Quadratic Functions Theory (SL) Flashcards
What are the three ways to solve a quadratic equation?
- Factorization
- Completing the square
- The quadratic formula
What are the steps to solving a quadratic equation by factorising?
- Get everything on one side, leaving just 0 on the other. (i.e. x2-2x+1=0).
- Factorise, so you get something like (x+a)(x+b)=0.
- Solve each parenthesis for x. (i.e. x+a=0 and x+b=0)
How can you recognize that an equation is quadratic?
Some variable is squared.
It can always be written as:
ax2+bx+c=0
What are the steps for factorising a quadratic equation?
ax2+bx+c=0
- Factor out any common factors. (So anything that goes into all of the terms. i.e. 6x2-2x-8 = 2 (3x2-x-4))
- Make a list of all the factors that multiply to make ac.
- Check to see which two factors from step two add to the b term.
- Rewrite the equation, separating the middle term into the two factors you found.
- Take the common factors out of the first two terms and the last two, and regroup.
For example, 3x2-x-4:
- 6x2-2x+8=2(3x2-x-4). Now I need to factorise 3x2-x-4
- 3•-4=-12, so the factors are 1•-12, -1•12, 2•-6, -2•6, 3•-4, -3•4
- Do any of the pairs add to -1? Yep, 3+-4=-1.
- 3x2+3x-4x-4
- 3x(x+1) - 4(x+1) = (3x-4)(x+1). So the answer is 6x2-2x+8=2(3x-4)(x+1).
What does the graph of f(x)=x2 look like? What are the vertex and line of symmetry?
Vertex: (0,0)
Line of symmetry: x=0
Where is the vertex and line of symmetry for
f(x)=a(b(x-h)2+k)?
Vertex: (h, a•k)
Line of symmetry: x=h
How can you find the root if a quadratic equation has “two equal real roots”?
This means the discriminant is zero, so your solution is just
How do you find the x-intercept of ANY function?
You plug in 0 for y and solve for x….because when you’re on the x-axis, the y-coordinate MUST be equal to 0.
How do you find the y-intercept of ANY function?
You plug in 0 for x and solve for y….because when you’re on the y-axis, the x-coordinate MUST be equal to 0.
How do you know when there are two repeated real roots for ax2+bx+c?
You find when the discriminant is 0.
So solve b2-4ac=0.
How do you know when there are no real roots for ax2+bx+c?
You find when the discriminant less than 0.
So solve b2-4ac<0.
How do you know when there are two real roots for ax2+bx+c?
You find when the discriminant greater than 0.
So solve b2-4ac>0.
When you need to use the “complete the square” method?
Whenever you need the form of the equation to tell you the vertex.
f(x)=(x-h)2+k
What’s the quadratic formula?
How do you turn
f(x)=ax2+bx+c
into the “vertex” form
f(x)=a(x-h)2+k?