Chemical reactions Flashcards
Chemical reaction
- Process leading to transformation of one set of chemical substances to anther. - Reactants → Products - Same nr. of atoms before and after reaction. According to stoichiometry oxidation nr./state doesn't change. - Can be reversible. Proceed in both forward and backward direction. Tend towards a chemical equilibrium.
Chemical Equilibrium
- It is the point at which both the forward and the reverse reactions take place at the same rate. - Since the forward and reverse rates are equal, the concentrations of the reactants and products are constant at equilibrium.
Why is equilibrium referred to as dynamic equilibrium?
Because even though the concentrations are constant at equilibrium, the reaction is still happening.
Equilibrium constant
- We can define the equilibrium constant Kc of a reaction (fixed conditions of temperature and pressure) as: Kc: (C)^c (D)^d / (A)^a (B)^b - a, b, c and d: stoichiometric coefficients - [A], [B], [C] and [D]: equilibrium concentration of the chemical species - Pure solids and pure liquids, including solvents, are not included in the equilibrium expression.
Acid Base Reactions
Acid: Proton donor (deduction -) #→#- Base: Proton acceptor (adding +) #→#+ Conjugate base: product of the acid (#-) Conjugate acid: product of the base (#+) - In acidic molecules all the bonds are covalent. But the bond X – H is polar covalent and when the molecule is dissolved in water, this bond behaves as ionic, and the molecule dissociates into X- and H+
Amphoteric substance
Can act as both base and acid.
H2O
Strong acid
Ionize completely in aqueous solutions. No reverse reaction. HCI : Hydrochloric acid HBr : Hydrobromic acid HI: Hydroiodic acid H2SO4 : Sulfuric acid HNO3 : Nitric acid
Weak acid
Ionizes partially in aqueous solution. Forward and reverse reaction. We can calculate constant for acidity: Ka = (H+)(A-)/(AH) AH ↔ H+ + A- Big majority of acids, carboxylic acid. F.ex. CH3COOH: Acetic acid.
Strong Base
Ionize completely in water. No reverse reaction. NaOH KOH Ca(OH)2 Group 1A, 2A, hydroxide compounds.
Weak bases
Ionize partially in water. Reverse reaction. B (aq) + H2O ↔ BH+(aq) + OH-(aq) We can calculate constant of basicity: Kb = (BH+)(OH-) / (B) Water Conjugate bases of strong acids. neutral nitrogen containing compounds such as NH3, amines and pyridines.
Measuring acidity
pH = - log [H+] → [H+] = 10-pH pOH = - log [OH-] → [OH-] = 10-pOH - If pH increases, H+ decrease and vice versa. pKa = -Log Ka pKb = -Log Kb [H+] x [OH-] = 10^14 and pH + pOH = 14 Ka x Kb = 10^14 and pKa + pKb = 14
Buffer solutions
- A buffer is an aqueous solution that resists changes in pH upon the addition of an acid or a base. - A buffer solution contains: • a weak acid and a substantial amount of its conjugate base (from a soluble salt) • a weak base and a substantial amount of its conjugate acid (from a soluble salt)
Henderson – Hasselbach equation
The pH of any buffer is defined by this equation:
pH = pKa + log ([deprotonated] / [protonated]) ↔ 10^pH-pKa = [A-] / [AH]
Protonated: Molar concentration of acid/conjugated acid
Deprotonated: Molar concentration of base/conjugate base
Henderson – Hasselbach equation for an acid
HA + H2O ↔ H3O+ + A-
pH = pKa + log ([A-] / [HA])
Henderson – Hasselbach equation for a base
B + H2O ↔ BH+ + OH-
pOH = pKb + log ([BH+] / [B])
pH = pKa + log ([B] / [BH+])