Exam 3 Reactions Flashcards
Dehydrohalogenation SM
alkyl halide
usually 3°, or 2° with stronger conditions
E1 DEHYDROHALOGENATION MECHANISM
- halogen leaves
- C+ rearrangement
- weak base deprotonates beta H; H e- make alkene
E1 dehydrohalogenation solvent
good ionizers - water, alcohol
E1 dehydrohalogenation rate law
rate = k[RX]
base used in E1 dehydrohalogenation
small or bulky?
weak
small yields Zaitsev product
bulky yields Hofmann product
E1 dehydrohalogenation byproducts
Sn1
how to favor E1 over Sn1?
heat
E2 dehydrohalogenation SM configuration requirement
anticoplanar
if cyclohexane, X and H must both be axial
E2 dehydrohalogenation SM
alkyl halide
usually 2° or 3°
E2 dehydrohalogenation rate law
rate = k[RX][B]
best base characteristics for E2 dehydrohalogenation
- strong
- nonpolarizable
- matched with solvent
- small (for Zaitsev product)
- large (for Hofmann product)
how to favor E2 dehydrohalogenation over Sn2
- polar protic solvent
- heat
E2 dehydrohalogenation stereospecificity
2 “wedges” end up one one side of alkene (longways)
Dehydration of alcohol SM
an alcohol
E1 DEHYDRATION MECHANISM
- hydroxy attacks H of acid to make a good LG
- C-O bond breaks and water leaves
- C+ rearrangement
- water attacks & removes beta H - H e- form alkene
E1 dehydration SM and acid
2° and 3° alcohol required
phosphoric/sulfuric acid
E2 DEHYDRATION MECHANISM
- acid attacks hydroxy to make good LG
- water leaves, and water attacks beta H - H e- make alkene
E2 dehydration SM & acid
1° alcohol
concentrated H2SO4
Hydrohalogenation SM
alkene
HYDROHALOGENATION MECHANISM
- alkene attacks H (or other electrophile), splitting it from X
- C+ rearrangement
- X attacks C+
hydrohalogenation product
alkyl halide
pair of enantiomers
hydrohalogenation variation
organic peroxide rxn
HBr
RO-OR solvent
radical mechanism
hydrohalogenation of alkynes SM and their products
terminal alkyne yields vinyl halides or geminal dihalides (depends on molar ratio)
internal alkyne yields 4 products, no Markovnikov application
HX addition to alkynes
1HX:1SM =
vinyl halide alkene
HX addition to alkynes
2HX:1SM =
geminal dihalide alkane
ACIDIC WATER HYDRATION MECHANISM
- alkene attacks H of acid
- C+ rearrangement
- water attacks C+, giving protonated alcohol
- another water deprotonates alcohol & regenerates acid
OXYMERCURATION-DEMERCURATION HYDRATION MECHANISM
- oxymercuration—alkene attacks Hg, Hg attacks C, forming mercurinium ion ring
- water attacks more stable partial + C, and Hg moves to the other C
- another water deprotonates alcohol, forming organomercurial alcohol
- demercuration—addition of NaBH4 drives SN2-type reaction, where Hg is replaced with H
why is mercuration used?
to get a non-rearranged hydrated product
species involved in oxymercuration-demercuration
- SM: alkene
- Hg(OAc)2
- THF-H2O solvent
- NaBH4 hydride
- product: non-rearranged alcohol
How is alkyoxymercuration different from oxymercuration? (2)
- Hg(O2CCF3) is used
- OR is attached to product, not OH; results in ether, not alcohol
Mercuric ion-catalyzed hydration of alkyne product
ketone
MERCURIC HYDRATION OF ALKYNE MECHANISM
- alkyne attacks Hg; mercury attaches to less sub. C
- water attacks C+, forming orthomercurial alcohol
- another water deprotonates water, giving alcohol
- alkene attacks proton from acid; Hg is replaced by H
- keto-enol tautomerization occurs
type of Hg salts used in mercuric hydration of alkynes
Hg (II) - HgO, HgSO4, Hg(OAc)2
hydroboration TS
4-membered ring, with Boron aligned with less sub. C
stereoselectivity of hydroboration
syn - H and Boron add to same face of alkene
Boron adds to less hindered face
if both faces are equally hindered, 2 products result
species involved in hydroboration of alkenes
- BH3 (or B2H6 dimer) - THF
- H2O2, OH-
boron reagent used in hydroboration of alkynes
Sia2BH
rearrangement involved with hydroboration of alkynes
enol-aldehyde tautomerization
HALOGENATION OF ALKENE MECHANISM
- halonium ion formation—alkene attacks X, X-X bond polarizes, X- breaks away
- X- opens 3-membered ring with backside attack
type of X-X addition to alkenes
anti
produces PVC
halogenation of alkenes
halogenation of symmetrical trans substrate gives…
of asymmetrical substrate gives…
meso product
enantiomers
halogenation of cis substrate gives…
pair of enantiomers
halogenation solvent
CCl4
halogenation of alkynes occurs in ________ conditions
anhydrous
halohydrin SM and product
SM: alkene
product: OH and X on alkane
halohydrin solvent
H2O
Nu and El for halohydrin formation
OH- is Nu
X+ is El
type of halohydrin addition
trans (anti)
HALOHYDRIN MECHANISM
- alkene attacks X-X, polarizing bond; X+ attacks one C; X- detaches
- water opens 3-membered ring from backside
- another water deprotonates alcohol
Halohydrin – is OH or X on more sub. C?
Markovnikov – OH is on more sub. C
2 variations of halohydrin formation
- ROH solvent gives ether, not OH
- salt in H2O gives mixed product, ex) Cl and Br on different products