Lecture 6 - Solow Growth Model Flashcards

1
Q

The Solow growth model builds on the production model by adding a theory of …?

A

capital accumulation

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2
Q

In the Solow growth model, is capital stock exogenous or endogenous?

A

endogenous

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3
Q

List 4 differences between the Solow model and the basic classical model

A
  • supply of K is no longer fixed (investment causes it to grow, depreciation causes it to shrink)
  • supply of L is no longer fixed (population growth causes it to grow)
  • no G or T in the Solow model
  • Model is dynamic (production model is static)
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4
Q

List 4 assumptions of the neoclassical growth model, in terms of firms’ behaviour, the type of output, technology/production, and if production factors change over time?

A
  • competitive firms maximise profit
  • produce homogenous output (Y) using Neoclassical production function
  • technology/productivity assumed exogenous
  • production factors (K, L) may grow over time
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5
Q

List 3 assumptions of the basic Neoclassical growth model, in relation to labour and productivity

A
  • the population is the same as the labour force
  • labour is assumed to be fixed in supply, L = L̅
  • assume that productivity does not change over time, and that 1 = A̅
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6
Q

Derive: y = f(k) where f(k) = F(k,1), let L̅ mean L is fixed

A
  • in aggregate terms: Y = F(K,L̅)
  • y = Y/L̅ = output per worker
  • k = K/L̅ = capital per worker
  • assume constant returns to scale: λY = F(λK, λL̅) for λ>0
  • pick λ = 1/L̅
  • Y/L̅ = F(K/L̅, 1)
  • y = F(k,1)
  • y = f(k) where f(k) = F(k, 1)
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7
Q

For a graph of y against k, would f(k) be concave or convex, why?

A
  • concave
  • as it exhibits diminishing MPK
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8
Q

What is the national income identity for the Solow model, in per worker terms? Why?

A
  • Y = C + I + G + NX
  • closed economy: NX = 0
  • no government: G = 0
  • Y = C + I
  • in per worker terms: (c = C/L, i = I/L)
  • y = c + i
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9
Q

What does s represent in this model?

A

s = the saving rate (the fraction of income that is saved)

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10
Q

Is s an exogenous or endogenous parameter?

A

s is an exogenous parameter

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11
Q

What is the consumption function?

A
  • c = (1 - s)y
  • (per worker)
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12
Q

What does saving per worker equal in this model?

A
  • saving (per worker) = y - c
  • = y - (1 - s)y
  • = sy
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13
Q

Show, using the equations formed, how investment = savings

A
  • y = c + i
  • c = y - i
  • c = (1 - s)y
  • y - i = (1 - s)y
  • i = sy (= sf(k))
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14
Q

What is the equation that links change in capital stock (Δk), investment (i), and depreciation (𝛿k)?

A
  • Δk = i - 𝛿k
  • as i = sf(k)
  • Δk = sf(k) - 𝛿k (fundamental equation of the Solow model)
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15
Q

Δk = sf(k) - 𝛿k determines the behaviour of capital over time, which in turn determines the behaviour of all the other endogenous variables because they all depend on k. For instance… (3 examples)

A
  • income per person: y = f(k)
  • consumption per person: c = (1 - s)f(k)
  • investment per person: i = sf(k)
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16
Q

What are the four equations for the Solow growth model?

A
  • y = f(k)
  • Δk = sf(k) - 𝛿k
  • y = c + i
  • i = sy
17
Q

What does 𝛿 represent?

A

𝛿 = the rate of depreciation

18
Q

What, in words, does 𝛿 mean?

A

the fraction of capital stock that wears out each period

19
Q

What does k* represent in the model?

A

the steady state capital stock per worker

20
Q

If investment is just enough to cover depreciation, then what will Δk equal? What is this situation called?

A
  • Δk = 0, capital per worker will remain constant
  • this constant value, denoted k*, is called the steady state capital stock per worker
21
Q

Graphically, where does the steady state (capital stock per worker) occur?

A

where the lines of 𝛿k and sf(k) intersect

22
Q

For a graph of depreciation against k, what type of line/curve is 𝛿k?

A

linear, through the origin (as 𝛿 is constant)

23
Q

As long as k < k*, ______ will exceed ______, and k will continue to grow toward ____

A

as long as k < k* , investment will exceed depreciation, and k will continue to grow toward k*

24
Q

Does the initial level of capital determine where it will end up?

A

no, it will always end up in the steady state (unless the initial level of capital is 0)