Chapter 2 Entropy Flashcards

1
Q

The entropy (S) of a given system

A

is the number of possible arrangements of the particles and their energy in a given system
In other words, it is a measure of how disordered a system is

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2
Q

When a system becomes more disordered, its entropy will

A
  • increase
  • An increase in entropy means that the system becomes energetically more stable
  • For example, during the thermal decomposition of calcium carbonate (CaCO3) the entropy of the system increases:

CaCO3(s) → CaO(s) + CO2(g)

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3
Q

CaCO3(s) → CaO(s) + CO2(g)

  • In this decomposition reaction, a gas molecule
A
  • (CO2) is formed
  • The CO2 gas molecule is more disordered than the solid reactant (CaCO3), as it is constantly moving around
  • As a result, the system has become more disordered and there is an increase in entropy
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4
Q
  • Another typical example of a system that becomes more disordered is when a solid is melted
  • For example, melting ice to form liquid water:

H2O(s) → H2O(l)

A
  • The water molecules in ice are in fixed positions and can only vibrate about those positions
  • In the liquid state, the particles are still quite close together but are arranged more randomly, in that they can move around each other
  • Water molecules in the liquid state are therefore more disordered
  • Thus, for a given substance, the entropy increases when its solid form melts into a liquid
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5
Q

Melting a solid will cause the particles to become more disordered resulting in a more energetically stable system

A
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6
Q
  • All elements have positive standard molar entropy values
  • The order of entropy for the different states of matter are as follows:
A

gas > liquid > solid

  • There are some exceptions such as calcium carbonate (solid) which has a higher entropy than mercury (liquid)
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7
Q

Simpler substances with fewer atoms have

A

lower entropy values than complex substances with more atoms

  • For example, calcium oxide (CaO) has a smaller entropy than calcium carbonate (CaCO3)
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8
Q

Harder substances have

A

lower entropy than softer substances of the same type

  • For example, diamond has a smaller entropy than graphite
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9
Q
  • The entropy of a substance changes during a change in state
  • The entropy …. when a substance melts (change from solid to liquid)
A

Increases

  • Increasing the temperature of a solid causes the particles to vibrate more
  • The regularly arranged lattice of particles changes into an irregular arrangement of particles
  • These particles are still close to each other but can now rotate and slide over each other in the liquid
  • As a result, there is an increase in disorder
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10
Q

The entropy ….. when a substance boils (change from liquid to gas)

A

increases

  • The particles in a gas can now freely move around and are far apart from each other
  • The entropy increases significantly as the particles become very disordered
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11
Q

Similarly, the entropy …… when a substance condenses (change from gas to liquid) or freezes (change from liquid to solid)

A

decreases

  • The particles are brought together and get arranged in a more regular arrangement
  • The ability of the particles to move decreases as the particles become more ordered
  • There are fewer ways of arranging the energy so the entropy decreases
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12
Q

The entropy of a substance increases when the temperature is raised as particles become more disordered

A
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13
Q

The entropy of a substance increases when the temperature is raised as particles become more disordered

A
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14
Q

The entropy also increases when a solid is

A
  • dissolved in a solvent
  • The solid particles are more ordered in the solid lattice as they can only slightly vibrate
  • When dissolved to form a dilute solution, the entropy increases as:
    • The particles are more spread out
    • There is an increase in the number of ways of arranging the energy
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15
Q

The crystallisation of a salt from a solution is associated with a

A

decrease in entropy

  • The particles are spread out in solution but become more ordered in the solid
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16
Q

Gases have higher entropy values than

A
  • solids
  • So, if the number of gaseous molecules in a reaction changes, there will also be a change in entropy
  • The greater the number of gas molecules, the greater the number of ways of arranging them, and thus the greater the entropy
17
Q
  • For example the decomposition of calcium carbonate (CaCO3)

CaCO3(s) → CaO(s) + CO2(g)

  • The CO2 gas molecule is more disordered than the solid reactant (CaCO3) as it can
A
  • freely move around whereas the particles in CaCO3 are in fixed positions in which they can only slightly vibrate
  • The system has therefore become more disordered and there is an increase in entropy
18
Q

Similarly, a decrease in the number of gas molecules results in a

A

decrease in entropy causing the system to become less energetically stable

19
Q

The standard entropy change (ΔSsystem) for a given reaction can be calculated using the

A
  • standard entropies (S) of the reactants and products
  • The equation to calculate the standard entropy change of a system is:

ΔSsystem= ΣΔSproducts - ΣΔSreactants

(where Σ = sum of)

20
Q
  • For example, the standard entropy change for the formation of ammonia (NH3) from nitrogen (N2) and hydrogen (H2) can be calculated using this equation
A

N2(g) + 3H2(g) ⇋ 2NH3(g)

ΔSsystem = (2 x ΔS(NH3)) - (ΔS(N2) + 3 x ΔS(H2))

21
Q

The feasibility of a reaction does not only depend on the entropy change of the reaction, but can also be affected by the

A
  • enthalpy change
  • Therefore, using the entropy change of a reaction only to determine the feasibility of a reaction is inaccurate
22
Q

The Gibbs free energy (G) is the energy change that takes into account

A

both the entropy change of a reaction and the enthalpy change

23
Q
  • The Gibbs equation is:
A

ΔG = ΔHreaction - TΔSsystem

  • The units of ΔG are in kJ mol-1
  • The units of ΔHreaction are in kJ mol-1
  • The units of T are in K
  • The units of ΔSsystem are in J K-1 mol-1 (and must therefore be converted to kJ K-1 mol-1 by dividing by 1000)
24
Q
  • The Gibbs equation can be used to calculate the Gibbs free energy change of a reaction
A

ΔG = ΔHreaction - TΔSsystem

  • The equation can also be rearranged to find values of ΔHreaction, ΔSsystem or the temperature, T
25
Q
  • The Gibbs equation can be used to calculate whether a reaction is feasible or not
A

ΔG = ΔHreaction - TΔSsystem

  • When ΔG is negative, the reaction is feasible and likely to occur
  • When ΔGis positive, the reaction is not feasible and unlikely to occur
26
Q

The feasibility of a reaction can be affected by the

A
  • temperature
  • The Gibbs equation will be used to explain what will affect the feasibility of a reaction for exothermic and endothermic reactions
27
Q

Exothermic reactions

  • In exothermic reactions, ΔHreaction is negative
A
  • If the ΔSsystem is positive:
    • Both the first and second term will be negative
    • Resulting in a negative ΔG so the reaction is feasible
    • Therefore, regardless of the temperature, an exothermic reaction with a positive ΔSsystem will always be feasible
28
Q

Exothermic reactions

  • In exothermic reactions, ΔHreaction is negative
  • If the ΔSsystem is positive:
A
  • Both the first and second term will be negative
  • Resulting in a negative ΔG so the reaction is feasible
  • Therefore, regardless of the temperature, an exothermic reaction with a positive ΔSsystem will always be feasible
29
Q

Exothermic reactions

  • In exothermic reactions, ΔHreaction is negative
  • If the ΔSsystem is negative:
A
  • The first term is negative and the second term is positive
  • At high temperatures, the -TΔSsystemwill be very large and positive and will overcome ΔHreaction
  • Therefore, at high temperatures ΔGis positive and the reaction is not feasible
  • The reaction is more feasible at low temperatures, as the second term will not be large enough to overcome ΔHreaction resulting in a negative ΔG
30
Q

This corresponds to Le Chatelier’s principle which states that for exothermic reactions an increase in temperature will cause the

A

equilibrium to shift position in favour of the reactants, i.e. in the endothermic direction

  • In other words, for exothermic reactions, the products will not be formed at high temperatures
  • The reaction is not feasible at high temperatures
31
Q

The diagram shows under which conditions exothermic reactions are feasible

A
32
Q

Endothermic reactions

  • In endothermic reactions, ΔHreaction is positive
  • If the ΔSsystem is negative:
A
    • Both the first and second term will be positive
      • Resulting in a positive ΔG so the reaction is not feasible
      • Therefore, regardless of the temperature, endothermic with a negative ΔSsystem will never be feasible
33
Q

Endothermic reactions

  • In endothermic reactions, ΔHreaction is positive
  • If the ΔSsystem is positive:
A
  • The first term is positive and the second term is negative
  • At low temperatures, the -TΔSsystemwill be small and negative and will not overcome the larger ΔHreaction
  • Therefore, at low temperatures ΔGis positive and the reaction is less feasible
  • The reaction is more feasible at high temperatures as the second term will become negative enough to overcome the ΔHreaction resulting in a negative ΔG
34
Q

This again corresponds to Le Chatelier’s principle which states that for endothermic reactions an increase in temperature will cause the

A

equilibrium to shift position in favour of the products

  • In other words, for endothermic reactions, the products will be formed at high temperatures
  • The reaction is therefore feasible
35
Q

The diagram shows under which conditions endothermic reactions are feasible

A