Immuno 3 Flashcards
What is a B cell (B lymphocyte)?
a lymphocyte that is dedicated to making immunoglobulins and antibodies
the primary effector function of B cells is to produce antigen-specific antibodies
Antibodies are aka?
immunoglobulins
B cells (and T cells) are derived from what cells?
common lymphoid progenitor cells
Where are B cells produced? What happens after they are produced there?
B cells are produced in the bone marrow. They mature in the bone marrow, and then B cells emerge from the bone marrow as naïve B cells; these cells bear receptors on their surface (membrane bound antibody molecules; B cell receptor) that can potentially bind to a specific antigen. It is important to note that each of the immunoglobulins produced by any one B cell clonal line all have the same antigen-specificity.
What happens if B cell receptors bind to an appropriate antigen?
the B cell can be activated to proliferate (giving rise to many B cells that bear and produce immunoglobulins that are specific for the same antigen) and differentiate into either plasma cells or memory cells
What is the primary function of plasma cells?
a terminally differentiated B cell whose primary function is to produce antibodies.
Where do IgG producing plasma cells typically go?
migrate to bone marrow
Where do IgA producing plasma cells typically go?
IgA-producers migrate primarily to the lamina propria of mucosal surfaces
What do memory cells do?
a long-lived antigen-specific B cell that results from antigenic stimulation of a naïve B cell during the primary immune response. Upon subsequent exposure to specific antigen, these cells are reactivated to differentiate into plasma cells as a component of a secondary immune response
How many antigen specificities exist in the body?
there can be as many as 10^11 different antibody specificities generated by somatic recombination of immunoglobulin genes in any individual (perhaps more than 10^11)
Note on rearrangement of light and heavy chains.
This is an antigen-INdependent process.
A tremendous number of different Ab molecules (10^11), that differ only in their variable regions, are produced by each
individual. This diversity is needed for recognition of the countless antigens that are associated with potential pathogens. The tremendous diversity of possible antibody specificities results from a “cassette” system of gene segments that are somewhat randomly spliced together to form the genes that encode the variable regions of light and heavy chains of antibody molecules.
NOTE: there are two sets of gene segments that can be recombined to generate the coding regions for light chains (the kappa and lambda genes); only one of these will be successfully rearranged in any B cell.
What are the component of light chain genes?
variable (V) and joining (J) gene segments which are combined to create the variable region which is associated with a constant (C) region gene segment to form the complete light chain gene
What are the component of heavy chain genes?
How much variety of each of these components exist?
consist of V, D (diversity), and J gene segments which combine with the C region gene to form a complete heavy chain gene
there are approx. 38-46 V gene segments, 23 D genes, 6 J genes, and 9 C genes (one for each isotype (and subtype) of Ig)
Describe a lambda light chain gene organization.
there are approx. 29-33 Vλ gene segments (each preceded by a leader sequence),
followed 4-5 Jλgene segments; each of the Jλ gene segments is associated with a Cλ gene (codes for the constant
domain).
Can you draw this out? If not, refer to note set for diagram
Describe a kappa light chain gene organization.
there are approx. 31-36 Vκ gene segments (each preceded by a leader sequence),
followed by up to 5 Jκ gene segments in a row which are associated with a single Cκ gene segment (i.e. 1 Ck gene segment for the total 5 Jk segments, ratio 1:5)
Can you draw this out? If not, refer to note set for diagram
Describe a heavy chain gene organization.
there are approx. 38-46 VH gene segments (each preceded by a leader sequence),
followed by 23 DH gene segments, then 6 JH gene segments, and finally 9 CH segments
What are leader sequences used for?
it directs the proteins into the cells’ secretory pathway following translation
Overview of B cell proliferation.
Through a process known as somatic recombination, our immune system produces a B cell repertoire that has more than 10^11 distinct B cell receptor/antibody specificities. Each B cell expresses many identical copies of the B cell receptor on its surface. When one of the millions of B cells becomes activated during an infection, it divides rapidly (proliferates), resulting in clonal expansion and differentiation of that B cell specificity line. The antibodies produced by effector B cells, or plasma cells from that B cell line, then participate in inactivation/removal of the pathogen.
T or F. Somatic recombination is a random process that occurs continuously throughout the life of the host.
T. It does not occur in response to infection, and it is completely antigen- independent.
Describe somatic recombination of light chains.
occurs in germline DNA
light chain gene construction: the first step is the random rearrangement of a single V gene segment with a single J gene segment to form a continuous piece of DNA that encodes the entire variable region of the light chain (catalyzed by a RAG gene); During this, all of the DNA separating the two segments is removed from the germline DNA; Once the germline DNA has been rearranged successfully, transcription of the rearranged DNA results in the production of a primary RNA transcript. since a C gene segment adjacent to the J gene segment is separated from the VJ junction by non-coding (intronic) DNA sequence, RNA processing following transcription of the rearranged DNA brings the VJ junction together with the C gene segment to create the complete coding region for the light chain. The primary RNA transcript then undergoes splicing to generate the final mRNA. Once the mRNA has been produced, it serves as a template for translation to produce the light chain protein.
Describe somatic recombination of heavy chains.
occurs in germline DNA
heavy chain gene construction: the variable region of heavy chains are constructed from 3 gene segments (VH, DH, and JH); the first step is the random rearrangement of a single DH gene segment with a single JH gene segment to form a DJH junction, removing all DNA operating them; the second step is a random rearrangement of a single VH gene segment with the previously joined DJH sequence to form a complete DNA sequence that encodes the variable domain of the heavy chain (VDJH); as in the light chain, the C gene segment (always Cμ) adjacent to the J gene segment is separated from the VDJH junction by non- coding (intronic) DNA sequence; RNA processing following transcription of the rearranged DNA brings the VDJ junction together with the Cμ gene segment to create the complete coding region for the heavy chain.
The mRNA then serves as a template for translation to produce the heavy chain protein. Each heavy chain protein becomes disulfide-bridged to a single copy of the light chain that is produced by that B cell, and two copies of the heavy-light chain combination are disulfide bridged together to create a complete monomeric copy of the antibody that is produced by this B cell. In all cases, this antibody is of the IgM isotype.
Somatic recombination is mediated by which genes?
two recombination activation genes, or RAG genes: RAG-1 and RAG-2. People that have a deficiency that affects the function of one or both of these gene products experience extreme clinically susceptibility to virtually all pathogens.
T or F. The sequences that flank the V, D, and J gene sequences all have highly conserved motifs
T
The flanking sequences of the V regions of heavy and light chain gene segments are composed of what?
A conserved block of 7 nucleotides (the heptamer 5’-CACAGTG-3’) followed by a
spacer that is either 12 or 23 nucleotides long (no conservation of sequence, just length; corresponds to either 1 or two turns of the DNA double helix), and followed by a second conserved block of 9 nucleotides (the nonamer 5’- ACAAAAACC-3’)
What is the significance of the length of the spacer between the gene segments of the V region of light and heavy chains?
the length of the spacers ensure that the heptameter and nonomer are on the same side of the DNA double helix, where they can be bound by the protein complex that catalyzes recombination
VDJ recombination only occurs between gene segments on the same chromosome
VDJ recombination only occurs between a gene segment that is flanked by a 12-mer RSS and a gene segment that is flanked
by a 23-mer RSS (the 12/23 rule)
the heptamer-spacer, nonuser motifs are called?
RSSs, recombination signal sequences
What is the basis of junctional diversity on heavy chain recombination?
the joining of the heavy chain gene segments is not precise, and consequently generates added diversity of the recombined V region coding sequence
- Rag complex cleaves the heptameter RSSs from the D and J gene segments to yield DNA hairpins
- RAG complex opens the hairpins on the D and J by nicking one strand of the DNA, generating palindromic P-nucleotides
- N-nucleotide additions by TdT
- Pairing of strands, removal of unpaired bases by an exonuclease, and gaps filled in by DNA synthesis
What chromosome are the lambda light chain genes found on?
22
What chromosome are the kappa light chain genes found on?
2
What chromosome are the heavy chain genes found on?
14