Genetics Linkage and Mapping Flashcards
1
Q
linkage group
A
- genes located on the same chromosome belong to the same linkage group
2
Q
double crossover
A
- two crossovers
- smaller part of chromosome is switched (compared to with single crossover
- could rearrange dominant/recessive genes
3
Q
crossover limit
A
- after 1 crossover, it is less likely that there will be another crossover
- closer to the centromere–> less likely for crossover to occur
4
Q
Genes not linked (1/3 cases of genes that happens with cross over)
A
- Homozygous dominant and homozygous recessive individuals (AABB X aabb)
- genes are not linked–> shows normal random assortment
- test cross get 1:1:1:1 ratio of phenotype
- AaBb, Aabb, aaBb, aabb
- 50% nonparental (in dihybrid test cross w/ genes not linked)
5
Q
Genes completely linked (2/3 cases of genes that happens with cross over)
A
- do not show independent assortment
- do not crossover
- do not show genetic recombination
- Homozygous dominant and homozygous recessive individuals (AABB X aabb)
- A and B stick together–> not independently assorted (because they are physically close to each other
- test cross–> only get 2 phenotypes in 1:1 ratio (AABB, aabb)
- 2 offspring resemble parents–> 0 nonparental types
6
Q
Linked genes, with some distance between (3/3 cases of genes that happens with cross over)
A
- shows genetic recombination
- Homozygous dominant and homozygous recessive individuals (AABB X aabb)
- test cross–> 4 phenotypes in 9:9:1:1 ratio
- AaBa, aabb, Aabb, aaBb
- same offspring as when genes are not linked, but different ratio
- we get this ratio since this crossover happens rarely
- this ratio tells us that the genes are on the SAME chromosome, and they are genetically linked, they do NOT show independent assortment
7
Q
Parental types
A
- the parents that the offspring resemble
8
Q
recombinance
A
- breaking and rejoining DNA (crossing over)
- the farther apart the genes, genes are, the bigger the number for recombination percentage
- Farther apart, more likely to have nonparental types
9
Q
map unit
A
- relative distance between genes
- mapping- used to figure out where genes are on chromosomes
10
Q
trihybrid test cross
A
- result expected is 1:1:1:1:1:1:1:1 (8 different phenotypes all with equal distribution if genes are unlinked)
- parental types- highest number of offspring
- lowest numbers–> double crossover
11
Q
Chi square test
A
- Goodness of fit test
- Determining if idea of pattern inheritance you are seeing is correct or not
- TABLE: Classes, observed numbers, expected numbers (add up and divide by 4), deviation (difference between observed and expected)- should add up to 0, take deviation and square it, then take deviation square and divide by expected
- Chi squared number is the sum of the deviation^2/expected
- Degrees of freedom = The number of classes – 1