Borohydride Reduction Lab Quiz Questions Flashcards

1
Q

What reducing agent will we use?

A

NaBH4, sodium borohydride

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2
Q

What will be the reactant? (What we reduce)

A

9-Fluorenone

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3
Q

What will be the reduced product of 9-Fluorenone?

A

9-Fluorenol

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4
Q

What will we use to neutralize the reaction and isolate the alcohol product?

A

HCL

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5
Q

What do we use to separate out the products?

A

Methylene Chloride

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6
Q

What do we use to dry the products?

A

Anhydrous Sodium Sulfate

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7
Q

How do you calculate theoretical yield?

A

g/MM * mol product/molreactant *MM product

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8
Q

How do you calculate percentage yield?

A

Actual Yield/Theoretical Yield x 100

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9
Q

What is the structure/formula of 9-Fluorenol

A

A benzene ring on either side of a five carbon ring (sharing two carbons each), with a single bond OH on the top of the five carbon ring

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10
Q

What is the structure/formula of Hexane?

A

6 carbons

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11
Q

What is the structure/formula of Hydrogen Chloride?

A

HCL

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12
Q

What is the structure/formula of Silica Gel?

A

SiO2

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13
Q

What is the structure/formula of Methylene Chloride?

A

CH2Cl2

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14
Q

What is the structure/formula of Anhydrous Sodium Sulfate?

A

Na2SO4

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15
Q

What is the overall procedure?

A
Reduce ketone (monitor via TLC)
Acidify to form product & remove excess NaBH4.
Extract product with CH2Cl2.
Dry CH2Cl2 extract over Na2SO4.
Evaporate CH2Cl2.
Weigh product. Calc. % yield.
Run MP.
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16
Q

How do you calculate Rf?

A

d/D when d is starting line to sample spot center, and D is starting line to final solvent front

17
Q

What are the polarity effects of TLC? (for this experiment)

A

The more polar the compound, the more it sticks to the plate and the lower the Rf

18
Q

What is the structure/formula of 9-fluorenone?

A

A benzene ring on either side of a five carbon ring (sharing two carbons each), with a double bond O on the top of the five carbon ring

19
Q

What is the structure/formula of acetone?

A

Chain of three carbons, center has =O

20
Q

Give the balanced reaction for this experiment?

A

4 9-fluorenone + NaBH4 -> 4 9-fluorenol