EXPERIMENT 2 Flashcards

1
Q

molisch’s test

A

P: dehydration of carbohydrate by
sulfuric acid producing an aldehyde
• pentose → furfural
• hexose → hydroxymethylfurfural
• these aldehyde products
condense with α-naphthol to form
a purple product

• Molisch’s reagent: α-naphthol
dissolved in ethanol; + H2SO4

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2
Q

FEHLING’S TEST

A

P: cupric oxide is reduced by the
aldehyde portion of an aldose forming
a carboxylic acid and cuprous oxide
(aldehyde oxidizes to RCOOH)

Experimental Correlation:
• glu, xyl, fru, lac, mal: (+); reducing sugars
• suc: (-); non-reducing sugar

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3
Q

BENEDICT’S TEST

A

P: Benedict’s reagent contains blue
copper(II) ions (Cu2+) which are
reduced to copper(I) (Cu+). These are
precipitated as red copper(I) oxide
which is insoluble in water

• A&R:
• reducing sugar: orange - brick red
precipitate
• non-reducing sugar: absence of
orange – brick red precipitate

Experimental Correlation:
• all samples (yield positive result except
sucrose
• Sucrose can produce a positive result if
heated with dilute HCl prior to the test.
• The acidic conditions and heat break
the glycosidic bond in sucrose through
hydrolysis releasing glucose and
fructose (which are reductants).

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4
Q

clinical correlation of Benedict’s test

A

• tests reducing sugars in urine
• presumptive test for diabetes mellitus
• requires specific tests for glucose
(indicative of DM)

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5
Q

BARFOED’S TEST

A

• P: reduction of copper(II) acetate to
copper(I) oxide (Cu2O), which forms a
brick-red precipitate
• A: tests reducing monosaccharides
• disaccharides may also react, but the
reaction is much slower (heating for >2
min causes hydrolysis of glycosidic
linkage resulting to monosaccharides)
• a number of other substances,
(including NaCl), may interfere

• similar to Benedict’s test but lower in
pH and shorter heating time

Experimental Correlation:
• monosaccharides (+): glu, fru, xyl
• disaccharides (-): lac, mal, suc

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6
Q

NYLANDER’S TEST

A

• P: bismuth hydroxide is reduced to
black metallic bismuth
• mixture will darken if reducing sugar is
present and a black precipitate forms
after long standing

Experimental Correlation:
• all samples (glu, fru, xyl, lac, mal) yield
positive result

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7
Q

TOLLEN’S TEST

A

P: the diaminesilver(I) complex is an
oxidizing agent which in the presence
of the aldehyde of a sugar, is reduced
to silver metal, and further which in a
clean glass reaction vessel forms a
“silver mirror”.
• the aldehyde is oxidized to carboxylic
acids

Experimental Correlation:
• all samples yield positive result

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8
Q
  • detection for ketoses
    Principle:
  • ketohexoses (fructose) and
    disaccharides with ketohexoses (sucrose)
  • cherry red condensation product
  • other sugars ( aldoses)
  • yellow to faint pink color
A

SELIWANOFFS TEST

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9
Q
  • Detection for pentoses
    • Principle
    – Pentoses are converted to furfural by this
    reagent, which forms a blue green color with
    orcinol

– A blue-green color indicates a positive result.
Prolonged heating of some hexoses yields
hydroxymethyl furfural which also reacts with
orcinol to give colored complexes

A

BIAL’S ORCINOL TEST

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10
Q

IODINE TEST

A

• PRINCIPLE
• The amylose, or straight chain portion of starch, forms
helices where iodine molecules assemble, forming a
dark blue/black color.
• The amylopectin, or branched portion of starch, forms
much shorter helices and iodine molecules are unable to
assemble, leading the colour to be of an orange/yellow
hue. As starch is broken down or hydrolyzed into smaller
carbohydrate units, the blue-black color is not produced.

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11
Q

IODINE TEST

A
  • formation of deep blue –
    black color
  • presence of starch
  • dark blue-black color –
    starch and glucose
  • brown to blue – glycogen
  • yellow or clear color –
    negative test
  • (amylose +; amylopectin -)
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12
Q

• PRINCIPLE
• Starch – long chain glucose monomer, a polysaccharide
–poor solubility in solvents
• Glycogen is a branched polymer of glucose, and like
glucose, it has several hydroxyl groups per monomer. As
a result, it has lots of opportunities for hydrogen bonding
with water.
• Alcohols are non-polar and are equally charged on all
sides. The charged ends of the sucrose have nothing to
be attracted to other SUCROSE molecules,
therefore they will not dissolve.

A

ALCOHOL TEST

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