Calculus I Unit 4 - 8 Notations Flashcards

1
Q

What is the Linear Approximation Equation ?

A

ℓ(x) = ƒ(a) + ƒ’(a)(x - a)

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2
Q

Explain the Linear Approximation Process for √(15.9)

A

Identify the equation we are looking to approximate: √(x)

Then find a number close to our inside value: a = 16

Solve for f(a) using the original function then solve for f’(a) using the derivative of the original function:

ƒ(16) = √(16) = 4
ƒ’(16) = 1/2√(16) = 1/8

Now plug our values into the Linear Approximation equation, then plug in the true value:

ℓ(x) = 4 + 1/8 (15.9 - 16) → ℓ(15.9) 4 + 1/8 (15.9 - 16).

Lastly solve ℓ(15.9) for our approximation:

ℓ(15.9) = 4 + 1/8 (-1/10) → 420/80 - 1/80 = 319/80

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3
Q

Explain the Optimization Problem Process

A

Draw out the system being solved for.

Obj Equation: Identify the Equation being solved for (Ie: Surface Area/Volume Equations).

Constraints: Identify the equation (typically given) that forms our constraints.

Solve: the equation to make it single variable.

Identify: the domain of the variable using the new equation.

Differentiate: the Objective Equation with respect to our singled variable.

Critical Points are identified to find the minimum and maximums.

1st/2nd Derivative Test is performed to find the true minimum and maximum points.

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4
Q

What are the assumed intervals of Minimum and Maximum Optimization Problems ?

A

Maximum Problems: (Closed Intervals).
Minimum Problems: (Open Intervals ie: (0 ,∞)) use RD Test.

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5
Q

What does the Rolles Theorem state ?

A

If ƒ is cont. on [a,b] and ƒ(a) = ƒ(b) then there’s a value c between (a,b) such that ƒ’(c) = 0

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6
Q

What is the Equation to Mean Value Theorem in the interval [a,b] and how do you solve for the points guaranteed to exist ?

A

ƒ(a) - ƒ(b) / a - b = ƒ’(c)

Where ƒ’(c) is the derivative of ƒ(x) and x is set to c. c is then solved for using algebra

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7
Q

What does Mean Value Theorem state?

A

ƒ is cont. on [a,b] and differentiable on (a,b) then theres at least one point c such that:

ƒ(a) - ƒ(b) / a - b = ƒ’(c)

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8
Q

Under which conditions should L’hopital’s Rule be applied ?

A

When the Limit is in an indeterminate form:

0/0 | ∞/∞ | ∞ ⋅ 0 | ∞ - ∞ | 0⁰ | ∞⁰ | 1∞

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9
Q

How is L’hopital’s Rule applied ?

A

By format-ing the limit into a fraction then taking the derivative of the top and bottom separately

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10
Q

How is the Average Value of a function found ?

A

ƒₐ = (1/b - a) ⋅ ∫ ƒ(x) dx

where b is the upper bound and a is th lower bound

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11
Q

Explain the difference between Displacement and Distance

A

Displacement is the amount of distance traveled from the start point.

Distance is the amount traveled total regardless of displacement from starting point.

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12
Q

How to find the are bounded by the curve of
y = -x² + 3 and y = -x + 1

A

Take the intergral of the topmost function and subtract it by the bottomost intergral of the bottomost function at the same bounds:

∫ [(-x² + 3) - (-x + 1)] dx

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13
Q

Explain the structure of Sigma Notation:

A
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14
Q

Define the property of:

A

= n(n + 1) / 2

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15
Q

Define the property of:

A

= n(n + 1)(2n + 1) / 6

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16
Q

Define the property of:

A

n²(n + 1)² / 4

17
Q

Define the propety of:

A
18
Q

What is the equation for dy ?

A

dy = ƒ’(x)dx

Where dx is the change in x.

19
Q

Evaluate the limit:

lim h → 0⁺
(1/3) - (1/3+h) / h

A

Algebriacally manipulate the equation:

lim h → 0⁺
(3 + h - 3) / 3h(3 + h)

Cancel the h in the numerator and solve.

lim h → 0⁺ 1 / 3(3) = 1/9

20
Q

find a if ƒ(x) =

(x² + 4x) / (x) if x ≠ 0
a if x = 0

A

Find the limit of
(x² + 4x) / (x) using l’hopital’s rule.

limit x → 0
(x² + 4x) / (x)

limit x → 0
= (2x + 4) / 1

a = 4

21
Q

Explain how to solve

Given the velocity 𝑣(𝑡) of an object moving along a line and its initial position 𝑠(0),
which of the following represents the position of the object 𝑠(𝑡) for time 𝑡 ≥ 0.

A

Since we know that 𝑠(𝑡) is the antiderivative of 𝑣(𝑡) and the initial constant is given by 𝑠(0)

𝑠(𝑡) = 𝑠(0) + ∫₀ᵗ 𝑣(𝑥)d𝑥

22
Q

Find the solution to the initial value problem.

ƒ(𝜋/3) = -3

ƒ’(𝑡) = 1 + 6sin(𝑡)

A

First find the antiderivative of ƒ’(𝑡) and set it equal to ƒ(𝜋/3)

-3 = ∫ 1 + 6sin(𝑡)d𝑡

Take the antiderivative the right and solve for the constant c at 𝑡 = (𝜋/3)

-3 = 𝜋/3 -6cos(𝜋/3) + c

-3 = 𝜋/3 - 3 + c

-𝜋/3 = c

23
Q

What is the Fundamental Theorem of Calculus ?

A

The Derivative of the integral of ƒ is just ƒ itself

Ex: d/dx ƒ(𝑡)