Differentation Rules Flashcards

1
Q

What is the shortcut for the Stokoe rule?

A
  1. Multiply the bracket by the derivative of the bracket and then the original power of the bracket. Then subtract one from the power of the bracket.

For Example:

y = (3x2+4)4

dy / dx = (4)(6x)(3x2+4)4-1

dy /dx = 24x(3x2+4)3

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2
Q

When is the product rule used?

A
  • When you have two brackets multiplied together.
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3
Q

When is the Quotient rule used?

A
  • When you have two expressions divided by each other, such as a fraction.
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4
Q

What check should be performed before using the product rule?

A
  • Check to see if the brackets can be easily multiplied, we often over complicate simple questions.
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5
Q

What is the product rule?

A
  • dy/dx = U (dv/dx) + V (du /dx)
  • Let u = one bracket.
  • Let v = the other bracket.
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6
Q

How is the Quotient rule used?

A
  • Let u = numerator.
  • Lev v = denominator.
  • Differentiate each component separately.
  • Substitute into the following equation:

dy / dx = V(du/dx) - U(dv/dx) / V 2

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7
Q

What does sin(x) differentiate to?

A
  • cos(x)
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8
Q

What does cos(X) differentiate to?

A
  • -sin(x)
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9
Q

What does tan(x) differentiate to?

A
  • Sec2(x)
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10
Q

What does ex differentiate to?

A
  • ex
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11
Q

What is the rule for differentiating ex?

A
  • You multiply the expression by the derivative of the power:

Example:

y = e4x

dy/dx = 4e 4x

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12
Q

What is the derivative of ln(X)?

A
  • 1/x
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13
Q

What is the rule for differentiating natural logs?

A
  • You need to use the stokoe rule.
  • Do 1 / expression, multiplied by the derivative of the expression.
  • This gives the simplified method that dy/dx of a log is equal to the derivative / original expression.

Example:

y = ln(3x2-1)

dy / dx = 1/3x2-1 x 6x

dy / dx = 6x/3x2-1

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14
Q

How would one differentiate parametric equations?

A
  • Differentiate each equation separately.
  • Apply the chain rule.

Example:

y = 4t3

x = 8t2

dy/dt = 12t2

dx/dt = 16t

dy/dx = dy/dt x dt/dx

dy/dx = 12t2 x 1/16t

dy/dx = 12t2/6t

dy/dx = 2t

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