17: Equations Flashcards

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1
Q

Millikan’s oil drop experiment:

Force exerted on a current carrying wire in a magnetic field

A
F = BIl
B = magnetic flux density
I = current
l = length (m)
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2
Q

equation for current linking velocity of the charge going through the wire

A

I (current) = qv/l
v = velocity of charged particle
q = charge
l = length

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3
Q

equation for kinetic energy gained by electron between cathode and anode as part of electron deflection

A

1/2 m v^2 = eV

eV = electronvolts

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4
Q

force due to magnetic field acting on a single charged particle moving through a magnetic field

A
F = qvB
F = force in newtons
q = charge in coulombs
v = velocity in ms^-1
B = magnetic field strength in teslas
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5
Q

radius of circular path for deflected charged particle

A
r = mv / qB
r = radius in metres
m = mass in kg
v = velocity in ms^-1
q = charge in coulombs
B = magnetic field strength in Teslas
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6
Q

velocity of charged particle with magnetic force and centripetal motion

A
qvb = mv^2 / r
qb = mv / r
v = qbr / m
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7
Q

what is the equation to calculate the charge on an oil drop in Millikan’s experiment

A
q = mgd  /  v
q = charge
m = mass in kg
d is distance between plates in metres
v = voltage
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8
Q

what are the 2 equations that are equal when an oil drop is suspended between 2 charged plates

A
F = qE,  w = mg,
qE = mg
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9
Q

what does the equation for electric potential V V = kQ / r, a charged sphere give

A

V = kQ / r, where r is radial distance from the centre of the charge, which could go on to infinity
gives the work done to bring a unit positive charge from infinity to a given point in an electric field

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10
Q

how to find out electric field strength for electron moving in a straight line through a magnetic field

A
if its moving in a straight line then force due to electric field must be equal to the force due to magnetic field
so 
Felectric = Eelectric * q
F = QvB
QVB = EQ
so E = VB
V = velocity
B = magnetic field strength
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