Kinetics (4) Flashcards

Semester 1 year 1

1
Q

How do you calculate the rate from the Michaelis Menten equation when the substrate concentration is much greater than Km?

A

-denominator of [S] + Km ≈ [S]
-rate = (Vmax x [S]) / [S]
-rate = Vmax

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2
Q

How do you calculate the rate from the Michaelis Menten equation when the substrate concentration is much smaller than Km?

A

-denominator of [S] + Km ≈ Km
-rate = (Vmax x [S]) / Km
-rate = (Kcat / Km) x [E]total x [S]
-final equation from subbing in Vmax equation

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3
Q

What does the line look like on a graph when substrate concentration is much smaller than Km?

A

-linear
-the equation is the same as equation for straight line

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4
Q

What is Kcat / Km?

A

-second order rate constant describing reaction of E + S to give enzyme + product (includes both steps)
-it’s a specificity constant

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5
Q

What is the importance of Kcat / Km?

A

Only valid way of comparing enzymes with different substrates

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6
Q

How do you calculate the rate from the Michaelis Menten equation when the substrate concentration is equal to Km?

A

-denominator of [S] + Km = 2[S]
-rate = (Vmax x [S]) / 2[S]
-rate = 1/2 Vmax

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7
Q

What is Km?

A

The concentration of substrate that produces half the maximal rate

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8
Q

Why is a graph of rate against substrate concentration not normally used and what are the alternative representations?

A

-difficult to see what’s going on at low [S]
-use either log [S] or a double reciprocal plot

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9
Q

Describe a plot of rate against log [S]

A

-data points at low [S] more spread out
-harder to visualise Kcat / Km

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10
Q

Describe a double reciprocal plot

A

-plot 1/v against 1/[S]
-the line is straight
-gradient = Km / Vmax
-y intercept = 1/Vmax

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11
Q

What are competitive inhibitors?

A

-molecules that bind to the enzyme and prevent substrate binding
-often bind in active site

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12
Q

How do you overcome a competitive inhibitor and how does this effect Km and Kcat?

A

-need a higher [S] to compete against inhibitor so Km increases
-once substrate is in active site, it reacts as normal, so Kcat doesn’t change

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13
Q

On a double reciprocal plot, how does a line with a competitive inhibitor differ to the line without?

A

It has a shallower gradient

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14
Q

What are allosteric inhibitors?

A

-molecules that bind to the enzyme but not in the active site
-generally change the shape of active site

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15
Q

What do allosteric inhibitors affect?

A

-can affect binding + chemistry - both Km or Kcat can change
-can also activate, so change can be in either direction

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