Lecture 15- Thermodynamics 1 Flashcards

1
Q

Thermodynamics

A
  • The relationship between chemical reactions and heat

- Temp= measure of thermal every and average KE of a sample

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2
Q

Heat vs. temp

A
  • Heat= a form of energy measured in Joules
  • Temperature= a measure of average KE of atoms and molecules in a system
  • 0K=no KE
  • When KE doubles, K temp doubles
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3
Q

Boltzmann Distribution and Temperature

A
  • The greater distribution of KE of particles becomes more dispersed as temp increases and the average KE of particles in a system increases and temp increases
  • Lower temp=smaller distribution of particles
  • higher temp= wider distribution of particles
  • Distribution of KE increases as temp increases
  • Average KE of the particles in a system increases as temp increases
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4
Q

Energy transfer between systems

A
  • two systems at different temperatures that are in thermal contact with one another will exchange energy (heat)
  • The energy transferred from system 1 is equal to the energy transferred to system 2
  • shorter arrows= lower KE and V
  • Longer arrows= higher KE and V
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5
Q

system and surrounding

A
  • system- the actual chemical reaction that is taking place

- surrounding- the entire universe outside of the chemical reaction

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6
Q

change in a system’s internal energy

A
  • ^E=q+w
  • E= change in the PE and KE of the particles in a system
  • q= heat that is transferred into (+value) or out of (-value) the system
  • w= work done on the system by the surroundings (+ as energy flows into the system) or work done on the surrounding by the system (- value as energy flows out of the system)
  • Work results from changes in the volume of a gas
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7
Q

Heat and endothermic process

A
  • pe+KE=PE+ke
  • bonds in the products contain more PE, the product molecules contain less KE
  • Products of an endothermic reaction are at a lower temperature
  • heat flows from the surroundings into the system until thermal equilibrium is established
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8
Q

Heat and exothermic processes

A
  • ke+PE=KE+pe
  • as the bonds in the products contain less PE, the product molecules must contain more KE
  • This is why the products of an exothermic reaction are at a higher temperature
  • heat flows from the system into the surroundings until thermal equilibrium is established
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9
Q

Work and endothermic processes

A
  • If the pressure caused by gas particles colliding with the piston on the outside of the cylinder is greater than that inside the cylinder… the has outside does work on the piston, energy is transferred from the gas to the piston, and the has inside the cylinder contracts. Big to small
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10
Q

Work and exothermic process

A
  • if the pressure caused by gas particles colliding with the piston on the inside of the cylinder is greater than that outside the cylinder, the gas inside does work on the piston, energy is transferred from the gas to the piston, and the inside the cylinder expands. Small to big
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11
Q

Transfer of energy through work

A
  • P=F/A
  • F=PA
  • w=F^d
  • w=P^V
  • w= -P^V***
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12
Q

Enthalpy of Reaction (^H)

A
  • the heat that is released or absorbed in a chemical reaction
  • g-l is exothermic
  • l-g is endothermic
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13
Q

Four methods for finding ^H

A
  1. average bond enthalpies
  2. Calorimeter
  3. Hess’s Law
  4. Enthalpies of formation
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14
Q

^H from average bond enthalpies

A

^H=sumBE(broken)-sumBE(formed)

    • is exothermic
    • is endothermic
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15
Q

relating to gas

A

w= -P^V

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16
Q

calculate the work associated with this contraction in joules

A
  • w= -P^V
  • gets you atmXL
  • multiply by 101.3J/IatmL
17
Q

J/AtmL

A

101.3J/1atmL

18
Q

+ - W

A

-W=exothermic since energy is being released from the system
+W= endothermic since energy is being put into the system
- same for ^E

19
Q

calculate the change in internal energy of the balloon

A
  • Use w= -P^V to find J

- Plug into ^E=q+w

20
Q

compare the sum of the bond enthalpies of reactants and the sum of the bond enthalpies of the products

A
  • Use ^H=Hp-Hr for both the reactants the products (but just add)
  • If sum of products is higher this means theres a higher KE and lower PE because its an exothermic reaction and more energy is released during the formation of bonds in the products that is required to break the bonds in the reactants and the products are at a lower PE than the reactants.
21
Q

determine enthalpy change ^Hrnx

A

^H=Hp-Hr

- elements are 0 since they don’t have bonds

22
Q

using average bond energies

A

^H=sumBE(broken)-sumBE(formed)

- reactants-products

23
Q

gas compressing

A
  • positive= gas compressing

- negative= gas expanding