C9 Energy, Power and Resistance Flashcards

1
Q

Define Potential Difference and explain with a filament lamp as an example

A
  • A measure of the transfer of energy by charge carriers.
  • The p.d. across a filament lamp is a measure of the electrical energy being transferred into heat and light as charge carriers move through the lamp.
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2
Q

P.d. in terms of joules

A
  • 1 volt is the p.d. across a component when 1J of energy is transferred per unit charge.
  • 1V = 1 JC -1
  • A p.d. of 1000V means that 1000J of energy is transferred per coulomb of charge.
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3
Q

Formula relating Charge, Voltage, Energy

A

V = W / Q
Voltage = Work Done / Charge

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4
Q

Describe Potential Difference in terms of work done

A

Potential difference is when work is done by the charge carriers.

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5
Q

Electromotive Force (e.m.f) idea in terms of work done, and equation

A

This is when work is done on the charge carriers, as each charge carrier gains energy as they pass through a source of energy e.g. cell.

ε = W / Q

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6
Q

Electromotive Force in terms of energy transfer from sources definiton

A

The energy transferred from a chemical energy source (or another form) to electrical energy per unit charge.

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7
Q

Calculating work done with charge, emf and voltage

A

W = V x Q, work done = voltage x charge
W = ε x Q, work done = e.m.f x charge

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8
Q

How do electron guns work?

A
  • A small metal filament is heated by an electric current.
  • The electrons will gain enough kinetic energy to escape from the metal’s surface (thermionic emission).
  • The heated filament is placed in a vacuum, and a high p.d is applied between the filament and an anode, the filament acts as a cathode.
  • The emitted electrons accelerate toward the anode.
  • The anode as a small hole in it, so the electrons in line with this hole pass through it creating a beam of electrons with a specific KE.
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9
Q

How to calculate work done on electron from electron gun

A

work done on a single electron = eV
V = accelerating p.d

eV = 1/2mv^2

this assumes the electrons have negligible kinetic energy at the cathode

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10
Q

Formula for resistance

A

R = V / I

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11
Q

Define the ohm

A
  • The resistance of a component when a p.d. of 1V is produced per ampere of current.
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12
Q

Define Ohm’s law, and what is a device that obeys Ohm’s law called?

A
  • For a metallic conductor kept at a constant temperature, the current in the wire is directly proportional to the p.d across its ends, V = IR.
  • If the voltage across a wire doubles, so does the current.
  • A component that obeys ohm’s law is an ohmic conductor, e.g. fixed resistor.
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13
Q

How and why does temperature affect resistance?

A
  • As temperature increases, the ions inside a wire have more internal energy, therefore vibrate with greater amplitude about their mean positions.
  • The frequency of collisions between charge carriers and ions increases, so the charge carriers have do more work to move.
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14
Q

Describe Filament Lamps

A
  • They are non-ohmic conductors.
  • Their resistance is not constant, and increases as the p.d. increases.
  • They behave in the same way regardless of polarity.
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15
Q

Describe the properties of a diode

A
  • Diodes are non-ohmic conductors.
  • They do not have a constant resistance.
  • Behaviour depends on polarity of circuit.
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16
Q

What is Diode Threshold Frequency

A
  • The minimum voltage required for the diode to conduct significant current.
17
Q

What factors affect the resistance of a wire?

A
  • Material
  • Length
  • Cross sectional area
18
Q

Explain the relationship between resistance and length

A
  • Resistance is directly proportional to length.
  • Electrons have to travel a longer distance through a wire. This means they encounter more collisions with ions in the wire, which impedes their flow, increasing resistance.
19
Q

State and explain the relationship between cross sectional area and resistance

A
  • They are inversely proportional, if cross sectional area increases, resistance decreases.
  • There is more space for electrons to flow through. This reduces the likelihood of collisions between electrons and the ions in the wire, allowing the current to flow better.
20
Q

Formula to calculate resistance given resistivity

A

R = pL / A
where p = resistivity of a material

21
Q

Formula to calculate resistivity given resistance

A

p = RA / L

22
Q

What does a negative temperature coefficient mean for a semiconductor

A
  • As temperature increases, their resistance drops.
  • The number density of the charge carriers increases as temp increases.
23
Q

Thermistor & its relationship between resistance and temperature

A
  • Thermistors are made from semiconductors with a negative temperature coefficient.
  • Noh-ohmic conductor
  • As temperature increases, resistance drops.
24
Q

Light-dependant resistor

A
  • Made from a semiconductor where density of charge carriers depends on intensity of incident light.
  • When light is more intense, resistance decreases.
25
Q

Define Power, and how to convert it into joules

A
  • The rate of energy transfer by an electrical component.
  • 1W = 1J per second
26
Q

Formulas for power

A

P = IV
P = I^2 * R
P = V^2 / R

27
Q

Deriving P = IV

A

P = W / t
V = W/Q
rearrange: W = QV
P = VQ / t
however, Q/t = I
P = IV

28
Q

Kilowatt-hour (kWh)

A

The energy transferred by a device with a power of 1kW for 1 hour.