Chapter 13 lecture (Homologous recombination) Flashcards

1
Q

why is Homologous recombination Essential in bacteria and in eukaryotic mitosis

A

to repair DNA damage and stalled replication forks

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2
Q

why is homologous recombination essential in eukaryotic meiosis

A

for generating diversity and for chromosome segregation

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3
Q

Recombination enzymes can use … as substrates

A

any pair of identical or nearly identical sequences

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4
Q

how is homologous recombination initiated

A

a double stranded break

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5
Q

in homologous recombination, how is the DbSB enlarged?

A

exonuclease will Degrade the 5’ end of both strands flanking the gap to form 3’-single stranded overhangs

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6
Q

A 3’ overhang will perform a … of the other duplex to make …

A

stand invasion
heteroduplex DNA

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7
Q

what will be used as template to synthesize new DNA through DbSB region

A

undamaged copy of DNA

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8
Q

after the DNA is synthesized in homologous recombination, what happens next?

A

The invading strand is released and base pairs with the single strand from the original duplex

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9
Q

in homologous recombination, High fidelity DNA polymerases will

A

fill in remaining gaps and all strands will be ligated

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10
Q

If it occurs after S phase

A

there will be identical sister chromatids to use as a template

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11
Q

If it occurs in G1,

A

it will have to use a non-identical homologous chromosome as a template

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12
Q

Meiotic recombination uses a homologous sequence as a template, even though

A

a sister chromatid is present

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13
Q

what is a key component of the homologous recombination mechanism in E. coli

A

RecA protein

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14
Q

RecA protein is similar to what in eukaryotes

A

Rad51

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15
Q

RecA binds to

A

the single stranded 3’ overhang produced after DbSB

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16
Q

RecA forces ssDNA into a

A

“double stranded” helical conformation

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17
Q

The RecA/ssDNA complex can displace

A

single strands from duplexes

18
Q

If RecA/ssDNA finds a complimentary sequence of >15 nt

A

Complimentary strand will pair with ssDNA to form heteroduplex

19
Q

Homologous recombination is necessary in eukaryotes
for

A

DNA repair
Restarting of collapsed replication forks
Needed for successful pairing of homologous chromosomes in prophase I

20
Q

failure of homologous pairing leads to

A

nondisjunction in anaphase 1

21
Q

Meiotic recombination begins in the same way as with general homologous recombination, except

A

The DbSB is induced by the Spo11 protein complex
The undamaged copy that is used as a template is a nonidentical homologous chromosome

22
Q

what two proteins coat ssDNA overhangs and promote strand invasion

A

dmc1 and rad51

23
Q

dcm1 is only active in

A

meiosis and has specificity for homologous chromosome
Prevents invasion of sister chromatid

24
Q

rad51 is active

A

throughout the cell cycle for all DsDB recombination in eukaryotes
Loaded onto the ssDNA by the Brca2 protein
Loss of Brca2 function leads to reduced DsDB repair

25
Q

Spo11 protein produces the

A

DbSB needed for meiotic recombination

26
Q

how does Spo11 protein produce the DbSB needed for meiotic recombination

A

A tyrosine side chain of Spo11 attacks the phosphodiester backbone of DNA and creates a covalent enzyme-DNA complex
Energy of phosphodiester linkage is stored in enzyme-DNA linkage
DbSB is reversible and DNA strands can be easily resealed if recombination does not proceed

27
Q

Sequence specificity of Spo11 activity is … but timing is …

A

low
highly regulated

28
Q

Nuclease activity of Spo11 is related to existence of

A

recombination hotspots and coldspots in genome

29
Q

hotspots

A

open active chromatin
promotors

30
Q

coldspots

A

centromeres, telomeres
constitutive heterochromatin

31
Q

holliday junction

A

where two homologous helices are held together by the exchange of two of the four strands

32
Q

90% of the time, the DbSB are resolved as

A

non-crossover (patch) products

33
Q

10% of the time, the DbSB are resolved as

A

The second strand is captured
Another Holliday junction is formed
The strands are cut and resolved as crossover (splice) products

34
Q

what end of the strands are used as primers to extend the heteroduplexes

A

3’

35
Q

When the extended single strands reaches the end of the gap, the single strands are ligated and

A

the second holiday junction is formed

36
Q

The Holliday junction can move along the DNA using

A

branch migration

37
Q

Upon resolution of both Holliday junctions using cleavage at different sites,

A

crossover products will be produced

38
Q

Crossover control

A

The small number of crossovers on a chromosome will inhibit the resolution of nearby DbSB as crossovers

39
Q

Even if a DbSB is resolved as a non-crossover a small heteroduplex patch remains that is a potential site of

A

gene conversion

40
Q

gene conversion

A

One allele converted into another
An additional way to produce genetic variation in meiosis
Is a possible result of any DbSB-coupled homologous recombination
Including DNA repair mechanism

41
Q

How does DbSB-coupled repair lead to gene conversion?

A

A polymorphic region is located inside the region that is involved in the strand invasion synthesis
The original allele will be replaced by one from the homologous duplex
If the homologous template is not identical, then it will create a heteroduplex mismatch
The heteroduplex mismatch randomly repaired by mismatch repair enzymes
Alters genotypic proportions of gametes