Chapter 7 Group 2 Flashcards

1
Q

Introduction of Group 2

A
  • The Group 2 nitrates and carbonates become more thermally stable going down the group
  • The charge density of the cation (Group 2 metal ion) and the polarisationoftheanion (the nitrate and carbonate ion) attribute towards this increased stability
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2
Q

Trends in thermal stability going down the group

A
  • All Group 2 metals form 2+ ions as they lose two electrons from their valence shells
  • The metal cations at the top of the group are smaller in size than those at the bottom
  • The metal cations at the top of Group 2, therefore, have the greatest charge density as the same charge (2+) is packed into a smaller volume
  • As a result, smaller Group 2 ions have a greater polarising effect on neighbouring negative ions
  • When a carbonate or nitrate ion approaches the cation, it becomes polarised
    • This is because the metal cation draws the electrons in the carbonate or nitrate ion towards itself
  • The more polarised the anion is, the less heat is required to thermally decompose them
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3
Q

Therefore, the thermal stability increases down the group

A
  • As down the group, the cation becomes larger
  • Thus has a smaller charge density
  • And a smaller polarising effect on the carbonate or nitrate anion
  • So the anion is less polarised
  • Therefore, more heat is required to thermally decompose them
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4
Q

Trends in Solubility & Enthalpy Change of Solution of Group 2 Hydroxides & Sulfates

A
  • The solubility of Group 2 hydroxides increases down the group
  • In contrast, the Group 2 sulfates show a decrease in solubility going down the group
  • Compounds that have very low solubility are said to be sparingly soluble
    • For example, calcium sulfate (CaSO4) has low solubility as only 0.21 g of CaSO4 dissolves in 100 g of water
  • Most of the sulfates are soluble in warm water with the exception of barium sulfate which is insoluble
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5
Q

Solubility of Group 2 elements table

A
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6
Q

The Standard enthalpy of solution

A
  • (ΔHsol) is the energy absorbed or released when 1 mole of ionic solid dissolves in enough water to form a dilute solution (under standard conditions)
    • The ΔHsol can be either exothermic or endothermic
  • For example, the ΔHsol of sodium chloride (NaCl) is +3.9 kJ mol-1

NaCl (s) + aq → NaCl (aq)

OR

NaCl (s) + aq → Na+ (aq) + Cl (aq)

  • This means, that 3.9 kJ mol-1 of energy is absorbed when one mole of NaCl is dissolved in enough water to form a dilute solution
  • The ΔHsol is the sum of the lattice energy (ΔHlatt) and the standard enthalpy change of hydration (ΔHhyd)

ΔHsol = ΔHlatt + ΔHhyd

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7
Q

The lattice (formation) energy

A
  • is the energy released when gaseous ions combine to form one mole of an ionic compound under (standard conditions)
    • Since energy is released when an ionic compound is formed, the ΔHlatt is always exothermic
    • For example, the ΔHlatt of NaCl is -787 kJ mol-1

Na+ (g) + Cl (g) → NaCl (s)

  • This means, that 787 kJ mol-1 of energy is released when NaCl is formed from its gaseous ions
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8
Q

The standard enthalpy of hydration

A
  • is the energy released when gaseous ions dissolve in enough water to form a dilute solution (under standard conditions)
    • Since energy is released when gaseous ions become hydrated, the ΔHhyd is always exothermic
    • For example, the ΔHhyd of the sodium (Na+) ion is -406 kJ mol-1

Na+ (g) → Na+ (aq)

  • This means, that 406 kJ mol-1 of energy is released when Na+ ions become hydrated
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9
Q

Trends of enthalpy change of solution

A
  • Going down the group, the ΔHlattof the ionic compounds decreases
  • Going down the group, the ΔHhyd also decreases
  • The more exothermic the ΔHsol the more soluble the compound
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10
Q

Trends of enthalpy change of solution: Going down the group, the ΔHlattof the ionic compounds decreases

A
  • Going down the group, the positively charged cations become larger
  • There is more space between the negatively and positively charged ions in the ionic compound so there are weaker attractive forces between the ions
  • As there are weaker electrostatic forces between the ions, there is less energy released upon formation of the ionic compound from its gaseous ions
  • Therefore, the ΔHlatt becomes less exothermic
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11
Q

Trends of enthalpy change of solution: Going down the group, the ΔHhyd also decreases

A
  • Again, the positively charged ions become larger going down the group
  • As a result, the ion-dipole bonds between the cations and water molecules get weaker
  • This means that less energy is released when the gaseous Group 2 ions become hydrated
  • The ΔHhyd , therefore, becomes less exothermic
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12
Q

Trends of enthalpy change of solution: For Group 2 hydroxides

A
  • Hydroxide ions are relatively small ions
  • The ΔHlatt falls faster than the ΔHhyd
  • The enthalpy change of solution is, therefore, more exothermic going down the group
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13
Q

Trends of enthalpy change of solution: For Group 2 sulfates

A
  • Sulfate ions are relatively large ions
  • The ΔHlatt falls slower than the ΔHhyd enthalpy
  • The ΔHsol will become more endothermic going down the group
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14
Q

Trends of enthalpy change of solution: The more exothermic the ΔHsol the more soluble the compound

A
  • This is why the sulfates become less soluble going down the group and the hydroxides more soluble
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