Chapter 7 Group 2 Flashcards
Introduction of Group 2
- The Group 2 nitrates and carbonates become more thermally stable going down the group
- The charge density of the cation (Group 2 metal ion) and the polarisationoftheanion (the nitrate and carbonate ion) attribute towards this increased stability
Trends in thermal stability going down the group
- All Group 2 metals form 2+ ions as they lose two electrons from their valence shells
- The metal cations at the top of the group are smaller in size than those at the bottom
- The metal cations at the top of Group 2, therefore, have the greatest charge density as the same charge (2+) is packed into a smaller volume
- As a result, smaller Group 2 ions have a greater polarising effect on neighbouring negative ions
- When a carbonate or nitrate ion approaches the cation, it becomes polarised
- This is because the metal cation draws the electrons in the carbonate or nitrate ion towards itself
- The more polarised the anion is, the less heat is required to thermally decompose them
Therefore, the thermal stability increases down the group
- As down the group, the cation becomes larger
- Thus has a smaller charge density
- And a smaller polarising effect on the carbonate or nitrate anion
- So the anion is less polarised
- Therefore, more heat is required to thermally decompose them
Trends in Solubility & Enthalpy Change of Solution of Group 2 Hydroxides & Sulfates
- The solubility of Group 2 hydroxides increases down the group
- In contrast, the Group 2 sulfates show a decrease in solubility going down the group
- Compounds that have very low solubility are said to be sparingly soluble
- For example, calcium sulfate (CaSO4) has low solubility as only 0.21 g of CaSO4 dissolves in 100 g of water
- Most of the sulfates are soluble in warm water with the exception of barium sulfate which is insoluble
Solubility of Group 2 elements table
The Standard enthalpy of solution
-
(ΔHsolꝋ) is the energy absorbed or released when 1 mole of ionic solid dissolves in enough water to form a dilute solution (under standard conditions)
- The ΔHsolꝋ can be either exothermic or endothermic
- For example, the ΔHsolꝋ of sodium chloride (NaCl) is +3.9 kJ mol-1
NaCl (s) + aq → NaCl (aq)
OR
NaCl (s) + aq → Na+ (aq) + Cl– (aq)
- This means, that 3.9 kJ mol-1 of energy is absorbed when one mole of NaCl is dissolved in enough water to form a dilute solution
- The ΔHsolꝋ is the sum of the lattice energy (ΔHlattꝋ) and the standard enthalpy change of hydration (ΔHhydꝋ)
ΔHsolꝋ = ΔHlattꝋ + ΔHhydꝋ
The lattice (formation) energy
- is the energy released when gaseous ions combine to form one mole of an ionic compound under (standard conditions)
- Since energy is released when an ionic compound is formed, the ΔHlattꝋ is always exothermic
- For example, the ΔHlattꝋ of NaCl is -787 kJ mol-1
Na+ (g) + Cl– (g) → NaCl (s)
- This means, that 787 kJ mol-1 of energy is released when NaCl is formed from its gaseous ions
The standard enthalpy of hydration
- is the energy released when gaseous ions dissolve in enough water to form a dilute solution (under standard conditions)
- Since energy is released when gaseous ions become hydrated, the ΔHhydꝋ is always exothermic
- For example, the ΔHhydꝋ of the sodium (Na+) ion is -406 kJ mol-1
Na+ (g) → Na+ (aq)
- This means, that 406 kJ mol-1 of energy is released when Na+ ions become hydrated
Trends of enthalpy change of solution
- Going down the group, the ΔHlattꝋ of the ionic compounds decreases
- Going down the group, the ΔHhydꝋ also decreases
- The more exothermic the ΔHsolꝋ the more soluble the compound
Trends of enthalpy change of solution: Going down the group, the ΔHlattꝋ of the ionic compounds decreases
- Going down the group, the positively charged cations become larger
- There is more space between the negatively and positively charged ions in the ionic compound so there are weaker attractive forces between the ions
- As there are weaker electrostatic forces between the ions, there is less energy released upon formation of the ionic compound from its gaseous ions
- Therefore, the ΔHlattꝋ becomes less exothermic
Trends of enthalpy change of solution: Going down the group, the ΔHhydꝋ also decreases
- Again, the positively charged ions become larger going down the group
- As a result, the ion-dipole bonds between the cations and water molecules get weaker
- This means that less energy is released when the gaseous Group 2 ions become hydrated
- The ΔHhydꝋ , therefore, becomes less exothermic
Trends of enthalpy change of solution: For Group 2 hydroxides
- Hydroxide ions are relatively small ions
- The ΔHlattꝋ falls faster than the ΔHhydꝋ
- The enthalpy change of solution is, therefore, more exothermic going down the group
Trends of enthalpy change of solution: For Group 2 sulfates
- Sulfate ions are relatively large ions
- The ΔHlattꝋ falls slower than the ΔHhydꝋ enthalpy
- The ΔHsolꝋ will become more endothermic going down the group
Trends of enthalpy change of solution: The more exothermic the ΔHsolꝋ the more soluble the compound
- This is why the sulfates become less soluble going down the group and the hydroxides more soluble