Amounts Of Substances Flashcards
5.1 Amount of Subastances: Moles
Moles (n)
How much a substance you have regardless its state
5.2 Amount of Subastances: Avogadro’s Constant in calculations
1 mol/ Avogadro’s Constant
n x Avogadro’s Constant = how many atoms in compound
6.02 x 10 23
5.2 Amount of Subastances: Avogadro’s Constant in calculations
1 Mole of any substance
Has the same weight of its Mr
5.3 Amount of Subastances: Moles Eq
n = m/ Mr
(solid)
moles
(mol) = mass (g) / molecular mass
moles (mol) = mass (g) / molar mass
5.3 Amount of Subastances: Moles Eq
n = cv
(liquid)
moles (mol) = concentration (mol dm-1) x volume (dm3)
5.3 Amount of Subastances: Conversions
1dm3 = 1L
5.3 Amount of Subastances: Conversions
1dm3 = 1000cm3
5.4 Amount of Subastances:
Molecular Formula
(Multiple Emperical)
Actual number of atoms of each element in a molecule
5.4 Amount of Subastances:
Emperical Formula
(Shortest)
Smallest whole number ratio of atoms of each element in a compound
5.5 Amount of Subastances: Calculating EF
Empirical Formulae
1) Find Empirical mass (Mr)
2) Divide given Molecular mass by Mr
↳ works out empirical unit
5.5 Amount of Subastances: Calculating MF
Molecular Formulae
Multiple Empirical Formular by Emperical unit
5.5 Amount of Subastances:
pV = nRT
(gasses & volatile liquids)
p: Pressure (Pa) [1KPa = 1000Pa]
V: Volume (m3) [1cm3 = 1 x10 -6 m3]
n: number of moles (mol)
R: gass constant (8.314JK -3)
T: Temperature (K) [K = °C +273]
5.5 Amount of Subastances: EF using composition by mass/percentage
When given a % instead of mass
Percentage = Mass
- If you get a whole number = ANSWER
- Otherwise divide answer in part 1 by smallest mole value
5.6 Amount of Subastances: Write Balanced Ionic Eq
Ionic Equations
(neutralisation/titration)
1) Write down balanced Molecular Formula
2) Add state symbols
3) Neut reactions (acid + base), 2 products formed (salt + water)
4) Water = always (l) Rest = (aq)
5) Split (aq) solutions into respective ions, NOT WATER
6) Remove duplicates on either sides of arrow
7) What is left over = final eq.
5.6 Amount of Subastances: Write Balanced Ionic Eq
Ionic Equations
(carbonate)
Similar to neut but:
1) Water = (l) CO2 = (g) Rest = (aq)
2) Don’t split up (l) & (g)
3) What is left over = final eq.
5.6 Amount of Subastances: Write Balanced Ionic Eq
Ionic Equation
(sulfuric acid)has 2 protons→release into reaction→ produces double I eq
Only when Sulfuric Acid reacts w a base containing a G1 metal base, Na2SO4 is produced
↳ where the metal doubles, the 2 goes after the metal
Percentage composition of element X
Total mass of element in compound / total mass of compound x 100
% comp of X = Ar/Mr x100
n of a Gas
n = v/Mr
moles = volume (dm3) [given volume] / molar gas volume (dm3) [according to PT]
At constant temp & pressure
1 mol of any gas occupies the same volume
RTP
Room Temp & Pressure
24 mol dm3
- 293K
- 101KPa
STP
Standard Temp & Pressure
22.4 mol dm3
- 293K
- 101KPa