3.10 Aromatic Flashcards

1
Q

What is the molecular formula of benzene?

A

C6H6

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2
Q

Describe Kekule’s structure of benzene

A

An organic cyclohexene, with alternating double and single bonds.
Ie Cyclohex-1,3,5-diene

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3
Q

Describe Lonsdale’s structure of benzene

A

A cyclohexane with a delocalised electron ring

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4
Q

What evidence is there for Lonsdale’s structure over Kekule’s structure of benzene?

A

The hydrogenation of benzene has a lower enthalpy change than the hydrogenation of cyclohex-1,3,5-triene, showing us that the structure of benzene is more stable than the kekule structure.

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5
Q

Describe some of the properties of benzene

A
  • Carbon-carbon bonds are all the same length, and are between single and double bonds in length.
  • Benzene does not undergo addition reactions readily
  • enthalpy change of hydrogenation of benzene is about 152Kjmol-1 less than expected
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6
Q

How do you source NO2+ ions?

A

A mixture of nitric acid and sulfuric acid
HNO3 + H2SO4 -> H2NO3+ +HSO4-

H2NO3+ + H2SO4 -> HSO4- + NO2+ + H2O

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7
Q

Describe the mechanism Electrophilic substitution (Nitration) of benzene

A

1) An arrow is drawn from the delocalised electron ring to the NO2+ ion, forming a positive intermediate, with a +horseshoe ring (this must be opposite the new bond formed). You must draw the C-H and C-NO2 bonds.
2) An arrow is drawn from the C-H bond to the horseshoe electron structure
3) Nitrobenzene + a proton is formed

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8
Q

Describe the mechanism Electrophilic Substitution (Friedel Crafts acylation) of benzene

A

1) An arrow is drawn from the delocalised electron ring to the C+OCH3 (Acylium) ion, forming a positive intermediate, with a +horseshoe ring (this must be opposite the new bond formed). You must draw the C-H and C-C+OCH3 bonds.
2) An arrow is drawn from the C-H bond to the horseshoe electron structure
3) An aromatic ketone + a proton is formed

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9
Q

How are Acylium ions sourced for friedel crafts acylation?

A

By reacting an acyl chloride with AlCl3 to for, an Acylium ion + AlCl4-

CH3COCl + AlCl3 -> CH3CO + AlCl4-

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