081.08 FLIGHT MECHANICS Flashcards
The flight-path angle is defined as the angle between an aeroplane’s (…) and (…).
The flight-path angle is defined as the angle between an aeroplane’s (speed vector) and (horizontal plane).
Turning motion in a steady, level coordinated turn is created by (thrust/drag/centripetal force/centrifugal force).
Turning motion in a steady, level coordinated turn is created by (centripetal force).
In a climb, weight can be resloved into two components. One that opposes lift and one that opposes (…).
In a climb, weight can be resloved into two components. One that opposes lift and one that opposes (thrust).
In a straight, steady descent, thrust is equal to (…).
In a straight, steady descent, thrust is equal to (D - W • sin γ).
In a straight, steady descent, lift is equal to (…).
In a straight, steady descent, lift is equal to (W • cos γ).
In a straight, steady climb, lift is equal to (…).
In a straight, steady climb, lift is equal to (W • cos γ).
In a straight, steady climb, thrust is equal to (…).
In a straight, steady climb, thrust is equal to (D + W • sin γ).
Define ‘VMCG‘.
Minimum control speed with critical engine inoperative on the ground.
Define ‘VMCA‘.
Minimum control speed with critical engine inoperative in take-off configuration.
Define ‘VMCL‘.
Minimum control speed with critical engine inoperative during approach and landing.
Define ‘VMC‘.
Minimum control speed with critical engine inoperative
VMCA is the minimum control speed where it is possible to maintain control and straight flight using no more than (…)° of bank withouth exceptional piloting skill or the aeroplane adopting a dangerous attitude or changing heading by more than (…)°.
VMCA is the minimum control speed where it is possible to maintain control and straight flight using no more than (5)° of bank withouth exceptional piloting skill or the aeroplane adopting a dangerous attitude or changing heading by more than (20)°.
For VMCG determination, the CG shoudl be on the (forward/aft) limit.
For VMCG determination, the CG shoudl be on the (aft) limit.
- largest arm -
As the bank angle is decreased from 5° to 0°, the value of VMCA<strong> </strong>(increases/decreases).
As the bank angle is decreased from 5° to 0°, the value of VMCA<strong> </strong>(increases).
- because at lower bank, more rudder deflection is necessary with OEI -
When VMCL is defined, the aeroplane is trimmed for (take-off/approach) with (all engines operating/one engine inoperative).
When VMCL is defined, the aeroplane is trimmed for (approach) with (all engines operating).
During VMCG determination, the lateral deviation from the runway centerline may not be more than (half the distance between runway centreline and runway edge/50 ft/30 ft).
During VMCG determination, the lateral deviation from the runway centerline may not be more than (30 ft).
The point on the diagram corresponding to the minimum value of the drag coefficient is point (1/2/3/4).
The point on the diagram corresponding to the minimum value of the drag coefficient is point (1).
The point on the diagram corresponding to CL for minimum horizontal flight speed is point (1/2/3/4).
The point on the diagram corresponding to CL for minimum horizontal flight speed is point (4).
The point on the diagram corresponding to the minimum value of drag is point (1/2/3/4).
The point on the diagram corresponding to the minimum value of drag is point (2).
- (CL/CD)max = VMD = minimum glide angle -
The point on the diagram corresponding to the value for minimum sink rate is point (1/2/3/4).
The point on the diagram corresponding to the value for minimum sink rate is point (3).
- (CL3/CD2)max = VMP -
Arrange the following point on a jet’s polar curve in order of increasing AoA:
- CLmax
- Long range cruise (zero wind)
- (L/D)max
- Minimum rate of descent (assume zero thrust)
- Maximum range cruise (zero wind)
Increasing AoA = decreasing speed
- Long range cruise (4% faster than maximum range cruise )
- Maximum range cruise (1.32 • VMD = VY)
- (L/D)max (= VMD = VX)
- Minimum rate of descent
- CLmax (stall speed)