Risk Management Flashcards
The National Aeronautics and Space Administration (NASA) uses redundant systems, each of which uses highly reliable components. System A has a probability of failure of 0.05, the redundant system B has a probability of failure of 0.03, and a common component in both systems has a probability of failure of 0.015.
What is the probability that both system A and system B fail?
0.015 ; Common mode/cause failure (CCF).
_
Since the Propability that a common component failing is 0.015, the propability that the redundant system will fail
cannot be any less than 0.015.
Risk impact assemssment factors would likely include:
Cost, schedule and functionallity
(III - 2/4)
What risk management technique lies outside of the execution phase of the risk management process?
Risk Planning
III - 4
Which of hazards would be considered as having the greatest hazard level?
Marginal/ frequent
Marginal severity with frequent occurence (I
III -23/30)
Hazard analysis on heat transfer problems such as: heat absorption, combustion, electrical losses, or equipment degeneration can be solved via which specific techique?
Energy analysis
III - 23/26
Which of the following standards addresses safety of machinery?
IEC 61310
III - 49
What technique is preferred for investigation into product failures that are not repairable once initiated?
FTA
( III - 8)
In the case of a common mode failure:
One event can cause single or multiple systems to fail
(III - 21)
A form of mechanical hazard would be:
Pinching
III - 26
A Failure modes and effect analysis is a method to analyze a system, subsystem, a part or a process for all potential failures modes. The failure modes will be prioritized and reduced to acceptable levels.
The best benefits for FMEA analysis comes:
Early in the design cycle
(III - 13/17)
What does the Japanese concept of poka-yoke mean?
Mistake proofing (II - 74 und 81)
What is the primary purpose of a failure mode, effect and criticality analysis (FMECA)
To dermine, by extensive analysis, the realiability of an item
(III - 13/17)
Risk management programs are often developed to
Safe Recources
(III - 35)
When considering reducing human errors using devices which of the following is considered accepted practice?
Green is normal condition and red is an abnormal condition
III - 56
The descision to establish controls for product testing only during the acceptance testing step of the project is a form of risk management known as …
Risk acceptance or assumption
(III - 4)
The nuclear reactor failure at Chernobyl USSR is an example of …
A number of common mode failures
III - 22
What is the verification that a safety system meets the requirements of a standard?
Compliance
III - 42/43
A risk anaylsis method using modeling simulations would be considered a:
Monte Carlo method (III - 31/32)
A company has a problem with damage to fragile assemblies during component handling and parts storage.
Which of the following is the best way to detect the cause of this problem?
Perform a fault-tree analysis
III - 7/8
A failure verified as peculiar to an item design, that will not enter to the operational
inventory is a:
Non-relevant failure
(III - 27/30)
Taking out an insurance policy for medical cost is one way of risk:
Transference
(III - 55)
Actions in the risk managment continous process consist of:
Accepting, mitigating or transferring the risk (III - 2/4)
Risk analysis planning should:
Start at the risk handling phase
(III - 3 und 29/30)
The most applicable reference on risk management can be found in:
ISO/FDIS 31’000
III - 5 und 49
In what risk managment process phase would reaction modles and decision analysis fall?
Risk analysis
III - 4
In the area of risk assessment, hazard severity categories are used to provide a measure of the seriousness involved.
A system failure causing major environmental damage would be classified as:
Critical
III - 27/2
The assessment of product development risk usually occurs during what design review phase?
Concept Development (III - 39)
A piece of equipment will fail as an “or” function of three components. The components have propabilities of failure of 0.07, 0.03 and 0.12.
What is the propability that the system will fail?
P(system failure) =
1 - (1-(P comp 1 fail)(1-(P comp 2 fail))(1-(Pccomp 3 fail))
=> 0.206