Solutions & Emulsions Flashcards

1
Q

emulsification

A

adding energy thru titration/homogenization –> creates small droplets of one liquid phase within another AND a static charge around those droplets.

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2
Q

adding energy thru titration/homogenization –> creates small droplets of one liquid phase within another AND a static charge around those droplets.

A

emulsification

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3
Q

compounding challenges for emulsions (3 additions)

A
  1. Preservatives added –> prevent microbiologic growth; must be present in aqueous phase in free, unbound, un-ionized, unadsorbed state
  2. antioxidants added –> to prevent rancidification of oils/fats (bad smell/taste)
  3. flavoring added –> to external phase to improve taste
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4
Q

Solution

A

liquid preps that contain one or more solute dissolved in a solvent OR the mixture of 2 miscible solvents

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5
Q

liquid preps that contain one or more solute dissolved in a solvent OR the mixture of 2 miscible solvents

A

solution

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6
Q

solute

A

substance dissolved in solvent

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7
Q

solvent

A

base liquid

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8
Q

solution

A

solute dissolved in solvent

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9
Q

solubility

A

degree/extent to which a solute dissolves in a solvent

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10
Q

Solution vs. Suspension

A

Solution:
- homogenous
- smaller particles mixed
- dissolved –> looks clear
- uniform distribution
- less stable

Suspension:
- heterogenous
- larger particles suspended
- mixture –> looks cloudy
- need to shake to uniformly distribute particles

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11
Q

Aqueous Solution vs. Non-Aqueous Solution

A

Aqueous:
- solvent = distilled water
- most common
- add flavoring, preservatives, buffering salts
- ex. syrups, aromatic waters, mucilage, aqueous acids

Non-Aqueous:
- solvent = alcohol (not water)
- less common due to alcohol concerns
- caution in peds
- ex. elixirs, spirits, tinctures

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12
Q

1 oz = ____ ml

A

1 oz = 29.57 ml

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13
Q

% w/v =

A

g/100 ml

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14
Q

% v/w =

A

ml/100g

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15
Q

% v/v

A

ml/100ml

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16
Q

mg%

A

mg/100ml

17
Q

“qs to Xoz” –>

A

final dispensing volume (convert oz to ml)
(29.57ml = 1 oz)

18
Q

amount of drug needed is given as a % –>

A

create a proprotion comparing % to final dispensing volume
○ ex. 10% = 10g / 100mL
○ final dispensing volume = 118.3mL
○ so, 10g / 100 ml = Xg / 118.3ml
answer: X=11.83g

19
Q

Solution Procedure:

A
  1. weigh out drug in beaker
  2. dissolve drug in minimal amount of dH2O
  3. transfer to grad cylinder w/ repeated washings of solvent
  4. qs to final dispensing volume with solvent
  5. mix by pouring between dispensing container and grad cylinder
  6. label/dispense