Particle in a box Flashcards

1
Q

Set up for particle in a box

A

Similar to free particle but restricted within a box length L

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2
Q

Boundary conditions for particle in a box

A

Infinite potential energy at the sides, elsewhere is 0
(particle cannot escape)

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3
Q

Equations for boundary conditions potential energy :

A

V(x<=0) = infinity
V(x=>L) = infinity
V(0<x<L) = 0
Where L is the length of our box

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4
Q

Equation for wavefunction at boundaries and explained

A

Ψ(x=0) = 0, Ψ(x=L) = 0,
hence we will have a standing wave with n+1 nodes

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5
Q

General wavefunction for standing wave:

A

Asin(kx+phi)

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6
Q

Steps to solve for E:

A

Use boundary condition of Ψ at 0 to show phi = 0
Use boundary condition of Ψ at L to show kL = npi, where n = 1,2,3… rearrange for k.
Use standing wave equation and k=k, to get in terms of λ.
Sub in de broigle for λ, to get in terms of p.
Use E =p^2/2m and sub in for p to show quantised

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7
Q

Standing wave equation

A

k = 2pi/λ

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8
Q

Is energy quantised for particle in a box?

A

Yes

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9
Q

Steps for calculating A

A

Use probability density integral with general wavefunction (no phi), between 0 and L.
Take out A and use triganometric identity:
sin^2(x) = (1-cos(2x))/2
Solve for A = (2/L)^1/2

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10
Q

Final wavefunction for particle in a box

A

Ψ = ((2/L)^1/2)Sin(npix/L)

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11
Q

How to find delta E

A

Delta E = En+1 - En, and simplify and solve

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12
Q

What happens to delta E as L tends towards infinity, and what does this tell us

A

Delta E tends towards 0, so for macroscopic L’s energy is unquantised

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13
Q

Zero point energy equal to 0?

A

No it is when we are in the ground state at n=1

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14
Q

What happens to values calculated when in a 2d box

A

Energies will be added together with different quantum numbers, and wavefunctions will be multiplied together

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15
Q

What type of molecules can be explained via particle in a box

A

Long conjugated straight-ish molecules

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16
Q

Heisenberg uncertainty principle equation

A

Deltap*deltax = ℏ/2

17
Q

Implication of Heisenberg uncertainty principle

A

It is impossible to know exactly both the position and momentum of a particle at the same time.