Electricity and chemistry Flashcards
Electrolysis
the breakdown of an ionic compound, molten or in aqueous solution, by the passage of electricity
electrode products and the observations made during the electrolysis of:
– molten lead(II) bromide
– concentrated hydrochloric acid
– concentrated aqueous sodium chloride
– dilute sulfuric acid
between inert electrodes (platinum or carbon)
ionic solution will contain the ions that make up the ionic compound, and the ions in water (OH- and H+)
● at the cathode (-):
○ hydrogen (from H+ in water) is produced UNLESS the + ions in the ionic compound are from a metal less reactive than hydrogen
○ if the metal is less reactive, it will be produced instead
● at the anode (+):
○ oxygen (from OH- in water) will be produced UNLESS the ionic compound contains halide ions (Cl- , Br-, I-)
○ if there are halide ions, the halogen will be produced instead (e.g. Cl2)
● Electrolysis of:
○ Molten lead (II) bromide: Pb2+ to cathode, Pb (s) is produced, Br- to anode, Br2 (l) is produced.
○ Concentrated hydrochloric acid: H+ ions go to cathode, H2 (g) is produced, Cl- ions go to anode, Cl2 (g) is produced.
○ Sodium chloride solution: H+ ions go to cathode, H2 (g) is produced (Na is more reactive than
hydrogen), Cl- ions go to anode, Cl2 (g) is produced (Cl- are halide ions)
○ Dilute sulfuric acid: H+ to cathode, H2 (g) is produced (these are the other ions present in sulfuric acid H2SO4), OH- to anode, O (g) is produced (SO 2- ions are not halide ions)
Relate the products of electrolysis to the electrolyte and electrodes used
●Electrolysis of copper (II) sulfate solution
o Cu+ ions go to cathode, Cu (s) is produced (Cu is less reactive than
hydrogen)
o OH- ions go to anode, O (g) is produced (SO4 2- ions are not halide ions)
Copper electrodes:
● set up:
o anode is made of impure copper (that you are purifying)
o cathode is made of pure copper
o the solution is copper sulfate
● what happens:
o Cu2+ions from the anode move to the cathode,where they gain electrons and are discharged as pure copper
o impurities form as sludge below the anode
● the cathode will increase in mass as it gains pure copper, whilst the anode will lose mass as copper ions are lost (they replace the ones from the CuSO4 solution that go to the cathode) and so are impurities
Carbon electrodes :
● at the cathode Cu (s) is produced (Cu is less reactive than hydrogen)
● at the anode O is produced (SO 2- ions are not halide ions) 2 4
● this leaves H+ and SO 2- ions in the solution, which will react to form H2SO4-
sulfuric acid
electrolysis in terms of the ions present and reactions at the electrodes in the examples given
● During electrolysis, positively charged ions (cations) move to the negative electrode (cathode), and negatively charged ions (anions) move to the positive electrode (anode).
● Ions are discharged at the electrodes producing elements.
State the general principle that
metals or hydrogen are formed at the negative electrode (cathode), and that non-metals (other than hydrogen) are formed at the positive electrode (anode)
electroplating of metals
● electroplating is a method of coating objects with a metal, using electrolysis
● Negative electrode = object to be electroplated
● Positive electrode = metal to coat the object with
● Electrolyte = solution of the coating metal (with ions of the coating metal in)
● the metal ions from solution are deposited on the negative electrode, and metal ions are released from the positive electrode to replace those lost in solution
uses of electroplating
● Coating a cheaper metal with a more expensive one, silver or copper
● Silver:Cutlery
● Copper:Metal pan
constructing ionic half-equations
○ negative electrode: X+ -> X, so ionic equation must be:
X+ + e- -> X, electrons gained, so positive ions are reduced
○ positive electrode: X- -> X, so ionic equation must be:
X- -> e- + X, electrons are lost, so negative ions are oxidised
- Oxidation Is Loss (of electrons) and Reduction Is Gain (of electrons) - OIL RIG
- ANODE :loss of electrons, oxidation (positive electrode) anions come to it
- CATHODE :gain of electrons, reduction (negative electrode) cations come to it
- “Red Cat An Ox”, oxidation occurs at the anode and reduction occurs at the cathode.
reasons for the use of copper and (steel-cored) aluminium in cables, and why plastics and ceramics are used as insulators
- Aluminium – good conductor of electricity, therefore is used in overhead power cables
- Copper –good conductor of electricity, therefore is used for electrical wiring
- Plastics & ceramics do not conduct electricity – therefore they are used as insulators
transfer of charge during electrolysis to include:
– the movement of electrons in the metallic conductor
– the removal or addition of electrons from the external circuit at the electrodes
– the movement of ions in the electrolyte
-Movement of electrons in the metallic conductor
o Electrons move in the wire
o Move from positive electrode to negative electrode
-Movement of ions in the electrolyte
o Positive ions move to negative electrode to receive electrons and are
reduced
o Negative ions move to positive electrode to lose electrons and are
oxidised
the production of electrical energy from simple cells
- you have 2 metal electrodes in an electrolyte solution and connect the 2 electrodes by a wire (outside of the solution), this creates a current of electrons and so creates electrical energy
- More reactive metal will lose electrons, least reactive will gain them
manufacture of:
– aluminium from pure aluminium oxide in
molten cryolite
– chlorine, hydrogen and sodium hydroxide from concentrated aqueous sodium chloride
-Aluminium is manufactured by the electrolysis of a molten mixture of aluminium oxide and cryolite using carbon as the positive electrode (anode).
o Aluminium oxide has a very high melting point, so it would be too expensive to melt it, which is why it is mixed with cryolite
o the positive electrodes need to be continually replaced because oxygen is formed, which reacts with the carbon of the positive electrodes, forming carbon dioxide, and they gradually burn away
-Sodium chloride
o Chlorine gas forms at the positive electrode
o Hydrogen gas forms at the negative electrode
o Solution of sodium hydroxide forms
o Must use inert electrodes since the products are reactive