M7 Topic 3 Part 2: The photoelectric effect Flashcards
what is the photoelectric effect
the spontaneous emission of electrons from a metallic surface when EM Radiation is incident upon it
when and who discovered the photoelectric effect
Hertz fist observed the effect in 1887: spark gap in his radio wave experiment
how many electrons does 1 photon liberate (if it has enough energy)
1 electron
what happens during the photoelectric effect (2)
- photons with enough energy to overcome the work function are incident on the metal surface releasing a electron
- The electron absorbs the photons energy, allowing it to overcome the attraction holding them to the metallic structure
what is the work function
the minimum amount of energy required to liberate an electron from the metals structure
what determines the size of the work function
how closely bound the electrons are to the different metals structures
what is the photoelectric equation
Φ = hf₀
what does each symbol in the photoelectric effect represent (3)
Φ = the work function of the metal (Joules or electron volt (J or eV))
h = Plank’s constant (6.63 x 10⁻³⁴J or 4.14 x 10⁻¹⁵eV)
f₀ =the threshold frequency for the metal (hertz (Hz))
what happens if the photon has less energy than the work function
no electrons will be emitted
what happens if the photon has energy equal to the work function
electrons will be emitted but have no kinetic energy and remain on the metal surface
what happens if the photon has more energy than the work function
the electron will be emitted and the additional energy will transform into kinetic energy for the electron
what is the equation to calculate the kinetic energy of the electron
kₘₐₓ = hf - Φ
what do the symbols represent in the kinetic energy of a photon equation, and what units are they measured in (4)
kₘₐₓ = the maximum kinetic energy of an emitted photoelectron (Joules or electron volts J or eV)) h = Plank's constant (6.63 x 10³⁴J or 4.14 x 10⁻¹⁵eV) f = the frequency of the incident photon (hertz (Hz)) Φ = the work function of the metal ( Joules or electron volts J or eV))
How do you calculate kinetic energy in the photoelectric effect in a electric field experiment
by measuring the voltage generating the electric field, as the work done by the electric field must be equal to the kinetic energy
what does the y intercept represent in the photoelectric effect in a electric field experiment graph
the work function (Φ)
what does the x intercept represent in the photoelectric effect in a electric field experiment graph
the threshold frequency (f₀)
what does the gradient represent in the photoelectric effect in a electric field experiment graph
Planck’s constant (h)
what observation where made about the photoelectric effect (2)
- Intensity only increases the number of electrons not their energy
- Electrons are emitted instantaneously
what predictions did classical physicist make about the photoelectric effect (3)
- The higher the brightness (intensity) of the incident light, the greater the energy of electrons, emitted from the surface.
- light waves of any frequency should be able to liberate electrons, provided a reasonable intensity is maintained.
- If the incident light is of low intensity, the metal surface must be continuously exposed for some time until enough waves strike the surface to knock off electrons.
What were the experimental results of the photoelectric effect (3)
- The energy of the knocked-off electrons does not depend on the intensity of incident light.
- Electrons are not knocked off the surface unless the frequency of the incident light wave is more than a critical value (threshold frequency).
- Electrons appear as soon as light falls on the metal surface.
How did einstein explain this the experimental results of the photoelectric effect
he used Planck’s quanta model for light which showed light as particles called quanta or photons which carried energy that could be transferred to matter
How did Einstein use Planck’s quanta model for light (5)
he proposed the following assumptions:
- As light existed as photons. The energy of each photon represented as E=hf;
- Light intensity depends on the number of photons (the more photons, the greater the intensity of light);
- Photons with the highest energy correspond to light of the highest frequency;
- To produce the photoelectric effect, when an electron is liberated from a metal, energy is required to overcome the forces holding the electron to the surface, the work function;
- If the energy of the photon is greater than the work function, the additional energy in the photon will provide kinetic energy to the photoelectrons.