Chapter 10: The Mole Flashcards
Mole (Avogadro’s Number)
6.02 x 10^23 particles
Subscript (Chemical Equation)
Denotes how many atoms of each substance in a compound
Coefficient (Chemical Equation)
Denotes how many of each compound
a.m.u. (Atomic Mass Units)
1 a.m.u. = 1/12 mass Carbon-12
Formula Mass
Sum of atomic masses of all atoms in a formula
Molar Mass
Grams (g)/mole (m)
Grams–>Moles
Multiply by molar mass
Moles–>Grams
Divide by molar mass
Moles–>Particles
Multiply by 6.02 x 10^23
Particles–>Moles
Divide by 6.02 x 10^23
Percent Composition
% Element = [(number of atoms) x (atomic weight)]/(formula weight of the compound)
Molecular Formula
Actual number of atoms of each type in a molecule
Ex: C6H12O6
Empirical Formula
Lowest ratio of atoms in a compound
Ex: CH2O (From C6H12O6)
Hydrate
Ionic material that has water incorporated in its crystalline structure
What Happens To A Hydrate When Heated
The water in a hydrate may be driven off, and the crystalline structure of the material changes
Anhydrous
Without water
Finding The Formula Of A Hydrate
- Find the mass of a hydrated salt
- Heat the salt to a uniform mass
- Find the mass lost
- Change the grams of water lost to moles
- Change the mass of salt remaining after heating (anhydrous salt) into moles
- Find a mole ratio between the moles of water and moles of anhydrous salt
- In the formula of the hydrate, use the mole ratio as a coefficient for the water