Demo Formula Flashcards

1
Q

Internal Timber Charge (Six problem solving format)

A

1) find Diameter
2) P=D^2 / 250
3) RE
4) PKG weight
5) Total # of target
6) total quantity

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2
Q

Relieved Face Crater Formula (Six problem solving format)

A

1) width of hasty crater
2) Friendly: 40 lbs. Enemy: 30 lbs.
3) N/A
4) 40, 30 divided by Package weight
5) N= (L-10) / 7 +1
6) Friendly/Enemy totals per hole x # of holes = Total quantity of packages.

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3
Q

Abatis Timber Charge formula (Six problem solving format)

A

1) find Diameter
2) P=D^2 /50
3) RE
4) PKG weight
5) Total # of target
6) total quantity

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4
Q

Saddle Charge Dimensions

A

Thickness of charge: 1”
Base of Charge: 1/2 circumference of target
Long axis of charge: Circumference of target

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5
Q

Conventional steel round stock (Six problem solving format)

A

1) find Diameter
2) P=D^2
3) RE
4) PKG weight
5) Total # of target
6) total quantity

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6
Q

Conventional steel cutting charge formula (Six problem solving format)

A

1) Find total area
2) P = .375 x Area
3) RE
4) Pkg weight
5) Total # of target
6) total quantity

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7
Q

Counterforce charge formula (Six problem solving format)

A

1) find information
2) P= 1.5 x Br (Diameter)
3) N/A
4) PKG weight
5) Total # of target
6) Total quantity

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8
Q

which charge formula use package weights?

A

Counterforce, and Dirt Cratering charge

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9
Q

Hasty Crater Formula (Six problem solving format)

A

1) width of hasty crater
2) 50 lbs of explosive per hole
3) N/A
4) 50 divide by package weight
5) N = (L-16) / 5 +1 then round up
6) 50 x Number of holes = Total quantity of package

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10
Q

Deliberate Crater Formula (Six problem solving format)

A

1) width of hasty crater
2) 5’ hole 40lbs, 7’ hole 80lbs
3) N/A
4) 40, 80 lbs divide by package weight
5) N = (L-16) / 5 +1 then round up
6) 7 ft./5 ft. totals explosive per hole x # of holes = Total quantity of packages.

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11
Q

C-shaped Ribbon charge formula (Six problem solving format)

A

1) find CV for all component
2) Total CV
3) N/A
4) Volume of explosive
5) Total # of target
6) total quantity

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12
Q

Abatis Timber Charge considerations

A

Charges placed at 5’ above ground
diameter of tree should be 18” for wheel vehicle
diameter of tree should be 24” for track vehicle
3 to 5 meter apart 45 degree toward ENY

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13
Q

conventional breaching radius rules

A
External = thickness of target, rounds up to near 1/2 foot
Internal = 1/2 the thickness of target, rounds up to near 1/4 foot
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14
Q

Expedient explosives charge formula

A

1) find information
2) Vcyl-VC=EV
3) N/A
4) Volume of explosive
5) Total # of target
6) Total quantity

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15
Q

Ribbon charge formula (Six problem solving format)

A

1) thickness and wide (for wide always convert feet to inch)
2) CV= CT x CW x CL
* CT= 1/2 of thickness or 1/2”
* CW= 3 x CT
3) N/A
4) Volume of explosive
5) Total # of target
6) total quantity

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16
Q

Internal Timber Charge Holes and depth

A

Trees up to 18” diameter = 1 hole
Larger than 18” diameter = 2 hole
2 types of hole: Dimensional and Circular
2” Diameter and 2/3 deep in timber

17
Q

Diamond charge formula (Six problem solving format)

A

1) Find information
2) CV=B^2
3) N/A
4) volume of explosive
5) total # of target
6) total quantity

18
Q

Saddle charge formula (Six problem solving format)

A

1) Find information
2) CV=B^2
3) N/A
4) volume of explosive
5) total # of target
6) total quantity

19
Q

Railroad tracks calculation

A

Rails 5” or higher use 1lb of TNT
Rails Less than 5” use ½ lb of TNT
Crossover and switches 1lb of TNT
Frogs 2lbs of TNT

20
Q

External Timber Charge requirement

A

1”-2” thick, cover at least 1/2 circumference, 1lb kicker charge

21
Q

External/Ring Timber Charge (Six problem solving format)

A

1) find Diameter
2) P=D^2 /40
3) RE
4) PKG weight
5) Total # of target
6) total quantity

22
Q

Stump Removal measurement

A

measured at 12”-18” above ground level

diameter is rounded to next higher 1/2 foot

23
Q

which charge formula use RE factor and package weights?

A

Timber charge (Internal, External, and Abatis), Conventional Steel, conventional breaching

24
Q

conventional breaching formula (Six problem solving format)

A

1) find information
2) P= R^3 KC
3) RE
4) PKG weight
5) N= W/2R (Round off)
6) Total quantity

25
which charge formula use volume?
advance steel, and expedient charge
26
Stump removal charge formula (Six problem solving format)
1) Find diameter (convert to feet) 2) 1' per explosive 3) N/a 4) PKG weight 5) Total # of target 6) Total quantity
27
Ring Timber Charge thickness
1/2 inch thick up to 15" diameter 1 inch thick up to 30" diameter explosive band should be as wide as possible