Stoichiometry Flashcards
Construct equations with state symbols, including ionic equations
-Start with the balanced chemical equation
HCl(aq) + NaOH(aq) → NaCl (aq) + H2O (l)
-Split up (aq) compounds into its ions
H+ + Cl- + Na+ + OH- → Na+ + Cl- + H2O
-Cancel out the ions that are the same on either side – known as ‘spectator ions’, leaving the ionic equation
H+ + OH- → H2O
Relative atomic mass, Ar
Average mass of naturally occurring atoms of an element on a scale where the 12C atom has a mass of exactly 12 units
Relative molecular mass, Mr
Sum of the relative atomic masses. (Relative formula mass or Mr will be used for ionic compounds.)
Mole and the Avogadro constant
- Mole = amount of substance
- The number of atoms, molecules or ions in a mole of a given substance is the Avogadro constant: 6.02x1023permole.
Molar gas volume, taken as 24 dm3 at
room temperature and pressure
Volume (dm3 ) of gas at RTP = Mol. x 24
Calculate stoichiometric reacting masses, volumes of gases and solutions, and concentrations of solutions expressed in g / dm3 and mol / dm3
moles = mass ÷ formula mass
● You can work out the moles or volume of a gas at RTP using the equation: volume = moles x 24, rearranged to: moles = volume ÷ 24
● You can work out concentrations of solutions in g/dm3 using the equation: concentration = mass of solute ÷ volume
● you can work out concentrations of solutions in mol/dm3 using the equation: concentration = moles of solute ÷ volume
● to convert between concentration in mol/dm3 and g/dm3: mol/dm3 → g/dm3 multiply by Mr, g/dm3 → mol/dm3 divide by Mr
● if you are given a reacting mass/volume/concentration and are asked to work out the mass/volume/concentration of another reactant or a product:
o calculate the number of moles (use the appropriate equation from
above)
● limiting reagents:
o in a reaction, often one of the reactants will be a limiting reagent. This means that this reactant will be used up first and will cause the reaction
to stop.
- if given the mass/volume of a limiting reagent and
another reagent, you must use the mass/volume of the limiting reagent.
Empirical formulae and molecular formulae
-if there is a common multiple in the number of different elements in your molecular formula, then divide by this number to give you the simplest whole number ratio. e.g. Fe2 O 4, common multiple is 2, empirical formula is FeO2
-Find relative molecular mass of the empirical formula, Divide relative molecular mass of compound by that of the empirical formula, If answer was 2 and the empirical formula was Fe2 O 3 then the molecular
formula would be empirical formula x 2 = Fe4 O 6
Percentage yield and percentage purity
Percentage yield= Amount of product produced(AY)/ Maximum amount possible (TY) x 100
Percentage purity = Mass of impure/ mass of pure x 100