Moles Flashcards

0
Q

RAM

A

Relative atomic mass/Ar

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1
Q

(Sq 24) Mg
(Sq 25) Mg
(Sq 26) Mg
These are all … Of eachother ad they have more/ less …

A

Isotopes

Neutrons

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2
Q

RAM is the … Of one mole of atoms compared to the mass of one mole of … Which is the most common isotope of … Which is the most common … On earth

A

Mass
Carbon-12
Carbon
Element

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3
Q

RAMs are found on an element in the periodic table at the

A

Top left hand number in the element box

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4
Q

Find the RAM of (sq35) Cl 75% and (sq37) Cl 25%

A

Total mass of 100 atoms: (75 x 35) + (25 x 37) = 3550
3550/100
Average Mass of one atom = 35.5

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5
Q

RFM

A

Relative formula mass/Mr

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6
Q

RFM is the … Of compounds can be measured on the same … Scale as elements

A

Masses

Carbon-12

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7
Q

To calculate the RFM of a compound, the RAM of the individual elements are added together eg for H2O

A

Mr = (2 x H) + (1 x O)
(2 x 1) + (1 x 16)
Mr = 18

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8
Q

Volume of gas equation

A

Volume = moles x 24

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9
Q

Empirical formula is the … Ratio of the atoms in a compound eg hydrogen peroxide H2O2

A

Simplest

HO

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10
Q

The empirical formula can be calculated from the mass of each element in a compound there are three stages to this process:

A

1) determination of mads or percentage of elements
2) divide the given mass or percentage by their RAM
3) calculate the ratio of atoms by dividing by the smallest value

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11
Q

Find empirical formula for calcium bromide

A

Ca 20%/40(RAM) Br 80%/80(RAM)
Ca 0.5/0.5 Br 1/0.5
= 1 : 2
= CaBr2

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12
Q

Equation for mass of a mole

A

Mass = Mr x moles

Can be rearranged

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13
Q

Find the mass of two moles of air

A

[(78 x 28) + (22 x 32) /100] x 2 = 57.76g

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14
Q

Find the mass of 1 mole of lead (II) nitrate Pb(NO3)2

A

207 + (2 x14) + (6 x 16) = 331g

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15
Q

Find the molecular formula from the empirical formula of CH2

A

CH2 has a Mr of 14 (RAMs H=1; C=12)
All you need to find out is how many times 14 goes into eg 56. 56/14=4 so all you need is 4 lots of CH2. Finally the molecular formula is C4H8

16
Q
Reacting masses (the 4 steps)
What mass of ammonium nitrate fertiliser can be made from 18.9g of nitric acid
A

1) calculate the Mr of known substance (HNO3) Mr = 1.0 + 14.0 + (3 x 16.0) = 63.0
2) calculate the number of moles of known substance (HNO3)
3) calculate the number of moles required substance required substance (NH4NO3) from equation
4) calculate mass of required substance (NH4NO3) Mr= 80, mass= 0.30 x 80.0 = 24g

17
Q

Work out the percentage yield when 10g of ‘a’ would give 12.5g of product but you would only get 11.2g

A

(11.2/12.5) x 100 = 89.6%