atomic structure exam question Flashcards

1
Q

In a time of flight mass spectrometer, molecule X is ionised using electrospray ionisation.
What is the equation for this ionisation?
A X(l) + e– → X+(g) + 2 e–
B X(g) + e– → X+(g) + 2 e–
C X(l) + H+ → XH+(g)
D X(g) + H+ → XH+(g)

A

D X(g) + H+ → XH+(g)

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2
Q

What is the electron configuration of V2+ in the ground state?
A 1s2 2s2 2p6 3s2 3p6 3d3
B 1s2 2s2 2p6 3s2 3p6 3d1 4s2
C 1s2 2s2 2p6 3s2 3p6 3d3 4s2
D 1s2 2s2 2p6 3s2 3p6 3d5 4s2

A

A 1s2 2s2 2p6 3s2 3p6 3d3

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3
Q

Which has the electron configuration of a noble gas?
A H+
B O–
C Se2–
D Zn2+

A

C Se2–

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4
Q

This question is about time of flight (TOF) mass spectrometry.
(a) Define the term relative atomic mass.

A

the average mass of an element

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5
Q

This question is about the isotopes of chromium.
(a) Give the meaning of the term relative atomic mass.

A

average/mean mass of 1 atom of an element
1/12 mass of one atom of 12Cr

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6
Q

The sample of chromium is analysed in a time of flight (TOF) mass spectrometer.
(d) Give two reasons why it is necessary to ionise the isotopes of chromium before they can be analysed in a TOF mass spectrometer.

A
  • so they are attracted to the negativley charged plate
  • so the ions can hit the detector and create a current
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7
Q

(c) A sample of germanium is analysed in a TOF mass spectrometer using electron impact ionisation.
Give an equation, including state symbols, for the process that occurs during the ionisation of a germanium atom.

A

Ge (g) + e- –> Ge+ (g) + 2e-

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8
Q

The first ionisation energies of the elements in Period 2 change as the atomic number increases.
Explain the pattern in the first ionisation energies of the elements from lithium to neon. [6 marks]

A

1st ionization energy increase
greater nuclear charge (more protons)
similar electron shielding
electrons in the same energy levle
stronger attractino between the nucleus and the outer electron
B lower thna BE
outer electron in 2p
2 electronis n 2p need to pair
pairing causes repulsion

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9
Q

Describe the process of electrospray ionisation.
Give an equation to represent the ionisation of P in this process.

A

P + H+ –> PH+

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10
Q

Which atom has the greatest first ionisation energy?
A H
B He
C Li
D Ne

A

He

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11
Q

State which of the elements magnesium and aluminium has the lower first ionisation energy.
Explain your answer.

A

Al
outer electron in 3p sublevel
higher energy further from the nucleus so easier to remove an outer electron

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12
Q

State how, if at all, the chemical properties of these isotopes differ.
Give a reason for your answer.

A

chemical properties dont differ
all have the same electronic configration or soame number of outer electrons

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13
Q

Element Q forms a sulfate with formula QSO4
Which of these could represent the electronic configuration of an atom of Q?
A [Ne]3s1
B [Ne]3s2
C [Ne]3s23p1
D [Ne]3s13p2

A

B
[Ne]3s2

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14
Q

Bromine exists as two isotopes 79Br and 81Br, which are found in almost equal abundance. Which of the statements is correct?
A The first ionisation energy of 79Br is less than the first ionisation energy of 81Br
B The atomic radius of 79Br is less than the atomic radius of 81Br
C The mass spectrum of C3H7Br has two molecular ion peaks at 122 and 124
D 79Br is more reactive than 81Br

A

C
The mass spectrum of C3H7Br has two molecular ion peaks at 122 and 124

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15
Q

Outline how the TOF mass spectrometer is able to separate these two
species to give two peaks.

A
  • positive ions are accelerated
  • lighter ions and more charged ions reach a higher speed
  • constant kinetic energy
  • … ion arrives at the detector first
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16
Q

state and explain the trend in the first ionization energies of the elements in group 2 form magnesium to barium

A

decrease
ions get bigger / more shells
weaker attraction of ion to lost electron

17
Q

state the element in period 3 that has the highest ionisation energy. explain your answer

A

argon
greatest nuclear charge
similar electron shielding

18
Q

explain why the second ionisation energy of boron is higher than the first ionisation enrgy of boron

A

electron is being removed from a positive ion therefore it needs more energy