Allosteric enzymes & Inhibitors Flashcards
what is an inhibitor?
Any molecule that acts to reduce the rate of an enzymatic reaction
act in different ways
small chemicals or larger polymers
drugs tend to be inhibitors of enzymatic reactions
what is a competitive inhibitor?
mimic the substrate to bind to the active site
can greatly increase the Km of the enzyme
How does competitive inhibition work?
differs from the substrate so cannot act in the sam way the substrate does
no reaction - EI complex just sits there
what is the dissociation constant?
Ki
units are in molar
can find the strength of the bonds between enzyme and inhibtor
Ki
[E]x[I] / [EI]
assumed that inhibitor I binds reversibly to the enzyme and is in rapid equilibrium with it
competitive inhibitor reduces the concentration of the free enzyme available for substrate binding
what is the effect on the michaeles-menten reaction in the presence of a competitive inhibitor?
[S] approaches infinity
v approaches Vmax
infinitely high [S] can overcome effects of competitive inhibitor
presence of I makes Km appear larger, binding of I and S to E are mutually exclusive
Curve shifts to the R
curve will eventually reach Vmax, have to add more substrate to outcompete inhibitor
Michaelis menten equation modified by a
v = Vmax [S] / aKm + [S]
Main effect is the introduction of a which is a change in Km
Ki measured
v = Vmax / aKm =[S] —> 1/v —> 1/[S] = 1/Vmax
What is uncompetitive inhibition?
inhibitor that binds to the enzyme-substrate complex but not directly to the free enzyme
doesn’t affect the catalytic function of the enzyme but not its substrate binding
what is Kis?
[ES] [I] / [ESI]
A dissociation constant
has units of M
enzyme-substrate-inhibitor complex is catalytically active
Kis measured
v = Vmax [S] / Km + a[S] —> 1/v —> 1/ [s] + a / Vmax
Both Km and Vmax are decreased
ratio Vmax / Km remains unchanged
effects of uncompetitive inhibition on Vmax are not reversed by increasing the substrate concentration
what is mixed inhibition?
binds to enzyme sites that participate in both substrate binding and catalysis
mixed inhibition measuring?
v = Vmax[s] / aKm + a’[s] —> 1/v —> 1/[s] + a’/Vmax
Special case pf non-competitive inhibition
Ki = Kis and a = a’
shows decrease in Vmax (reciprocal value) but Km remains constant
What is irreversible inactivation?
inhibitor binds irreversibly to an enzyme inhibitor is an inactivator
reduce effective level of [e]t and Vmax at all values of [s], not changing Km
double reciprocal lots similar to non-competitive inhibition