C4 Amount Of Substance- Moles In Solids And Gases

Question 1

Relative atomic mass

Answer 1

The weighted mean mass of an atom of an element compare with 1/12 of the mass of an atom of carbon-12 which is taken as exactly 12

Question 2

Relative isotopic mass

Answer 2

The mass of an atom of an isotope of the element compared with 1/12 of the mass of an atom of carbon-12 which is taken as exactly 12

Question 3

Relative molecular mass

Answer 3

The weighted mean mass of a molecule of the compounds compared with 1/12 of an atom of carbon 12 which is taken as exactly 12

Question 4

Relative formula mass

Answer 4

The weighted mean mass of the formula unit of the compound compared with 1/12 of an atom of carbon-12 which is taken as exactly 12

Question 5

Mole

Answer 5

The amount of substance that contains as many elementary particles as there are atoms in exactly 12g of carbon-12
Symbol= mol

Question 6

Avogadro constant (NA)

Answer 6

6.02 x10^23

Contains the same number of moles as carbon 12

Question 7

Molar mass

Answer 7

The mass of one mole of a substance

Unit = g mol^-1

Question 8

Mole calculation

Answer 8

n=m/Mr

Question 9

Empirical formulae

Answer 9

Mass} convert to} amount in moles} convert to} simplest who number ratio

Question 10

Water of crystallisation

Answer 10

The water present in hydrated salts

Question 11

Hydrated

Answer 11

Compound contains water as part of its structure

Question 12

Anhydrous

Answer 12

A hydrated compound after it has lost its water of crystallisation

Question 13

Avogadro’s law

Answer 13

States that equal volumes of all gases measured at the same temperature and pressure will contain the same number of molecules

Question 14

Standard gas conditions

Answer 14

0 degrees Celsius
100kPa
Molar volume of 22.7 dm^3mol^-1

Question 15

Laboratory gas conditions

Answer 15

Molar volume of 24 000 cm^3mol^-1

Question 16

Amount of gas in moles equation

Answer 16

n=V/molar volume

Question 17

Ideal gas equation

Answer 17

PV = nRT

P- pressure V- molar volume n- moles
R- constant of proportionality T- temperature

Question 18

Ideal gas standard conditions

Answer 18

R- worked out J K^-1 mol^-1
T- 273.16 K
P- 101.32 kPa
V- 22.414 dm^3
n- 1

Question 19

Combining Charles and Boyles law

Answer 19

P1V1/T1 = P2V2/T2

Question 20

Ideal gas factors

Answer 20

The molecules ( or atom) are in continuous random motion
There are no intermolecular forces between the individual molecules or atoms
All collisions are perfectly elastic with no change of kinetic energy
The molecules or atoms have no size (occupy 0 volume)