Module 14 Flashcards
Oxidation Numbers
Ex) In H2O, O is in oxidation state -2. O controls 2 more valence electrons than it usually does in pure oxygen
- Other hand - H iin H2O has oxidation state +1. H controls 1 fewer valence electrons than in pure hydrogen
Assigning Oxidation State
- Determine if atom is an atomic ion. If so, oxidation state is equal to its charge
- If atom is in a molecule made of its same type of element, then oxidation state is 0.
- If an atom of certain main group element, it might prefer a particular oxidation state
- Atoms in a molecule or polyatomic ion all add up to total charge. Ex) all atoms’ oxidations states in CO3^2- must add up to -2. C = +4, and 3O = 3(-2). +4 -6 = -2
Bronsted Lowry Base
accepts proton
Bronsted Lowry Acid
gives proton
Oxidation
Loss of Electrons
Reduction
Gain of Electrons
LEO means GER
Zn^2 + I^1- -> ZnI2
Zn loses 2 electrons to form Zn^2+ cations, while I must gain 1 electron to form 1^- anions.
Zn is oxidized, I is reduced
Reducing agent
contains atom being oxidized
Oxidizing agent
contains atom being reduced
Acid double displacement reaction that evolve to gas
- Carbonates + acid = salt (carbonate cation + acid anion) + CO2 gas + water
- Sulitfe(SO3^2-) + acids = salt (ssulfite cation + acid anion) + SO2 gas + H2O
- Sulfides + acids = salt (ssulfide cation + acid anion) + H2S gas + H2O
Calculating pH of strong acid soln
- Write the reaction
- As it’s a strong acid, ALL acid will react
3.Calculate initial moles of acid - Calculate moles of H3O produced (1 mol H3O for every 1 mol HA)
5.Calculate molarity of H3O+ - Calculate pH = - log[concentration of H3O]
- The amt of sig figs is the # of decimal places in final answer
Writing Half Reaction
e^- is symbol for electron
Ex)
Na(s) -> Na^+ (aq) + e^- (oxidation half reaction)
-electrons REMOVED
I2(s) + 2e^- -> 2I^- (aq) (reduction half reaction)
- electrons ADDED
When looking at possible reactions
the metal that is placed higher in the activity series can replace (‘reduce’ was used in this specific case) the other
Finding volume of base to titrate given mass of acid
- Find moles of acid
- Find mol of OH needed (1 mol OH for every H)
- Divide mol of Oh by Molarity of base soln to get volume of base soln in Liters
Finding molarity of base soln
- find molar mass of acid
- find moles of OH used for every mol of acid (1 OH for every H)
3.Divide by moles of OH by liters of OH used
Finding molar mass of monoprotic acid w/ base titrations
- Find mol of base - multiply volume of base w/ Molarity
- Multiply w/ ratio (mol of H / mol of base)
- Divide mass of monoprotic acid w/ moles to get molar mass
Solving limiting reactant problems in precipitating solutions
- Write reaction.
- Identify important species (AKA reactants that make up precipitate)
*Note: precipitation reactions run to completion
**HOWEVER If target reactant is NOT a reactant of precipitate, just find the moles of it straight from the given moles - Find the limiting reactant
- After finding the limiting reactant, use the mole ratio to find how many moles of target reactant is left over.