RNA structure & Processing (Post-Transcription) Flashcards
What is the chemical structure of RNA?
Mostly single stranded but can base-pair with complementary sequence within itself.
What are coding RNAs?
Messenger RNAs (mRNA) that code for synthesis of proteins
Match the following non-coding RNAs to their definitions:
1) Ribosomal RNAs (rRNA)
2) Transfer RNAs (tRNA)
3) Small nuclear RNAs (snRNA)
4) Small nucleolar RNAs (snoRNA)
5) Micro RNAs (miRNA)
6) Short interfering RNAs (siRNA)
7) Piwi-interacting RNAs (piRNA)
8) Long non-coding RNAs (lncRNA)
A) Important in protein synthesis; adapter between mRNA and amino acids with a complex tertiary structure
B) Regulate gene expression by blocking translation of specific mRNAs (can also increase degradation)
C) Scaffolds for chromatin folding; X-chromosome inactivation and more. Controversial.
D) 1) primary component of the ribosome & 2) catalyze protein synthesis
E) Involved in pre-mRNA splicing (attach to proteins to form snRNPs - snRiboNucleoProtein /splicesome). There is various kinds; U1, U2, U4, U5, U6 snRNA
F) Processing and chemical modification of rRNAs (increase stability, half life and optimal function)
G) Regulate gene expression by blocking translation of specific mRNAs (can also increase degradation)
H) Bind to piwi proteins and protect the germ line from transposable elements.
Ribosomal RNAs (rRNA): 1) primary component of the ribosome & 2) catalyze protein synthesis
Transfer RNAs (tRNA): Important in protein synthesis; adapter between mRNA and amino acids with a complex tertiary structure
Small nuclear RNAs (snRNA): Involved in pre-mRNA splicing (attach to proteins to form snRNPs - snRiboNucleoProtein /splicesome). There is various kinds; U1, U2, U4, U5, U6 snRNA
Small nucleolar RNAs (snoRNA): Processing and chemical modification of rRNAs (increase stability, half life and optimal function)
Micro RNAs (miRNA): Regulate gene expression by blocking translation of specific mRNAs (can also increase degradation)
Short interfering RNAs (siRNA): Regulate gene expression by blocking translation of specific mRNAs (can also increase degradation)
Piwi-interacting RNAs (piRNA): Bind to piwi proteins and protect the germ line from transposable elements.
Long non-coding RNAs (lncRNA): Scaffolds for chromatin folding; X-chromosome inactivation and more. Controversial.
Which non-coding RNAs are important for regulating gene expression?
Micro RNAs (miRNA)
Short interfering RNAs (siRNA)
What does post-transcriptional gene control involve?
1) Processing of Eukaryotic Pre-mRNA
2) Regulation of Pre-mRNA processing
3) Transport of mRNA across the nuclear envelope
4) Processing of rRNA and tRNA
What is the difference between pre-mRNA and mRNA?
pre-mRNA: mRNA precursor containing introns and not cleaved at the poly(A) site
mRNA: fully processed mRNA with 5’cap, introns removed by RNA splicing and a poly(A)tail
Where do the properly processed mRNAs go from the nucleus? What happens to the improperly processed mRNA?
Properly processed mRNAs - exported to the cytoplasm so they can be translated by ribosome
Improperly processed mRNAs = blocked from export to the cytoplasm, degraded by the EXOSOME complex that has lots of ribonucleases. This complex can also modify the mRNA to make it functional.
Briefly describe the processing of eukaryotic pre-mRNA.
Pre-mRNA is capped, polyadenylated, spliced, and associated with RNPs (ribonucleoproteins) in the nucleus before export to the cytoplasm.
Splicing is done by a large ribonucleoprotein splicesome complex through two TRANSESTERIFICATION reactions.
A network of interactions between SR (serine-arginine rich) proteins, snRNPs, and splicing factors form a ______-____ recognition complex that specifies correct _____ sites.
Cross-exon
Splice
What are lariat RNAs?
The introns spliced out of the mRNA that are circular molecules with a short tail.
What is the G value paradox? How is it explained?
The number of protein-coding genes does not correlate with biological complexity.
It is in part due to differential processing of pre-mRNAs! (One protein coding gene can yield multiple protein isoforms?)
What are the different forms of alternative splicing? Briefly describe them.
1) Constitutive splicing: remove all introns, stitch all exons together
2) Exon skipping: an exon is skipped and still yields a functional protein
3) Intron retention: can have an intron retained as a “pseudo exon.” can be used to suppress protein activity.
4) Mutually exclusive exons: some exons never together; one or the other. Could be due to having different substrates of isoforms or having opposing catalytic activity.
5) Alternative 5’ splice site: what’s at the beginning of the mRNA is different
6) Alternative 3’ splice site: what’s at the end of the mRNA is different
Is the largest human gene the human gene with most exons?
No! The largest gene (Contactin-associated protein like 2 gene) has 24 exons spanning millions of base pairs, while the human gene with most exons (TTN gene) has 346 exons spanning 300,000 base pairs.
What is the difference between prokaryotic and eukaryotic mRNA?
Prokaryotic mRNA:
- no 5’ cap
- no polyA tail
- several genes of an operon transcribed into one mRNA
- one mRNA leads to multiple proteins
Eukaryotic mRNA:
- 5’ cap
- polyA tail
- one gene transcribed into one mRNA
- one mRNA leads to one protein (not considering alternative splicing)
What does RNA processing produce in eukaryotes?
RNA processing produces functional mRNA.
Where does RNA polymerase start transcription, where does it end?
RNA polymerase starts transcription at gene nucleotide +1, which is upstream (“before”) of the codon that encodes the first amino acid.
RNA polymerase stops transcription downstream (“after”) of the translation STOP codon.
What are the 5’ and 3’ untranslated regions (UTRs) of the mRNA?
These regions are transcribed into mRNA but will not be translated into proteins by the ribosome.
5’ UTR is recognized by the ribosome to bind and initiate translation.
3’ UTR is after the STOP codon.
Match the steps of RNA processing:
1) Step 1
2) Step 2
3) Step 3
4) Step 4
A) Endonuclease cleaves primary transcript (downstream of the STOP codon) at the poly(A) site
B) POLY(A) POLYMERASE adds 100-200 A residues
C) For short primary transcripts with few introns, splicing occurs after step 3.
For long primary transcripts with multiple introns, introns spliced out at the nascent RNA during transcription.
D) Nascent RNA 5’ end capped with 7-METHYLGUANYLATE during formation of the RNA transcript. Transcription terminated at one of multiple termination site downstream from the poly(A)site
Step 1: Nascent RNA 5’ end capped with 7-METHYLGUANYLATE during formation of the RNA transcript. Transcription terminated at one of multiple termination site downstream from the poly(A)site
Step 2: Endonuclease cleaves primary transcript (downstream of the STOP codon) at the poly(A) site
Step 3: POLY(A) POLYMERASE adds 100-200 A residues
Step 4: For short primary transcripts with few introns, splicing occurs after step 3.
For long primary transcripts with multiple introns, introns spliced out at the nascent RNA during transcription.
What is the function of the poly(A) tail?
- Stabilizes the mRNAs in the nucleus and cytoplasm
- Involved in mRNA translation
- Protects mRNA from being degraded by exonucleases
What is the function of 5’ Methylated cap?
- Protects mRNA from enzymatic degradation
- Assists export of the mRNA to the cytoplasm
- Bound by a protein factor required by ribosome to begin translation
(T/F) 5ʹ→5ʹ Linkage of 7-methylguanylate to the initial nucleotide of the mRNA molecule and methyl group addition to the 2ʹ hydroxyl of the ribose of base 1 occur in all animal and most plant cells.
True!
(T/F) The methyl group can only be added to the 2ʹ hydroxyl of the ribose of base 1.
False! It can be added in base 2 as well.
Yeasts cells lack methyl group on base 1, but have it on base 2. While, vertebrate cells have methyl on both bases.
Match the steps of the synthesis of the 5’cap on eukaryotic mRNA:
1) Step 1
2) Step 2
3) Step 3
4) Step 4
A) GUANYLYL TRANSFERASE links GMP residue from GTP to the 5ʹ diphosphate of the transcript, creating a guanosine 5ʹ-5ʹ triphosphate structure.
B) 2’-O-METHYL TRANSFERASE – transfers methyl group from
S-adenosylmethionine to the 2ʹ oxygens of riboses of the first one or two RNA nucleotides (base 1/base 2)
C) PHOSPHOHYDROLASE removes the γ phosphate, while α and β phosphates remain associated with the cap
D) GUANYLYL-7-METHYL TRANSFERASE transfers methyl
group from S-adenosylmethionine to the guanine N7 position
Step 1: PHOSPHOHYDROLASE removes the γ phosphate, while α and β phosphates remain associated with the cap (all attached to the first base of pre-mRNA)
Step 2: GUANYLYL TRANSFERASE links GMP residue from GTP to the 5ʹ diphosphate of the transcript, creating a guanosine 5ʹ-5ʹ triphosphate structure.
Step 3: GUANYLYL-7-METHYL TRANSFERASE transfers methyl
group from S-adenosylmethionine to the guanine N7 position
Step 4: 2’-O-METHYL TRANSFERASE – transfers methyl group from
S-adenosylmethionine to the 2ʹ oxygens of riboses of the first one or two RNA nucleotides (base 1/base 2)
What is S-adenosylmethionine?
Methyl donor - gives methyl to the 5’ cap and to the 2ʹ hydroxyl of the ribose of base 1 or base 2 of the mRNA.
What is the RNA recognition motif (RRM)?
Most common RNA-binding domain in heterogeneous nuclear ribonuclearprotein proteins (hnRNP proteins) and other RNA-binding proteins.
It is composed of two α helices and four β strands. It has highly conserved RNP1 and RNP2 regions, which are located in the two central β strands.
What are the sex-lethal RNA recognition motif (RRM) domains?
Two RRM domains in Drosophila melanogaster Sex-lethal (Sxl)
protein.
The domains are oriented with the β sheets of the RRMs facing toward each other.
The domains, together, bind a nine-base sequence in transformer pre-mRNA to the surfaces of the positively charged β
sheets.
What are the intron splice site invariant bases (flanking bases found at frequencies higher than expected for a random distribution)?
5’ GU: splice donor
3’ AG: splice acceptor
Branch point adenosine
*Most conserved + important regions for splicing
*10/10 times, there is gonna GU at that 5’ site, there is gonna AG at that 3’ site and Adenosine in the branch point.
*This is what the two transesterification reactions involve
What is the polypyrimidine tract in the pre-mRNA?
What is the central region?
Polypyrimidine tract: found in most introns near the 3’ end
Central region: 40 bases-50kilo bases long. Not conserved, can be varied. Regulatory regions.
How many nucleotides at each end of an intron are necessary for splicing to occur at normal rates?
30-40 nucleotides
Match the following step of the two transesterification reactions that result in the splicing of exons in pre-mRNA:
1) Reaction 1
2) Reaction 2
A) 3’ Oxygen of EXON 1 binds to the 5’ Phosphate of EXON 2, breaking the ester bond between the phosphate of EXON 2 and the INTRON’s 3’ oxygen.
B) 5’ Phosphorus of the INTRON binds to 2’ Oxygen of BRANCH POINT A (ester bond) by breaking its bond with the 3’ Oxygen of EXON 1 (ester bond).
Reaction 1: 5’ Phosphorus of the INTRON binds to 2’ Oxygen of BRANCH POINT A (ester bond) by breaking its bond with the 3’ Oxygen of EXON 1 (ester bond).
Reaction 2: 3’ Oxygen of EXON 1 binds to the 5’ Phosphate of EXON 2, breaking the ester bond between the phosphate of EXON 2 and the INTRON’s 3’ oxygen.
The two exons are joined, the intron is released as a LARIAT stricture.
*look at slide 20 to fully understand
What are the key oxygens in the two two transesterification reactions that result in the splicing of exons in pre-mRNA?
1) 3’ oxygen of exon 1
2) 2’ oxygen of branch point A
3) 3’ oxygen of intron
snRNAs base pair with the pre-mRNA during splicing. Match the following snRNAs to what they base pair.
1) U1 snRNA
2) U2 snRNA
A) Base pairs with sequence surrounding the branch point A
B) Base pairs across 5’ splice site exon-intron junction
snRNAs base pair with the pre-mRNA.
U1 snRNA: base pairs across 5’ splice site exon-intron junction
U2 snRNA: base pairs with sequence surrounding the branch point A.
*U cause they are rich in uracil!
Why is branch point A not base paired but only its surroundings by U2 snRNA?
So that it can bulge out to allow the 2’ OH to participate in the first transesterification reaction.
What happens if there is a mutation in the pre-mRNA 5’ splice site and U1 snRNA can no longer base pair to it?
How is this restored?
Splicing is blocked!
U1 RNA has a compensating mutation, that restores the base pairing, that restores the splicing.