5 - centres of mass 1 Flashcards
centre of mass of two identical particles
midpoint of the straight line between them
if the masses of particles are different you find the CoM by
caclulating a weighted average
x = m1x1+m2x2… /m1+m2
fromula to find centre of mass of particles
Mx = m1x1+m2x2…+ mnxn
where M = m1+m2…+mn
CoM of particles arranged in a plane
M(x,y) = m1(x1,y1) + m2(x2,y2)… mn(xn, yn)
CoM of a uniform rod
midpoint
CoM of a uniform lamina
lies on any axis of symmetry
if there are multiple then it lies at the intersection of these
lamina
2D object
assume the lamina has zero thickness
uniform = constant mass per unit area
CoM of a uniform triangular lamina
add up coordinates of the corners and average
x = x1+x2+x3 /3
y = y1+y2+y3 /3
CoM of the sector of a circle
2rsin⍺/3⍺
where 2⍺ is the angle of the sector in radians
CoM of a uniform wire bent to form an arc
rsin⍺/⍺
where 2⍺ is the angle of the sector in radians
CoM of composite bodies
table of shape, length/ vol/ area and CoM
then use the formula