C4 Flashcards
Relative masses and moles
Number of moles = mass/Ar or mass/Mr
Mass = number of moles x Ar or Mr
Percentage by mass = mass of element/mass of compound x 100
Equations and calculations
Number of moles = mass of substance/molar mass
Mass = number of moles x molar mass
The yeild of a chemical reaction
The percentage yeild of a chemical reaction shows how much product was actually made compared with the amount of product that was expected.
Percentage yeild = mass of product made/ maximum mass of product x100
Factors effecting percentage yeild:
Reaction could be reversible
Some products may be lost
The reaction may not be pure
Atom economy
Atom economy is a measure of the efficiency of a chemical reaction.
It is the amount of starting materials that end up as useful products
If most of the starting materials end up as useful products the reaction is aaid to have a high atom economy
Atom economy = mass of desired products / sum of mass of all products x100
Limiting reactants
The reactant that gets used up first in a chemical reaction is called the limiting reactant
The amount of chemicals formed in a chemical reaction are determined by the limiting reactant
Expressing concentrations
Vol in dm3 = vol in cm3 / 1000
Concentration(mol/dm3) = moles/volume(dm3)
Concentration(g/dm3) = amount of solute(g)/ volume of solution(cm3) x1000
Titrations
An acid and an alkali react togther and neutralise eachother. They form a salt and a water in the process.
If you mix a strong acid and a strong alkali the solution made will be neutral only if the exact quantities are added
Acid and alkali titrations
If you start with more acid than alkali, the alkali will be neutralised, however the solution after will ve acidic, because the acid is in excess.
If you you have more alkali than acid to begin with, then all the acid will be neutralised and the solution left alkaline.
End point- the point in a titration where the reaction is complete and the titration should stop
Volume of gases
At room temperature and pressure, one mole of any gas has a volume of 24dm3 (molar mass volume)
Number of moles of gas = volume of gas/24dm3
Volume of gas(cm3)/240000cm3