Chapter 9 Flashcards
The reactant that limits the amount of the other reactant that can combine and the amount of product that can form in a chemical reaction.
Limiting Reactant
The volume occupied by one mole of a gas at STP.
Standard molar volume
Use the balanced chemical equation below to calculate the number of moles of carbon needed to react completely with 135 grams of iron(III) oxide.
2Fe2O3 + 3C –> 4Fe +3CO2
Use the molar mass of the first substance to convert to moles, then use the mole ratio from the coefficients to convert to moles of the other substance.
Using the balanced equation below, calculate the number of moles of hydrogen needed to react completely with 2.5 moles of nitrogen.
3H2 + N2 –> 2NH3
Use the mole ratio from the coefficients to convert from moles of one substance to moles of another substance.
Use the balanced reaction below to calculate the theoretical yield of tin(II) fluoride from 119g of tin and 43.0g of hydrogen fluoride. What is the limiting reactant?
Sn + 2HF –> SnF2 + H2
If the actual yield is 149g, what is the percent yield?
The smaller answer is the theoretical yield. The reactant that limits the amount of product is the limiting reactant.
Fill in each circle:
What volume would 0.68mol of ozone gas occupy at STP?
1 mole of any gas at STP occupies 22.4 liters at STP.
Using the balanced equation below, what mass of sodium peroxide would be needed to react completely with 5.0L of CO2, at STP?
2Na2O2(s) + 2CO2(g) –> 2Na2CO3(s) + O2(g)
Since at STP, use the standard molar volume to convert liters to moles. Then use the mole ratio from the coefficients to convert to moles of the second substance. Finally, use the molar mass of the second substance to convert to grams.
The values of standard temperature and standard temperature, respectively
0°C and 1 atmosphere
Fill in the information missing beside each line.
The substance that is not used up completely in a chemical reaction.
Excess Reactant
The maximum amount of product that can be produced from a given amount of reactant.
Theoretical yield
Use the balanced chemical equation below to calculate the mass in grams of sodium hypochlorite that could be produced from 0.50mol of NaOH, assuming an excess of chlorine:
2NaOH + Cl2 –> NaClO + NaCl + H2O
Convert from moles of the first substance to moles of the second substance using the mole ratio from the coefficients, then use the molar mass of the second substance to convert to grams.
A conversion factor that relates the amounts in moles of any two substances involved in a chemical reaction.
Mole Ratio
Use the balanced chemical equation below to calculate the mass in grams of chlorine needed to produce 17g of sodium chloride, assuming an excess of sodium hydroxide:
2NaOH + Cl2 –> NaClO + NaCl + H2O
Convert the mass of the first substance to moles using its molar mass. Then, convert from moles of the first substance to moles of the second substance using the mole ratio from the coefficients. Finally, convert to mass of the second substance using its molar mass.