Calculations II: Compounding Flashcards
% w/v
g/mL
% v/v
mL/100 mL
% w/w
g/100 g
ratio strength
one unit:total amount
convert one unit to g
PPM
from percentage: move decimal L 4 spaces
to percentage: move decimal R 4 spaces
to ratio strength: equate to g substance/total mL
specific gravity
weight of substance/weight of equal volume of water
g/mL
dilution and concentration
Q1 x C1 = Q2 x C2
“pure” = 100%
diluent concentration = 0%
watch out for Q2 being TOTAL final weight = may need to subtract weight already started with
osmolarity
always normalize to vol of 1 L (when finding weight)
mOsmol/L = wt of substance (g/L) / MW (g/mole) X valence X 1000
if you have more than 1 component (dextrose in NS + added drug) - find separate osmolarities and then add together
dextrose dissociated particles
1
mannitol dissociated particles
1
potassium chloride dissociated particles
2
sodium chloride dissociated particles
2
magnesium sulfate dissociated particles
2
calcium chloride dissociated particles
3
sodium citrate dissociated particles
4
finding dissociation factor/ionization i
1 dissociated ions = 1
2 dissociated ions = 1.8
3 dissociated ions = 2.6
4 dissociated ions = 3.4
5 dissociated ions = 4.2
E value
`amt of NaCl that makes same osmolarity as drug in question
E = (58.5)(i)/(MW x 1.8)
to find NaCl equivalent of substance: weight * E
moles and millimoles
mol = g/MW
mmol = mg/MW
milliequivalents
mEq = (mg x valence)/MW
mEq = mmols/valence
ammonium chloride valence
1
potassium chloride valence
1
potassium gluconate valence
1
sodium acetate valence
1
sodium bicarbonate valence
1
sodium chloride valence
1
calcium carbonate valence
2
calcium chloride valence
2
ferrous sulfate valence
2
lithium carbonate valence
2
magnesium sulfate valence
2
KCl 10% mEq
20 mEq/15mL