Demo Formula Flashcards

1
Q

Internal Timber Charge (Six problem solving format)

A

1) find Diameter
2) P=D^2 / 250
3) RE
4) PKG weight
5) Total # of target
6) total quantity

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2
Q

Relieved Face Crater Formula (Six problem solving format)

A

1) width of hasty crater
2) Friendly: 40 lbs. Enemy: 30 lbs.
3) N/A
4) 40, 30 divided by Package weight
5) N= (L-10) / 7 +1
6) Friendly/Enemy totals per hole x # of holes = Total quantity of packages.

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3
Q

Abatis Timber Charge formula (Six problem solving format)

A

1) find Diameter
2) P=D^2 /50
3) RE
4) PKG weight
5) Total # of target
6) total quantity

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4
Q

Saddle Charge Dimensions

A

Thickness of charge: 1”
Base of Charge: 1/2 circumference of target
Long axis of charge: Circumference of target

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5
Q

Conventional steel round stock (Six problem solving format)

A

1) find Diameter
2) P=D^2
3) RE
4) PKG weight
5) Total # of target
6) total quantity

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6
Q

Conventional steel cutting charge formula (Six problem solving format)

A

1) Find total area
2) P = .375 x Area
3) RE
4) Pkg weight
5) Total # of target
6) total quantity

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7
Q

Counterforce charge formula (Six problem solving format)

A

1) find information
2) P= 1.5 x Br (Diameter)
3) N/A
4) PKG weight
5) Total # of target
6) Total quantity

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8
Q

which charge formula use package weights?

A

Counterforce, and Dirt Cratering charge

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9
Q

Hasty Crater Formula (Six problem solving format)

A

1) width of hasty crater
2) 50 lbs of explosive per hole
3) N/A
4) 50 divide by package weight
5) N = (L-16) / 5 +1 then round up
6) 50 x Number of holes = Total quantity of package

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10
Q

Deliberate Crater Formula (Six problem solving format)

A

1) width of hasty crater
2) 5’ hole 40lbs, 7’ hole 80lbs
3) N/A
4) 40, 80 lbs divide by package weight
5) N = (L-16) / 5 +1 then round up
6) 7 ft./5 ft. totals explosive per hole x # of holes = Total quantity of packages.

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11
Q

C-shaped Ribbon charge formula (Six problem solving format)

A

1) find CV for all component
2) Total CV
3) N/A
4) Volume of explosive
5) Total # of target
6) total quantity

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12
Q

Abatis Timber Charge considerations

A

Charges placed at 5’ above ground
diameter of tree should be 18” for wheel vehicle
diameter of tree should be 24” for track vehicle
3 to 5 meter apart 45 degree toward ENY

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13
Q

conventional breaching radius rules

A
External = thickness of target, rounds up to near 1/2 foot
Internal = 1/2 the thickness of target, rounds up to near 1/4 foot
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14
Q

Expedient explosives charge formula

A

1) find information
2) Vcyl-VC=EV
3) N/A
4) Volume of explosive
5) Total # of target
6) Total quantity

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15
Q

Ribbon charge formula (Six problem solving format)

A

1) thickness and wide (for wide always convert feet to inch)
2) CV= CT x CW x CL
* CT= 1/2 of thickness or 1/2”
* CW= 3 x CT
3) N/A
4) Volume of explosive
5) Total # of target
6) total quantity

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16
Q

Internal Timber Charge Holes and depth

A

Trees up to 18” diameter = 1 hole
Larger than 18” diameter = 2 hole
2 types of hole: Dimensional and Circular
2” Diameter and 2/3 deep in timber

17
Q

Diamond charge formula (Six problem solving format)

A

1) Find information
2) CV=B^2
3) N/A
4) volume of explosive
5) total # of target
6) total quantity

18
Q

Saddle charge formula (Six problem solving format)

A

1) Find information
2) CV=B^2
3) N/A
4) volume of explosive
5) total # of target
6) total quantity

19
Q

Railroad tracks calculation

A

Rails 5” or higher use 1lb of TNT
Rails Less than 5” use ½ lb of TNT
Crossover and switches 1lb of TNT
Frogs 2lbs of TNT

20
Q

External Timber Charge requirement

A

1”-2” thick, cover at least 1/2 circumference, 1lb kicker charge

21
Q

External/Ring Timber Charge (Six problem solving format)

A

1) find Diameter
2) P=D^2 /40
3) RE
4) PKG weight
5) Total # of target
6) total quantity

22
Q

Stump Removal measurement

A

measured at 12”-18” above ground level

diameter is rounded to next higher 1/2 foot

23
Q

which charge formula use RE factor and package weights?

A

Timber charge (Internal, External, and Abatis), Conventional Steel, conventional breaching

24
Q

conventional breaching formula (Six problem solving format)

A

1) find information
2) P= R^3 KC
3) RE
4) PKG weight
5) N= W/2R (Round off)
6) Total quantity

25
Q

which charge formula use volume?

A

advance steel, and expedient charge

26
Q

Stump removal charge formula (Six problem solving format)

A

1) Find diameter (convert to feet)
2) 1’ per explosive
3) N/a
4) PKG weight
5) Total # of target
6) Total quantity

27
Q

Ring Timber Charge thickness

A

1/2 inch thick up to 15” diameter
1 inch thick up to 30” diameter
explosive band should be as wide as possible