E1 L8: Bioavailability and Clearance 3 Flashcards
FA
Fraction of drug absorbed
EG
Fraction of drug that is eliminated by intestinal metabolism during single pass; approx zero
Bioavailability (F) Equation
F = QH/(QH + fu * CLint)
Low EH drug
F = 1
CLH = Fu * CLint
High EH drug
F = QH/ (fu *CLint)
CLH =QH
Summary: Low EH (<0.3)
F is close to 1
F is not affected by changes in CLint, fu, or QH
CLH is affected by changes in CLint or fu
Summary: High EH (>0.7)
F is affected by changes in CLint, fu, or QH
CLH is proportional to QH
If a drug is 100% metabolized, then
CL = CLH
Q: T/F: Hepatic metabolism can be the major elimination route for a low EH drug (i.e. fe=0; or no renal excretion)
True
Q: T/F: After IV administration of drug X at 100 mg dose, you find 100% (i.e. 100mg) of drug X in the urine as metabolites. The fe of drug X is 1
False
Assuming 100% oral absorption, co-administration of an enzyme inducer with a low EH drug (drug X) would
Significantly increase CLH of Drug X
Assuming 100% oral absorption, co-administration of an enzyme inducer with a high EH drug(Drug Y) would:
A. Significantly increase F of Drug Y
B. Significantly decrease F of Drug Y
C. Significantly increase CLH of drug Y
D. Significantly decrease CLH of Drug Y
B. Significantly Decrease F of drug Y
Assuming 100% oral absorption and fe = 0, co-administration of an enzyme inducer with a high EH drug (Drug Y) would:
A. Significantly increase CL of Drug Y
B. Significantly increase CLpo of drug Y
C. Significantly increase F of Drug Y
D. Significantly increase AUCiv of Drug Y
B. Significantly increase CLpo of Drug Y