Physics IV: Electrostatics, Batteries, Capacitors, Resistors Flashcards

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1
Q

the attractive force holding together the nucleus is directly caused by

A

electric charge, both positive and negative

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2
Q

charge of a proton is called the ______________ and is designated by the symbol ____. Its value is __________ C (coulombs)

A

“elementary charge”

symbol: +e
value: e=1.6 x 10-19 C

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3
Q

if a neutral atom has electrons removed/added/both we say it has been ionized

A

both, and the resulting atom is an ion

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4
Q

what does it mean to say that charge is “quantized”

A

it means that an object can be charged by losing or gaining electrons or protons in whole number amounts.

so, q=n(±e)

q=charge

n= 0, 1, 2, …

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5
Q

How do you find the charge of any ion in Coulombs?

A

Example: Flourine

take its simplified charge: -1 →means -1e → means -1 elementary units → so multiply -1 x unit of elementary unit → -1 x 1.6 x 10-19 → -1.6 x 10-19

for a positively charged atom like

Ca2+ it’s +2 x 1.6 x 10-19 ​→ +3.2 x 10-19

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6
Q

What’s Coulombs law and what does it mean?

A

Fe=k |q1q2| /r2 (in Newtons)

It means that the magnitude of the electrostatic force is proportional to the absolute value of the charges (q1q2) and inversely proportional to r2

when the material between the charges is air, then k is Coulomb’s constant, which is 9 x 109 N•m2/C2

*in problems, assume K is coulombs constant unless specified otherwise

Each particle feels the same force (Fe) toward or against one another

*picture shows its similartiy to newton’s law

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7
Q

as a smaller object moves away from a larger object d/t repulsion, the object’s acceleration will increase/decrease

A

decrease because electrostatic force is inversely proportional to the square of the distance between the charges and as a smaller object moves away from the larger object (in a repulsion scenario) the distance increases which weakens the electrostatic force/force of repulsion in this case

F proportional to acceleration, so if force decreases so will acceleration

*note that velocity is increasing because it remains in movement in the same vector as before, away from the larger body, but the rate at which it increases slows

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8
Q

how do you determine the net electric force on a charge (q) due to a collection of other charges (Qs)

A

it is equal to the vector sum of the individual forces that each of the charges (Qs) alone exerts on q

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9
Q

Which of the following pairs of electric forces form an action-reaction pair? (can pick more than one)

I. 2 positive charges of different masses placed at a distance d apart

II. 2 negative charges of equal masses placed at a distance d apart

III. one positive charge and one negative charge of equal masses placed at a distance d apart

A

All of them.

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10
Q

T/F: The electric field inside of an electrostatic conductor is always zero

A

true

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11
Q

Moving from higher electric potential (V or φ) to lower electric potential, you get a increase/decrease in PE (-ΔPE)

A

decrease (analogous to the PE that decreases when you drop a book from a height)

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12
Q

For an electron, the move towards higher potential φ (ie higher voltage), is favorable/unfavorable, because then Δφ is positive (+), which yields a negative ΔPE in the equation:

ΔPE=qΔφ

A

favorable because -ΔPE always represents movement with nature which is favored

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13
Q

within a conductor, if a voltage is not applied, then there is no net movement of electrons, meaning that they are freely moving, but in random directions such that the directions all cancel out. What does it look like to apply a voltage?

A
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14
Q

how is current measured

A

since current is the flow of charge, we use a version of flow rate equation f=Av:

I=Q/t

Q=charge in coulombs

t=time

I= current

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15
Q
A
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