Chapter 5 - Line Integrals Flashcards
Scalar field
A function that assigns a real number to each point (x,y,z) in a region of R^3
Vector field
A function that assigns a vector v (x,y,z) in a 3-dimensional space to each point (x,y,z) in a region of R^3
Smooth curve
Dr/dt is continuous and |dr/dt| isn’t equal to 0
Piecewise smooth curve
A continuous curve made up of 2 or more smooth curves such that the end point of one smooth curve coincides with the start point of the next smooth curve
Method to calculate line integrals of scalar fields along a smooth curve C from A to B
1) Choose an appropriate parameterisation such that the position vector of a point on C is r(t), ta
Simple closed curve
A curve that doesn’t cross itself and ends at the same point that it begins
Line integral of a vector field v(x,y,z) along a smooth curve C
I = integral over C of [v•dr]
Since r=(x,y,z), dr=(dx,dy,dz)
I=integral over C of [v1dx + v2dy + v3dz]
Evaluating integral if we specify C parametrically with position vector r (t) given as a function of a parameter t
Then we can write I = integral over c of [v• dr/dt] dt.
Then evaluate the scalar porduct as a function of t and evaluate thr definite integral with respect to t as for scalar fields
Evaluating integral if we can specify c as an explicit functional relationship, such as y=f (x), z=g (x) where f (x) and g (x) are continuous differentiable functions of x
Then I = integral over C of [v1 + v2f’(x) + v3g’(x)] dx
And evaluate this as a definite integral with respect to x
Length of C
Integral (from ta to tb) of [ |dr/dt| ]
What happens to the sign of the line integral of a vector field?
Unlike the integrals of scalar fields, the value od the line integral of a vector field changes sign when the sense of description of the curve C is reversed
Circulation of v around c
K = closed integral over c of [ v•dr ]
This is hoe the line integral of a vector field v aroubd a simple closed curve is denoted.
Green’s theorem
Let R be a simply connected closed region of the plane whose boundary is a simple, piecewise smooth, closed curve C oriented anti-clockwise.
If f(x,y) and g(x,y) are continuous and have continuous first partial derivatives on some open set containing R, then
Closed integral over C of [ f(x,y)dx + g(x,y)dy]
= double integral over R of [(dg/dx - df/dy) dxdy]
Area of the region R enclosed by the curve C
A = (1/2)* closed integral over c of [ -ydx + dy]
= closed integral over c of [xdy]
= closed integral over c of [-ydx]
Path independent line integrals
The value of the integral depends only on the location of the end points of the curve, and not on the particular path taken between them.
I = integral (A to B) of [v•dr]
where A and B denote the start and end points of the curve over which integration is performed