ring of electrons reforms and stability is restored.
Write the equation for the formation of NO2+.
HNO3 + H2SO4 —–> NO2+ + HSO4- + H2O
What are the reagents needed for the nitration of benzene and why are they needed in the reaction?
- A mixture of concentrated nitric acid and concentrated sulfuric acid is used.
- The sulfuric acid is needed to generate an electrophile from the nitric acid.
- The electrophile is the nitryl cation, nitronium ion, and has the formula NO2+.
Draw the mechanism for the nitration of benzene.
Explain how the sulfuric acid acts as a catalyst in the nitration of benzene.
The H+ reacts with the HSO4- from the first step to reform H2SO4. So the sulfuric acid is acting as a catalyst.
H++ HSO4- —–> H2SO4
Write how the equation for the formation of Br+(bromonium ion, reacts with benzene).
Br2 + FeBr3 ——> Br+ + FeBr4-
Draw out the mechanism for the bromination of benzene.
Show how the iron(III) bromide used as a halogen carrier in the bromination of benzene is a catalyst.
The H+ reacts with FeBr4- from the first step to form the other product of the overall reaction, HBr, and to reform FeBr3. So the iron(III) is acting as a catalyst.
H+ + FeBr4-——-> FeBr3 + HBr
For bromination what halogen carriers could you use?
- For bromination, the halogen carrier is AlBr3, FeBr3or Fe.
- You can use Fe for bromination because Fe reacts with the halogens to form the iron (III) halide.