Module 3 - Hydraulic Calculations Flashcards

1
Q

Four Principles of Friction Loss

A
  1. Varies directly with the length of the hose (double the length = double the friction loss)
  2. Varies with the square of the velocity (flow) – if we double the flow we will have 4x the FL
  3. For a given flow, FL varies inversely as the 5th power of the hose diameter
    655 /445 = 7
    - For the same flow a 44mm hose will have 7x more FL than the 65
  4. Is dependent on flow and does not change with different pressure
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2
Q

Basic Friction Loss Calculation

A

FL/L = (Q/100)^2 x C

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3
Q

FL/L = (Q/100)^2 x C

A

FL/L = FL per length in 30m lengths

Q = quantity of water flowing in L/M

C = coefficient of friction of a given hose

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4
Q

Coefficients

A

44mm = 6
65mm = 0.8
77mm = 0.4
125mm = 0.03

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5
Q

Determining Friction loss

A

Two ways: actual test and calculations

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6
Q

Hydraulic Calculation Pump Discharge Pressure

A

PDP = NP + TFL + APP +/- ELEV

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7
Q

PDP = NP + TFL + APP +/- ELEV

A

PDP – Pump discharge pressure
NP - nozzle pressure
TFL – total friction loss
APP – appliance pressure loss
ELEV – elevation pressure gain or loss

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8
Q

Nozzle Pressure

A

solid bore handline – 350 kPa
Fog nozzle handline – 700 kPa
Master stream – 550 kPa

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9
Q

Total Friction loss – different sized lines

A

TFL = FLa + FLb

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10
Q

Appliance Friction Loss

A

We consider flow under 1400 lpm to be negligible and consider it to be zero

Flows of 1400 lpm and above simply add 70 kPa to our PDP

Excluding master stream devices

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11
Q

Elevation Equation

A

Pressure in a column of water is calculated at 10 kPa per meter of elevation

When there is a rise in elevation we need to add to our discharge

When there is a drop in elevation we need to subtract from the discharge pressure

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12
Q

Elevation Change

A

Commonly found at high rise events

Every floor is 4m – add 40 kPa/floor above ground

We count from the second floor up to the fire floor because we are level with the first floor when pumping

Residential = 3.5m, commercial = 4m

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13
Q

Net Pump Discharge Pressure (NPDP)

A

Centrifugal pumps can take advantage of incoming water pressure to increase pumping efficiency

If an engine is required to discharge 1000kPa and it has an intake pressure of 350kPa, the pump only needs to add 650kPa more to meet the demand

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14
Q

Nozzle Calculations

A

Not performed on the fire ground

Too low – limits the flow to less than critical application rate

Too high – may result in unreasonable nozzle reaction

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15
Q

Nozzle Flow (Solid Bore)

A

L/Min = 0.067 x D^2 NP

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16
Q

Bore Sizes

A

44mm handline – 24mm
65mm handline – 29mm
Blitzfire solid bore tips – 24mm, 32mm, 38mm

17
Q

Nozzle Reaction

A

NR = 0.0015 x D^2 x NP

18
Q

Configurations of connecting to Hydrants

A

Single
Twin
Single relay
Twin relay
Two hydrant supply

19
Q

Single

A
20
Q

Twin

A
21
Q

Single relay

A
22
Q

Twin Relay

A
23
Q

Two hydrant supply

A
24
Q

Limiting Factors and Solutions

A

Available water flow from the hydrant/main

The pressure hydrant has to push the water down the supply hose to the truck

Friction loss created by the hose lay supplying the truck

25
Q

Available water flow from the hydrant/main

A

Use 125 port as well as a 65 port with a 65 to 125 adapter

Use a second hydrant

26
Q

The pressure hydrant has to push the water down the supply hose to the truck

A

Relay supply engine helps maximize the water to the attack engine

27
Q

Friction loss created by the hose lay supplying the truck

A

Can be reduced by twinning the supply lines directly from the hydrant or in a relay

28
Q

*When using a second hydrant, the attack engine compound gauge

A

must not exceed the original static pressure to prevent pumping back into the water supply*

29
Q

Hydrant Flow depends on: (S.L.I.P)

A
  • Size
  • Length
  • Internal condition
  • Pressure of the water main
30
Q

*City of Calgary water services considers hydrant flow of ___________ as a minimum

A

5000 lpm as a minimum

31
Q

High rise events

A

have a standard of 150kpa friction loss and must be added to the calculations

32
Q

relay operations

A

boost the pressure to a maximum of 1260 kpa from the supply engine

33
Q

Max forward lay

A

of lengths = (discharge-safety) / FL/L

34
Q

twinning from a single hydrant will increase the flow by

A

approx. 30%

35
Q

using two hydrants will yield higher flow than twinning from 1 hydrant

A

approx. double

useful in areas with low flowing hydrants

36
Q
A